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Helium gas is in thermal equilibrium with liquid helium at 4.20 \(\mathrm{K}\) . Even though it is on the point of condensation, model the gas as ideal and determine the most probable speed of a helium atom (mass \(=6.64 \times 10^{-27} \mathrm{kg} )\) in it.

Short Answer

Expert verified
The most probable speed of a helium atom at 4.20 K is approximately 53.8 m/s.

Step by step solution

01

Understanding the Most Probable Speed

The most probable speed, denoted by \(v_p\), in an ideal gas is the speed at which the largest number of gas particles are moving. It is derived from the Maxwell-Boltzmann distribution and can be calculated using the formula \(v_p = \sqrt{\frac{2k_BT}{m}}\), where \(k_B\) is the Boltzmann constant \(\left(1.38 \times 10^{-23} \,\mathrm{J/K}\right)\), \(T\) is the temperature in kelvin, and \(m\) is the mass of one atom or molecule of the gas.
02

Plugging in the Values

To calculate the most probable speed of a helium atom at \(4.20 \,\mathrm{K}\), we plug in the values for the Boltzmann constant \(k_B\), the temperature \(T\), and the mass \(m\) of a helium atom into the formula for \(v_p\). This gives us \(v_p = \sqrt{\frac{2 \times 1.38 \times 10^{-23} \,\mathrm{J/K} \times 4.20 \,\mathrm{K}}{6.64 \times 10^{-27} \,\mathrm{kg}}}\).
03

Calculating the Most Probable Speed

By calculating the expression under the square root, multiplying \(2\) by \(1.38 \times 10^{-23}\) by \(4.20\), dividing by \(6.64 \times 10^{-27}\), and then taking the square root, we find the most probable speed of a helium atom at the given temperature.
04

Finding the Numerical Value

Performing the calculations, we find \(v_p = \sqrt{\frac{2 \times 1.38 \times 10^{-23} \times 4.20}{6.64 \times 10^{-27}}} \approx \sqrt{2.89 \times 10^{3}} \approx 53.8 \,\mathrm{m/s}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Maxwell-Boltzmann Distribution
The Maxwell-Boltzmann distribution is a fundamental concept in statistical mechanics that describes the distribution of speeds among particles in a gas. It tells us that in a sample of gas, particles will have a range of speeds, but certain speeds are more probable than others. This distribution arises from the random motion of particles and a tendency toward achieving equilibrium.

At a given temperature, most particles will have speeds around a certain value, known as the most probable speed. This speed is not the same as the average speed, but rather the peak of the probability curve in the Maxwell-Boltzmann distribution graph. The graph itself is asymmetrical, because while there is a limit to how slow a particle could move (approaching zero speed), there is no strict upper limit to a particle's speed.

The reason why understanding the Maxwell-Boltzmann distribution is important is that it provides insight into the kinetic properties of gases, including diffusion, viscosity, and thermal conductivity. Essentially, it helps us predict how gas molecules will behave under varying conditions of temperature and pressure.
Ideal Gas Law
The ideal gas law is a key principle in thermodynamics that describes the behavior of ideal gases, providing a simple relationship between pressure, volume, temperature, and the number of moles of the gas. Represented by the equation PV = nRT, where
  • P is the pressure of the gas,
  • V is the volume it occupies,
  • n is the number of moles,
  • R is the gas constant (approximately 8.314 J/molâ‹…K),
  • and T is the absolute temperature in kelvin.

This law assumes that the gas particles do not interact with each other and that they occupy no volume themselves, conditions that are approximated under many conditions but can deviate at high pressures or low temperatures.

For real gases, certain corrections must be applied to account for intermolecular forces and the actual volume of the gas particles. Nevertheless, the ideal gas law remains a useful tool in understanding how gases behave when they are close to ideal conditions and when discussing concepts such as the most probable speed, as it assumes the connection between temperature, pressure, and volume can determine the kinetic energy properties of the gas.
Thermal Equilibrium
Thermal equilibrium refers to the state in which two or more objects or systems in thermal contact with each other cease to exchange energy through heat. At this point, they have reached the same temperature and energy flows cease, meaning there is no net change in heat.

