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(II) The decay of a neutron into a proton, an electron, and a neutrino is an example of a three-particle decay process. Use the vector nature of momentum to show that if the neutron is initially at rest, the velocity vectors of the three must be coplanar (that is, all in the same plane). The result is not true for numbers greater than three.

Short Answer

Expert verified
The three momentum vectors must be coplanar due to conservation of momentum.

Step by step solution

01

Understanding the Problem

We need to demonstrate that if a neutron at rest decays into three particles, the momenta of these particles are coplanar. We will use the concept of conservation of momentum to prove this.
02

Initial Conditions

The neutron is initially at rest, meaning its initial momentum is zero. After the decay, the neutron transforms into a proton, an electron, and a neutrino, each with a momentum vector.
03

Application of Conservation of Momentum

Since the neutron was initially at rest, the combined momentum of the three resulting particles must still add up to zero. This gives us the equation: \( \vec{p}_{proton} + \vec{p}_{electron} + \vec{p}_{neutrino} = \vec{0} \).
04

Solving for Coplanarity

The sum of the vectors must be zero, implying these vectors form a closed triangle, since there are only three vectors. The only way these three vectors can add up to zero and form a closed geometric shape is if they lie in a single plane, thus being coplanar.
05

Conclusion

For three vectors, as in this decay process, the momentum conservation naturally results in them being coplanar. This conclusion does not hold for four or more vectors, as they can form higher-dimensional shapes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
Momentum is a crucial concept in physics, especially when analyzing particle decays. It refers to the product of an object's mass and velocity. In any isolated system, the total momentum remains constant, meaning it is conserved.
In the neutron decay process, we see the neutron initially at rest, making its initial momentum zero. Upon decay, it splits into three particles: a proton, an electron, and a neutrino. Each particle carries its own momentum vector, symbolized as \( \vec{p}_{proton} \), \( \vec{p}_{electron} \), and \( \vec{p}_{neutrino} \).
Because momentum is conserved, the sum of these momenta must still equal the neutron's starting momentum, which was zero. This is mathematically expressed as: \\[ \vec{p}_{proton} + \vec{p}_{electron} + \vec{p}_{neutrino} = \vec{0}. \]
This equation shows that even after the neutron decays, there is no net change in momentum.
Coplanarity
Coplanarity is a geometric property relevant in vector mathematics. It implies that all vectors or lines lie on the same plane. In the context of a three-particle decay, if the momentum vectors form a closed geometric shape, like a triangle, they must be coplanar.
When a neutron decays and produces three particles, their momentum vectors must add up to zero, a condition they can only satisfy if they lie in the same plane.
Imagine three arrows (vectors) pointing around in a circle: their heads touching tail to tail, forming a loop. None protrudes out of the plane of the paper, demonstrating coplanarity. Should there be more than three vectors, such a closed shape isn't strictly confined to a single plane, allowing for higher-dimensional configurations.
Therefore, whenever you witness a three-particle decay, identifying coplanarity becomes a vital task.
Neutron Decay
Neutron decay is an important example of radioactive decay and is critical for our understanding of particle physics. A free neutron is unstable, with a lifespan of about 14 minutes, and will eventually decay.
This decay process involves the neutron transforming into three separate particles: a proton, an electron, and a neutrino. Each of these particles carries away energy and momentum. The process can be represented by the reaction: \\[ n \rightarrow p + e^- + \overline{u}_e \]
This notation indicates that a neutron (\( n \)) decays into a proton (\( p \)), an electron (\( e^- \)), and an antineutrino (\( \overline{u}_e \)). It is an example of weak nuclear force, one of the four fundamental forces in nature responsible for this transformation.
Understanding neutron decay helps physicists investigate the stability of matter and the forces that govern particle interactions.

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