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A gas is at \(0^{\circ} \mathrm{C}\) . If we wish to double the rms speed of its molecules, to what temperature must the gas be brought?

Short Answer

Expert verified
The temperature must be brought to 1092 K to double the rms speed of the molecules.

Step by step solution

01

Understanding the Relationship Between rms Speed and Temperature

The root mean square (rms) speed of the molecules in a gas is related to the temperature of the gas by the formula \( v_{rms} = \sqrt{\frac{3kT}{m}} \), where \( v_{rms} \) is the rms speed, \( k \) is the Boltzmann constant, \( T \) is the temperature in Kelvin, and \( m \) is the mass of a gas molecule. To double the rms speed, \( v_{rms}' = 2v_{rms} \), we need to find the new temperature \( T' \).
02

Setting Up the Equation for the New Temperature

We have the equation \( 2v_{rms} = \sqrt{\frac{3kT'}{m}} \), and using the initial condition \( v_{rms} = \sqrt{\frac{3kT}{m}} \), where \( T \) is the initial temperature in Kelvin. Squaring both sides of the new equation gives us \( 4v_{rms}^2 = \frac{3kT'}{m} \).
03

Calculating the New Temperature

Substituting the initial condition into the squared equation, we get \( 4 \cdot (\frac{3kT}{m}) = \frac{3kT'}{m} \). This simplifies to \( 4T = T' \). Since the initial temperature is \( T = 273 \text{ K} \) (equivalent to \( 0^\circ \text{C} \)), we can calculate the new temperature needed to double the rms speed as \( T' = 4 \cdot 273 \text{ K} = 1092 \text{ K} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Root Mean Square Speed
The term 'root mean square speed' (rms speed) refers to a statistical measure of the speed of particles in a gas that is crucial for understanding gas molecule kinetics. It represents the square root of the average of the squares of the individual speeds of the gas molecules. The importance of this measure lies in its relationship with the temperature of the gas.

According to the kinetic theory of gases, as temperature increases, so does the average energy of the gas molecules. This is captured by the rms speed formula:

\[\begin{equation} v_{rms} = \/ \sqrt{\frac{3kT}{m}}\end{equation}\]
In this formula, the rms speed (\[\begin{equation} v_{rms}\end{equation}\]) is proportional to the square root of temperature (\[\begin{equation} T\end{equation}\]), meaning that if you want to double the rms speed, you'll need to increase the temperature by a factor of four, as squared dependencies necessitate. This is critical for scientists and engineers who work on processes involving temperature and gas behavior.
Gas Molecules Kinetics
When we delve into gas molecules kinetics, we're exploring how these tiny particles move and interact with each other. The kinetic theory regarding gases provides insights into the physical properties of gases, including pressure, temperature, and volume. It's based on the premise that gas molecules are in constant, random motion and that they collide with each other and the walls of their container.

As temperature is a measure of the average kinetic energy of the particles in a substance, an increase in temperature will lead to an increase in kinetic energy and hence an increase in the speed of the gas molecules. The rms speed serves as a practical measure of this molecular speed. Understanding the movement of these molecules is fundamental for diverse applications, from predicting the behavior of an ideal gas in a sealed container to more complex systems like weather patterns or the design of combustion engines.
Boltzmann Constant
The Boltzmann constant (\[\begin{equation} k\end{equation}\]) is a fundamental physical constant that links the average kinetic energy of particles in a gas with the temperature of the gas. This constant is named after the Austrian physicist Ludwig Boltzmann, and it plays a pivotal role in statistical mechanics and thermodynamics.

With a value of approximately \[\begin{equation} 1.38 \times 10^{-23}\end{equation}\] joules per Kelvin, the Boltzmann constant serves as a bridge between macroscopic and microscopic physics. It enables us to translate between the energy scales of individual atoms and molecules (\[\begin{equation} kT\end{equation}\]) and the temperature scale that emerges from the collective behavior of a vast assembly of particles. With this understanding, students can appreciate that the behavior of vast numbers of tiny particles can be described by a few macroscopic variables like temperature, and these can be related back to the properties of individual molecules via constants like Boltzmann's.

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Most popular questions from this chapter

A certain molecule has \(f\) degrees of freedom. Show that an ideal gas consisting of such molecules has the following properties: \((1)\) its total internal energy is \(f n R T / 2 ;(2)\) its molar specific heat at constant volume is \(f R / 2 ;\) (3) its molar specific heat at constant pressure is \((f+2) R / 2 ;\) (4) its specific heat ratio is \(\gamma=C_{P} / C_{V}=(f+2) / f\)

In a constant-volume process, 209 \(\mathrm{J}\) of energy is transferred by heat to 1.00 mol of an ideal monatomic gas initially at 300 \(\mathrm{K}\) . Find (a) the increase in internal energy of the gas, (b) the work done on it, and (c) its final temperature.

During the compression stroke of a certain gasoline engine, the pressure increases from 1.00 atm to 20.0 atm. If the process is adiabatic and the fuel- air mixture behaves as a diatomic ideal gas, (a) by what factor does the volume change and \((b)\) by what factor does the temperature change? (c) Assuming that the compression starts with 0.0160 mol of gas at \(27.0^{\circ} \mathrm{C},\) find the values of \(Q, W,\) and \(\Delta E_{\text { int that characterize the process. }}\)

Consider 2.00 mol of an ideal diatomic gas. (a) Find the total heat capacity of the gas at constant volume and at constant pressure assuming the molecules rotate but do not vibrate. (b) What If? Repeat, assuming the molecules both rotate and vibrate.

Twenty particles, each of mass \(m\) and confined to a volume \(V,\) have various speeds: two have speed \(v ;\) three have speed \(2 v ;\) five have speed \(3 v ;\) four have speed \(4 v ;\) three have speed 5v; two have speed \(6 v ;\) one has speed 7\(v\) . Find (a) the average speed, (b) the rms speed, (c) the most probable speed, (d) the pressure the particles exert on the walls of the vessel, and (e) the average kinetic energy per particle.

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