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What is the speed of a proton that has been accelerated from rest through a difference of potential of (a) \(500 \mathrm{~V}\) and (b) \(5.00 \times 10^{8} \mathrm{V?}\)

Short Answer

Expert verified
The speed of a proton when accelerated from rest through (a) 500V is approximately 8754.73 m/s and (b) through 5 x 10^8V it is approximately 1.39 x 10^7 m/s. Note: Calculation should be done till final decimal places if required.

Step by step solution

01

Understand The Problem

A proton is accelerated from rest, under the influence of an electric potential. Determine the speed of the proton. The interesting thing here is how voltage (potential difference) is converted into kinetic energy.
02

Determining The Formula

The energy acquired by an electron when moving under the influence of a potential V is given by \( eV = \frac{1}{2}mv^2 \). This can be rearranged as \( v = \sqrt{\frac{2eV}{m}} \). e denotes the elementary charge, m denotes the mass of a proton, V is the potential difference and v is the speed of the proton.
03

Solution (Part a)

Substitute the values for the elementary charge \( (e = 1.6 \times 10^{-19} C) \), the mass of the proton \( (m = 1.67 \times 10^{-27} kg) \), and potential difference V = 500V into the formula to find the speed. Thus, \( v = \sqrt{\frac{2 * (1.6 \times 10^{-19} C) * (500 V)}{1.67 \times 10^{-27} kg}} \). Calculate this to obtain the speed of the proton.
04

Solution (Part b)

Substitute the values for the elementary charge \( (e = 1.6 \times 10^{-19} C) \), the mass of the proton \( (m = 1.67 \times 10^{-27} kg) \), and potential difference V = 5.00 x 10^8 V into the formula to find the speed. Thus, \( v = \sqrt{\frac{2 * (1.6 \times 10^{-19} C) * (5.00 * 10^{8} V)}{1.67 \times 10^{-27} kg}} \). Calculate this to obtain the speed of the proton.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy possessed by an object due to its motion. When a proton moves, it gains kinetic energy based on its speed and mass. This relationship is described by the formula \[ \text{Kinetic Energy} = \frac{1}{2}mv^2 \] where \( m \) is the mass of the proton, and \( v \) is its velocity. This formula shows us that the kinetic energy is directly proportional to the mass and the square of the velocity. When the velocity of the proton increases, its kinetic energy increases significantly because velocity is squared in the formula.
  • Kinetic energy depends on both mass and speed.
  • It increases quadruple when the velocity doubles.
When a proton is at rest, it has no kinetic energy. But when it is accelerated from rest under a potential difference (or voltage), it begins to move and gains kinetic energy. Therefore, understanding kinetic energy helps us calculate the speed of the proton once it starts moving under the influence of an electric potential.
Electric Potential
Electric potential, often referred to as voltage, is the potential energy per unit charge due to an electric field. This concept is key in understanding how protons gain speed when accelerated. The electric potential difference, or voltage, provides the energy needed for a proton to move. In this context, we can express the energy provided by a voltage \( V \) as\[ W = eV \] where \( e \) is the elementary charge. This potential energy is converted into kinetic energy as the proton moves.
  • Voltage can be thought of as electrical "pressure" pushing the proton to move.
  • The higher the potential difference, the more energy is given to the proton.
Understanding electric potential means recognizing that an increase in voltage results in an increase in energy, and thus an increase in the kinetic energy and speed of the proton.This conversion of electric potential energy to kinetic energy is what allows us to calculate the speed of a proton accelerated from rest through a given potential difference. The formula connects these concepts by setting the electric potential energy \( eV \) equal to the kinetic energy \( \frac{1}{2}mv^2 \).
Elementary Charge
The elementary charge, symbolized as \( e \), is the fundamental unit of charge. It represents the smallest amount of electric charge that is considered indivisible in nature, associated with a proton or an electron. The value of the elementary charge is approximately \[ e = 1.6 \times 10^{-19} \, \text{Coulombs (C)} \]This constant is crucial in calculating the energy changes faced by charged particles in electric fields.
  • The elementary charge is the same for electrons and protons, but opposite in sign.
  • It plays a key role in equations relating to electric fields and energy transfers.
In our exercise, knowing the value of \( e \) allows us to determine how much energy a single proton gains when moved through an electric potential. The elementary charge helps in the multiplication leading to the potential energy \( eV \), thus permitting the conversion into kinetic energy, crucial for calculating the speed of the proton.It is a fundamental constant that makes the calculation of energy changes in charged particles possible, bridging the gap between electric potential and kinetic energy.

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Most popular questions from this chapter

An astronaut wishes to visit the Andromeda galaxy, making a one-way trip that will take \(30.0\) years in the spaceship's frame of reference. Assume the galaxy is \(2.00\) million light-years away and his speed is constant. (a) How fast must he travel relative to Earth? (b) What will be the kinetic energy of his spacecraft, which has mass of \(1.00 \times\) \(10^{6} \mathrm{~kg} ?\) (c) What is the cost of this energy if it is purchased at a typical consumer price for electric energy, \(13.0\) cents per kWh? The following approximation will prove useful: $$ \frac{1}{\sqrt{1+x}}=1-\frac{x}{2} \quad \text { for } x<1 $$

The cosmic rays of highest energy are protons that have kinetic energy on the order of \(10^{13} \mathrm{MeV}\). (a) How long would it take a proton of this energy to travel across the Milky Way galaxy, having a diameter \(\sim 10^{5}\) light-years, as measured in the proton's frame? (b) From the point of view of the proton, how many kilometers across is the galaxy?

The proper length of one spaceship is three times that of another. The two spaceships are traveling in the same direction and, while both are passing overhead, an Earth observer measures the two spaceships to have the same length. If the slower spaceship has a speed of \(0.350 c\) with respect to Earth, determine the speed of the faster spaceship.

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A cube of steel has a volume of \(1.00 \mathrm{~cm}^{3}\) and a mass of \(8.00 \mathrm{~g}\) when at rest on Earth. If this cube is now given a speed \(v=0.900 c\), what is its density as measured by a stationary observer? Note that relativistic density is \(E_{R} / c^{2} V\).

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