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(II) An internal explosion breaks an object, initially at rest, into two pieces, one of which has 1.5 times the mass of the other. If \(7500 \mathrm{~J}\) is released in the explosion, how much kinetic energy does each piece acquire?

Short Answer

Expert verified
Smaller piece acquires 4500 J, larger 3000 J.

Step by step solution

01

Understand the problem

An object initially at rest explodes into two pieces, and the total energy released is given. One piece is 1.5 times the mass of the other. We need to find the kinetic energy of each piece after the explosion.
02

Define variables

Let the mass of the smaller piece be \(m_1\) and the mass of the larger piece be \(m_2 = 1.5m_1\). The total energy released in the explosion is \(K = 7500\, \text{J}\).
03

Apply conservation of momentum

Since the total momentum before the explosion was zero (the object was initially at rest), the momentum after the explosion must also be zero. This gives us the equation: \(m_1v_1 = m_2v_2\), or \(m_1v_1 = 1.5m_1v_2\).
04

Relate velocities using momentum

From the momentum equation, solve for \(v_1\) in terms of \(v_2\): \(v_1 = 1.5v_2\).
05

Use energy conservation

The total kinetic energy after the explosion is equal to the energy released, so: \(KE_1 + KE_2 = 7500\, \text{J}\), where \(KE_1 = \frac{1}{2}m_1v_1^2\) and \(KE_2 = \frac{1}{2}m_2v_2^2\).
06

Substitute velocities

Substitute \(v_1 = 1.5v_2\) into the expression for \(KE_1\): \(KE_1 = \frac{1}{2}m_1(1.5v_2)^2 = \frac{9}{8}m_1v_2^2\). Also, since \(m_2 = 1.5m_1\), \(KE_2 = \frac{1}{2}(1.5m_1)v_2^2 = \frac{3}{4}m_1v_2^2\).
07

Solve for kinetic energies

Set up the equation: \(\frac{9}{8}m_1v_2^2 + \frac{3}{4}m_1v_2^2 = 7500\). Simplifying, \(\frac{15}{8}m_1v_2^2 = 7500\). Solve for \(m_1v_2^2 = \frac{7500 \times 8}{15} = 4000\). Thus, \(KE_1 = 4500\, \text{J}\) and \(KE_2 = 3000\, \text{J}\).
08

Conclusion

The smaller piece (\(m_1\)) acquires \(4500\, \text{J}\) of kinetic energy, and the larger piece (\(m_2\)) acquires \(3000\, \text{J}\) of kinetic energy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Kinetic Energy
Kinetic energy is the energy an object has due to its motion. Any object that moves possesses kinetic energy. In our problem, an object initially at rest breaks into two pieces due to an internal explosion. This explosion distributes the total energy released as kinetic energy to the two separate pieces. The key formula for kinetic energy (KE) is:
  • \( KE = \frac{1}{2}mv^2 \)
where \(m\) is the mass of the object and \(v\) is its velocity.
This formula tells us that kinetic energy depends on both mass and speed—more mass or greater speed means more kinetic energy.
In our exercise, the total kinetic energy from the explosion is known to be 7500 J. This energy is then split between the two pieces of the object. Given that one piece has 1.5 times the mass of the other, the challenge is to determine how this energy is shared between the two pieces based on their masses and velocities.
Energy Conservation Principles
The principle of energy conservation states that in a closed system, energy cannot be created or destroyed; it only changes form. This is a fundamental concept in physics. In the context of our problem, energy conservation tells us that the total energy before and after the explosion remains consistent.
Before the explosion, the object is at rest, so its kinetic energy is 0. During the explosion, 7500 J of internal energy is converted into kinetic energy that propels the pieces apart.
  • The total kinetic energy after the explosion is the same as the total energy released, 7500 J.
  • All of this energy becomes kinetic energy for the two moving pieces: \( KE_1 + KE_2 = 7500 \, \mathrm{J} \).
By applying energy conservation, we calculated the kinetic energies of the pieces to be 4500 J and 3000 J, ensuring the total remains constant.
The Role of Internal Explosion
An internal explosion is a sudden release of energy within an object that causes it to break apart with a force. In our exercise, such an explosion occurs, and the object splits into two pieces.
Understanding the mechanics of internal explosions helps explain why and how the pieces move. The explosion inside releases energy, often in the form of heat and work, causing the object’s segments to gain speed and fly apart.
  • Momentum before the explosion is zero because the object starts from rest.
  • Post-explosion, the conservation of momentum ensures that the momentum of one piece is balanced by the momentum of the other, but they travel in opposite directions.
  • We calculated using the momentum principle \( m_1v_1 = m_2v_2 \), which shows how the velocities are connected to the masses.
This helps us distribute the 7500 J of energy across the two pieces using their mass ratio, as the explosion does not add or remove total momentum, only transforms the initial potential into kinetic action.

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Most popular questions from this chapter

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