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(III) If an infinitely deep well of width \(\ell\) is redefined to be located from \(x=-\frac{1}{2} \ell\) to \(x=\frac{1}{2} \ell\) (as opposed to \(x=0\) to \(x=\ell\) ), speculate how this will change the wave function for a particle in this well. Investigate your speculation(s) by determining the wave functions and energy levels for this newly defined well. [Hint: \(\operatorname{Try} \psi=A \sin (k x+\phi)\).

Short Answer

Expert verified
The wave functions are \(\psi_n(x) = \sqrt{\frac{2}{\ell}} \sin\left(\frac{2\pi n}{\ell}x\right)\) and energy levels are \(E_n = \frac{2\hbar^2 \pi^2 n^2}{m\ell^2}\).

Step by step solution

01

Define the Problem with Boundaries

An infinitely deep well is defined with new boundaries from \(x = -\frac{1}{2} \ell\) to \(x = \frac{1}{2} \ell\). We aim to find the wave functions and energy levels for a particle confined in this well. The standard wave function for a particle in a box is assumed to be of the form \(\psi(x) = A \sin(kx+\phi)\).
02

Apply Boundary Conditions

Based on the new boundaries, the wave function must be zero at the edges of the well. Thus, \(\psi\left(-\frac{1}{2}\ell\right) = 0\) and \(\psi\left(\frac{1}{2}\ell\right) = 0\). This leads us to two conditions: \(A \sin\left(k \left(-\frac{1}{2}\ell\right) + \phi\right) = 0\) and \(A \sin\left(k \left(\frac{1}{2}\ell\right) + \phi\right) = 0\).
03

Solve the Boundary Conditions

Since \(A\) cannot be zero (as it would negate the wave function), we use \(\sin(\theta) = 0\) implying \(\theta = n\pi\). Therefore, we set \(k \left(-\frac{1}{2}\ell\right) + \phi = m\pi\) and \(k \left(\frac{1}{2}\ell\right) + \phi = n\pi\) where \(m\) and \(n\) are integers. Solving this yields, \(k = \frac{2\pi n}{\ell}\) and \(\phi = 0\).
04

Derive the Wave Function

Given \(\phi = 0\), the wave function becomes \(\psi(x) = A \sin\left(\frac{2\pi n}{\ell}x\right)\). The normalization condition \(\int_{-\frac{1}{2}\ell}^{\frac{1}{2}\ell} |\psi(x)|^2 \, dx = 1\) helps us find \(A\). This results in \(A = \sqrt{\frac{2}{\ell}}\). Finally, the wave function is \(\psi_n(x) = \sqrt{\frac{2}{\ell}} \sin\left(\frac{2\pi n}{\ell}x\right)\).
05

Calculate the Energy Levels

The energy levels for the particle are found using the relation \(E_n = \frac{\hbar^2 k^2}{2m}\). Substituting \(k = \frac{2\pi n}{\ell}\), the energy levels become \(E_n = \frac{\hbar^2 (2\pi n)^2}{2m\ell^2} = \frac{2\hbar^2 \pi^2 n^2}{m\ell^2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Particle in a Box
The concept of a "particle in a box" is a fundamental model in quantum mechanics. Imagine putting a small particle, like an electron, inside a box with barriers so high the particle cannot escape. These barriers are considered to be "infinitely deep," meaning the particle is completely confined within the box.

This setup is not just a box; it closely represents how particles behave in tiny spaces, like electrons in an atom. Mathematically, this means the particle can only exist within certain limits, for example, between \(x = -\frac{1}{2} \ell\) and \(x = \frac{1}{2} \ell\). This is where it will move, vibrate, and form unique patterns called wave functions.

The boundaries define the "box," and help in determining where the particle can be found. In quantum mechanics, this simple model tells a lot about the behavior of particles in physics, giving rise to specific properties like energy levels and wave functions that describe them.
Wave Function
The wave function is a crucial concept in quantum mechanics. It represents the quantum state of a particle or system of particles through a mathematical function. By solving the Schrödinger equation for a particle in a box, we find the potential wave function that describes the probability of finding a particle in a certain position inside the box.

For a particle in our newly defined box, the wave function takes the form: \(\psi_n(x) = \sqrt{\frac{2}{\ell}} \sin\left(\frac{2\pi n}{\ell}x\right)\).

