/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 An ideal gas in a cylinder is co... [FREE SOLUTION] | 91Ó°ÊÓ

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An ideal gas in a cylinder is compressed very slowly to one-third its original volume while its temperature is held constant. The work required to accomplish this task is \(75 \mathrm{~J}\). (a) What is the change in the internal energy of the gas? (b) How much energy is transferred to the gas by heat in this process?

Short Answer

Expert verified
The change in internal energy is 0J and the energy transferred to the gas by heat is 75J.

Step by step solution

01

Calculation of change in internal energy

As the gas is held at constant temperature, the change in internal energy (∆U) of the system is 0. This is because the internal energy of an ideal gas is a function of temperature. So, ∆U = 0J
02

Calculation of heat transferred

The first law of thermodynamics is represented by \(Q = W + ∆U\). Substituting the given values (W=-75J and ∆U=0J) into the equation, we get \(Q = -75J + 0 = -75J\). However, because the heat is transferred to the system, the sign of Q turns positive. Thus, Q = 75J.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

First Law of Thermodynamics
The First Law of Thermodynamics is a fundamental concept in physics that relates to the energy changes within a system. It is often phrased as "energy cannot be created or destroyed; it can only be transformed from one form to another." This principle applies to ideal gas processes and many other thermodynamic scenarios. The law can be mathematically expressed as:
  • \( \Delta U = Q - W \)
where:
  • \( \Delta U \) is the change in internal energy of the system,
  • \( Q \) is the heat added to the system,
  • \( W \) is the work done by the system (positive if work is done by the system and negative if work is done on the system).

Understanding this equation helps us analyze energy transactions in various processes.
In the context of an isothermal process, as described in the exercise, the internal energy remains constant, simplifying calculations.
Internal Energy
Internal energy refers to the total energy contained within a system, such as an ideal gas, due to both its kinetic and potential energies. For ideal gases, internal energy is directly related to temperature, which is crucial for understanding reactions and processes involving gases.
In the given exercise, the temperature is held constant during compression, indicating no change in internal energy. Thus, the \( \Delta U = 0 \text{ J} \).
This is because, in an ideal gas, if there is no change in temperature between states, the kinetic energy of gas molecules remains constant, resulting in unchanged internal energy. This simplifies analysis when applying the First Law of Thermodynamics.
Heat Transfer
Heat transfer is the process by which thermal energy reaches or exits a system, influencing its internal energy but often through different pathways than mechanical work. The first law helps in determining the heat exchanged with the environment by accounting for changes in internal energy and work done by or on the system.
Using the exercise, since the internal energy change \( \Delta U = 0 \text{ J} \), the heat transferred can be directly equated to the work done on the system, resulting in
  • \( Q = 75 \text{ J} \)
This positive value of \( Q \) indicates that heat energy was absorbed by the gas. Understanding heat balance is essential in practical applications like engines and HVAC systems.
Isothermal Process
An isothermal process occurs when a system undergoes changes at a constant temperature, which is a common scenario in ideal gases. This type of process is significant because it features simple characteristics:
  • No change in internal energy (\( \Delta U = 0 \)), since temperature directly determines the internal energy of ideal gases.
  • Work done and heat transfer are equal in magnitude, because all the work done results in heat added to or eliminated from the system.

Isothermal processes are often reversible and can be represented graphically by a hyperbolic curve on a PV (Pressure-Volume) graph.
In the exercise, the gas being compressed to one-third its original volume and the calculation of work at constant temperature illustrate the application of this concept, leading to straightforward equations for energy calculations.

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Most popular questions from this chapter

One mole of an ideal gas initially at a temperature of \(T_{i}=0^{\circ}\) C undergoes an expansion at a constant pressure of \(1.00 \mathrm{~atm}\) to four times its original volume. (a) Calculate the new temperature \(T_{f}\) of the gas. (b) Calculate the work done on the gas during the expansion.

Hydrothermal vents deep on the ocean floor spout water at temperatures as high as \(570^{\circ} \mathrm{C}\). This temperature is below the boiling point of water because of the immense pressure at that depth. Because the surrounding ocean temperature is at \(4.0^{\circ} \mathrm{C}\), an organism could use the temperature gradient as a source of energy. (a) Assuming the specific heat of water under these conditions is \(1.0 \mathrm{cal} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\), how much energy is released when \(1.0\) liter of water is cooled from \(570^{\circ} \mathrm{C}\) to \(4.0^{\circ} \mathrm{C}\) ? (b) What is the maximum usable energy an organism can extract from this energy source? (Assume the organism has some internal type of heat engine acting between the two temperature extremes.) (c) Water from these vents contains hydrogen sulfide \(\left(\mathrm{H}_{2} \mathrm{~S}\right)\) at a concentration of \(0.90 \mathrm{mmole} / \mathrm{liter}\). Oxidation of \(1.0\) mole of \(\mathrm{H}_{2} \mathrm{~S}\) produces \(310 \mathrm{~kJ}\) of energy. How much energy is available through \(\mathrm{H}_{2} \mathrm{~S}\) oxidation of \(1.0 \mathrm{~L}\) of water?

If you roll a pair of dice, what is the total number of ways in which you can obtain (a) a 12? (b) a 7?

A cylinder of volume \(0.300 \mathrm{~m}^{3}\) contains \(10.0 \mathrm{~mol}\) of neon gas at \(20.0^{\circ} \mathrm{C}\). Assume neon behaves as an ideal gas. (a) What is the pressure of the gas? (b) Find the internal energy of the gas. (c) Suppose the gas expands at constant pressure to a volume of \(1.000 \mathrm{~m}^{3} .\) How much work is done on the gas? (d) What is the temperature of the gas at the new volume? (c) Find the internal energy of the gas when its volume is \(1.000 \mathrm{~m}^{3}\). (f) Compute the change in the internal energy during the expansion. (g) Compute \(\Delta U-W\) (h) Must thermal energy be transferred to the gas during the constant pressure expansion or be Laken away? (i) Compute \(Q\), the thermal energy transfer. (j) What symbolic relationship between \(Q, \Delta U\), and \(W\) is suggested by the values obtained?

A 70 -kg log falls from a height of \(25 \mathrm{~m}\) into a lake. If the log, the lake, and the air are all at \(300 \mathrm{~K}\), find the change in entropy of the Universe during this process.

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