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A ball is thrown upward from the ground with an initial speed of \(25 \mathrm{~m} / \mathrm{s}\); at the same instant, another ball is dropped from a building \(15 \mathrm{~m}\) high. After how long will the balls be at the same height?

Short Answer

Expert verified
The balls will be at the same height after 0.6 seconds.

Step by step solution

01

Define the Variables and Equations

Let's denote the height of the first ball (thrown upward) as \(h1\) and the height of the second ball (dropped from a building) as \(h2\). For the first ball, we have \(h1 = h_{0,1} + v_{0,1} * t - 0.5 * g * t^2\), where \(h_{0,1}\) is the initial height, \(v_{0,1}\) is the initial velocity and \(g\) is the gravitational acceleration. For the second ball, we have \(h2 = h_{0,2} - 0.5 * g * t^2\), where \(h_{0,2}\) is the initial height of the second ball. The task is to find the time \(t\) when \(h1 = h2\).
02

Substituting Given Values

Plug the values into the respective equations: for the first ball, \(h_{0,1} = 0 m\), \(v_{0,1} = 25 m/s\), \(g = 9.81 m/s^2\); for the second ball, \(h_{0,2} = 15 m\), \(g = 9.81 m/s^2\). This gives us two equations: \(h1 = 0 m + 25 m/s * t - 0.5 * 9.81 m/s^2 * t^2\) and \(h2 = 15 m - 0.5 * 9.81 m/s^2 * t^2\).
03

Solve The Equations

Setting the equations \(h1\) and \(h2\) equal to each other gives: \(0 m + 25 m/s * t - 0.5 * 9.81 m/s^2 * t^2 = 15 m - 0.5 * 9.81 m/s^2 * t^2\). After simplifying, we get the equation \(25 m/s * t - 15 m = 0\) from which we solve for \(t\) to get \(t = 15 m / (25 m/s) = 0.6 s\). This is the time when the balls will be at the same height.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is a branch of physics that studies the motion of objects without considering the forces that cause this motion. In the problem discussed, kinematics helps to analyze the motion of the two balls. One ball is thrown upwards, and another is dropped downwards. By understanding kinematics, we can predict and calculate how each ball moves over time. This involves using parameters such as initial velocity, height, time, and acceleration.

The motion of the balls is described using kinematic equations, which include initial velocities and gravitational effects. For example:
  • Initial speed: It determines how fast an object starts moving.
  • Acceleration: Here, it is due to gravity, which constantly affects the speed.
  • Time: The variable that indicates how long the ball has been moving.
In this situation, both balls follow a parabolic path because of the uniform gravitational pull acting on them, exemplifying typical kinematic motion.
Gravitational Acceleration
Gravitational acceleration is the rate at which an object increases its velocity as it falls towards the Earth due to gravity. It is denoted by the symbol \( g \) and is approximately \( 9.81 \ m/s^2 \) near the Earth's surface.

This concept is crucial in projectile motion as it influences how quickly objects fall and how trajectories are shaped. The ball thrown upward in the problem decelerates until it stops momentarily at its peak height, then accelerates downwards due to gravity. Meanwhile, the other ball, dropped from a height, accelerates from the start.

Understanding gravitational acceleration allows us to:
  • Predict the motion of falling objects
  • Calculate key values like time of flight
  • Determine maximum height reached
Hence, gravity not only affects how fast an object falls but also the entire trajectory and time of motion in projectile scenarios.
Equations of Motion
In the context of projectile motion, equations of motion are mathematical expressions that describe the movement of objects under specific conditions like initial velocity and acceleration.

The three standard kinematic equations in physics often involve parameters like displacement (\( h \)), initial velocity (\( v_0 \)), time (\( t \)), and acceleration due to gravity (\( g \)). Each equation correlates with different terms to provide insight into different motion aspects:
  • Displacement equation: \( h = h_0 + v_0 \cdot t - 0.5 \cdot g \cdot t^2 \)
  • Velocity equation: \( v = v_0 + g \cdot t \)
  • Acceleration consideration
For the exercise, these equations help us express the relation between the two balls' positions over time and solve for when their heights equal. Subsequently, setting up and rearranging these equations enables solving for time when both balls meet at the same height.

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Most popular questions from this chapter

Two students are on a balcony a distance \(h\) above the street. One student throws a ball vertically downward at a speed \(v_{0}\); at the same time, the other student throws a ball vertically upward at the same speed. Answer the following symbolically in terms of \(v_{0}, g_{1} h\), and \(\ell\). (a) Write the kinematic equation for the \(y\) -coordinate of each ball. (b) Set the equations found in part (a) equal to height 0 and solve each for \(t\) symbolically using the quadratic formula. What is the difference in the two balls' time in the air? (c) Use the time-independent kinematics equation to find the velocity of each ball as it strikes the ground. (d) How far apart are the balls at a time \(t\) after they are released and before they strike the ground?

In a test run, a certain car accelerates uniformly from zero to \(24.0 \mathrm{~m} / \mathrm{s}\) in \(2.95 \mathrm{~s}\). (a) What is the magnitude of the car's acceleration? (b) How long does it take the car to change its speed from \(10.0 \mathrm{~m} / \mathrm{s}\) to \(20.0 \mathrm{~m} / \mathrm{s} ?\) (c) Will doubling the time always double the change in speed? Why?

An athlete swims the length \(L\) of a pool in a time \(t_{1}\) and makes the return trip to the starting position in a time \(t_{2} .\) If she is swimming initially in the positive \(x\) direction, determine her average velocities symbolically in (a) the first half of the swim, (b) the second half of the swim, and (c) the round trip. (d) What is her average speed for the round trip?

A steam catapult launches a jet aircraft from the aircraft carrier John C. Stenmis, giving it a speed of \(175 \mathrm{mi} / \mathrm{h}\) in \(2.50 \mathrm{~s}\). (a) Find the average acceleration of the plane. (b) Assuming the acceleration is constant, find the distance the plane moves.

A speedboat increases its speed uniformly from \(v_{t}=\) \(20.0 \mathrm{~m} / \mathrm{s}\) to \(v_{j}=30.0 \mathrm{~m} / \mathrm{s}\) in a distance of \(2.00 \times 10^{2} \mathrm{~m}\) (a) Draw a coordinate system for this situation and label the relevant quantities, including vectors. (b) For the given information, what single equation is most appropriate for finding the acceleration? (c) Solve the equation selected in part (b) symbolically for the boat's acceleration in terms of \(v_{f}, v_{a}\), and \(\Delta x\). (d) Substitute given values, obtaining that acceleration. (e) Find the time it takes the boat to travel the given distance.

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