  • \(\psi\) represents the wave function.
  • \(n\) is an integer that represents the energy level or quantum state.
  • The sine function models the oscillatory nature of the particle within the confines of the box.

The wave function has to follow specific rules; it must be zero at the boundaries to match the physical constraint that the particle cannot exist outside the box. In essence, the wave function provides the framework through which we understand the probability distribution of a particle within the box.
Energy Levels
Energy levels in a quantum mechanical system such as a particle in a box are quantized. This means that the particle can only occupy certain discrete energy states. These are not continuous as we might expect in classical physics but instead occur at fixed values.

The energy levels for a particle in a box are given by the formula \(E_n = \frac{2\hbar^2 \pi^2 n^2}{m\ell^2}\).

  • \(E_n\) represents the energy level for a given state \(n\).
  • \(\hbar\) is the reduced Planck's constant, a fundamental constant in quantum mechanics.
  • \(m\) is the particle's mass, and \(\ell\) is the width of the box.

These energy levels are critical in understanding how and why particles behave the way they do in confined spaces. They show that particles can only possess certain energies, and this restriction leads to the unique behavior observed in quantum systems.
Boundary Conditions
Boundary conditions are essential to solving any physics problem involving differential equations, especially in quantum mechanics.

For our system, the boundary conditions state that the wave function must be zero at the box's edges. This is because the walls are infinitely high, and the particle cannot be found outside these boundaries.

In terms of math, this is expressed as: \(\psi\left(\frac{-1}{2}\ell\right) = 0\) and \(\psi\left(\frac{1}{2}\ell\right) = 0\).

  • This rule ensures the physical reality that the particle cannot "escape" the box.
  • It shapes the form of the wave function inside the box.

Without these boundary conditions, solving the Schrödinger equation wouldn't yield the specific wave functions and energy levels necessary for understanding a particle in a confined area. They dictate the behavior of the system's solutions, ensuring they align with physical expectations and constraints imposed by the setup.

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Most popular questions from this chapter

(I) An electron remains in an excited state of an atom for typically \(10^{-8}\) s. What is the minimum uncertainty in the energy of the state (in eV)?

(II) The neutrons in a parallel beam, each having kinetic energy \(0.030 \mathrm{eV}\), are directed through two slits \(0.60 \mathrm{~mm}\) apart. How far apart will the interference peaks be on a screen \(1.0 \mathrm{~m}\) away? [Hint: First find the wavelength of the neutron.

A neutron is trapped in an infinitely deep potential well 2.5 \(\mathrm{fm}\) in width. Determine \((a)\) the four lowest possible energy states and \((b)\) their wave functions. (c) What is the wavelength and energy of a photon emitted when the neutron makes a transition hetween the two lowest states? In what region of the EM spectrum does this photon lie? \([\) Note: This is a rough model of an atomic nucleus.]

Simple Harmonic Oscillator. Suppose that a particle of mass \(m\) is trapped not in a square well, but in one whose potential energy is that of a simple harmonic oscillator: \(U(x)=\frac{1}{2} C x^{2} .\) That is, if the particle is displaced from \(x=0\) a restoring force \(F=-C x\) acts on it, where \(C\) is constant. (a) Sketch this potential energy. (b) Show that \(\psi=A e^{-B x^{2}}\) is a solution to the Schrödinger equation and that the energy of this state is \(E=\frac{1}{2} \hbar \omega,\) where \(\omega=\sqrt{C / m}\) (as classically, Eq. \(14-5\) ) and \(B=m \omega / 2 \hbar\). [Note: This is the ground state, and this energy \(\frac{1}{2} \hbar \omega\) is the zero-point energy for a harmonic oscillator. The energies of higher states are \(E_{n}=\left(n+\frac{1}{2}\right) \hbar \omega,\) where \(n\) is an integer.

(1I) An electron with 180 \(\mathrm{eV}\) of kinetic energy in free space passes over a finite potential well 56 \(\mathrm{eV}\) deep that stretches from \(x=0\) to \(x=0.50 \mathrm{nm}\) . What is the electron's wavelength (a) in free space, ( \(b\) ) when over the well? (c) Draw a diagram showing the potential energy and total energy as a function of \(x,\) and on the diagram sketch a possible wave function.

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