In the context of gas particles, when a gas is in thermal equilibrium, as in the helium gas exercise, all parts of the gas sample have reached the same temperature, which is also consistent with the temperature of the environment or any connected systems. A vital consequence of thermal equilibrium is the uniform distribution of speeds among gas particles as described by the Maxwell-Boltzmann distribution. At equilibrium, the most probable speed of particles is entirely dependent on the temperature, meaning that any sample of the gas will feature particles zipping around at this preferred speed.

Understanding thermal equilibrium is not only crucial in determining gas particle behavior but also in the broader context of thermodynamic processes and the study of heat transfer, energy conservation, and entropy.
Boltzmann Constant
The Boltzmann constant (

k_B) is a fundamental physical constant that relates the average kinetic energy of particles in a gas with the temperature of the gas. It forms a crucial bridge between macroscopic and microscopic physics by connecting thermodynamic temperature (a large-scale property) with the kinetic energies of particles (a microscopic property). The value of the Boltzmann constant is approximately

1.38 x 10^-23 J/K.

In the equation used to calculate the most probable speed of helium atoms in the given exercise (

v_p = \(\sqrt{\frac{2k_BT}{m}}\)

), the Boltzmann constant appears in the numerator under the square root. This constant effectively scales the temperature to give us the energy per particle, so it is essential for computations involving a gas's thermal properties. Knowledge of the Boltzmann constant allows us to comprehend and calculate various properties of gases, such as pressure, temperature, and, as seen in the exercise, the most probable speed of gas particles.

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Most popular questions from this chapter

A 1 -L Thermos bottle is full of tea at \(90^{\circ} \mathrm{C}\) . You pour out one cup and immediately screw the stopper back on. Make an order-of-magnitude estimate of the change in temperature of the tea remaining in the flask that results from the admission of air at room temperature. State the quantities you take as data and the values you measure or estimate for them.

A certain molecule has \(f\) degrees of freedom. Show that an ideal gas consisting of such molecules has the following properties: \((1)\) its total internal energy is \(f n R T / 2 ;(2)\) its molar specific heat at constant volume is \(f R / 2 ;\) (3) its molar specific heat at constant pressure is \((f+2) R / 2 ;\) (4) its specific heat ratio is \(\gamma=C_{P} / C_{V}=(f+2) / f\)

A 4.00-L sample of a diatomic ideal gas with specific heat ratio 1.40, confined to a cylinder, is carried through a closed cycle. The gas is initially at 1.00 atm and at 300 K. First, its pressure is tripled under constant volume. Then, it expands adiabatically to its original pressure. Finally, the gas is compressed isobarically to its original volume. (a) Draw a PV diagram of this cycle. (b) Determine the volume of the gas at the end of the adiabatic expansion. (c) Find the temperature of the gas at the start of the adiabatic expansion. (d) Find the temperature at the end of the cycle. (e) What was the net work done on the gas for this cycle?

Given that the rms speed of a helium atom at a certain temperature is 1350 \(\mathrm{m} / \mathrm{s}\) , find by proportion the rms speed of an oxygen \(\left(\mathrm{O}_{2}\right)\) molecule at this temperature. The molar mass of \(\mathrm{O}_{2}\) is 32.0 \(\mathrm{g} / \mathrm{mol}\) , and the molar mass of He is \(4.00 \mathrm{g} / \mathrm{mol} .\)

An incandescent lightbulb contains a volume \(V\) of argon at pressure \(P_{i}\) . The bulb is switched on and constant power \(\mathscr{P}\) is transferred to the argon for a time interval \(\Delta \iota\) . (a) Show that the pressure \(P_{f}\) in the bulb at the end of this process is \(P_{f}=P_{i}\left[1+(\mathscr{P} \Delta t R) /\left(P_{i} V C_{V}\right)\right]\) . (b) Find the pressure in a spherical light bulb 10.0 \(\mathrm{cm}\) in diameter 4.00 \(\mathrm{s}\) after it is switched on, given that it has initial pressure 1.00 \(\mathrm{atm}\) and that 3.60 \(\mathrm{W}\) of power is transferred to the gas.

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