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(I) An electron remains in an excited state of an atom for typically \(10^{-8}\) s. What is the minimum uncertainty in the energy of the state (in eV)?

Short Answer

Expert verified
The minimum uncertainty in energy is approximately \( 3.29 \times 10^{-8} \text{ eV} \).

Step by step solution

01

Understanding the Concept

This problem requires the application of Heisenberg's Uncertainty Principle, which relates the uncertainty in energy (\( \Delta E \)) to the uncertainty in time (\( \Delta t \)). Heisenberg's principle is given by the formula \( \Delta E \cdot \Delta t \geq \frac{\hbar}{2} \), where \( \hbar \) is the reduced Planck's constant (\( \hbar = \frac{h}{2\pi} \)).
02

Determine Key Values

The problem states the uncertainty in time \( \Delta t = 10^{-8} \) s. The reduced Planck's constant \( \hbar \) is approximately \( 1.0545718 \times 10^{-34} \) Js.
03

Substitute into the Uncertainty Equation

Apply the minimum uncertainty relation \( \Delta E = \frac{\hbar}{2\Delta t} \). Substitute \( \hbar = 1.0545718 \times 10^{-34} \text{ Js} \) and \( \Delta t = 10^{-8} \text{ s} \).
04

Calculate the Minimum Energy Uncertainty

Evaluate the expression \( \Delta E = \frac{1.0545718 \times 10^{-34}}{2 \times 10^{-8}} = 5.272859 \times 10^{-27} \text{ J} \).
05

Convert from Joules to Electron Volts

To convert the energy from joules to electron volts, use the conversion factor \( 1 \text{ eV} = 1.602176634 \times 10^{-19} \text{ J} \). Calculate \( \Delta E = \frac{5.272859 \times 10^{-27}}{1.602176634 \times 10^{-19}} \approx 3.29 \times 10^{-8} \text{ eV} \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Uncertainty
In the realm of quantum mechanics, the concept of energy uncertainty plays a pivotal role in understanding the limitations of our measurements. The "energy uncertainty" refers to the degree of indeterminacy or lack of precise information about the energy of a particle, such as an electron within an atom.
An essential principle addressing this is Heisenberg's Uncertainty Principle. It states that it is impossible to simultaneously know both the exact energy ( \( \Delta E \) ) and the exact time duration ( \( \Delta t \) ) that a particle remains in a certain state. This limitation is mathematically expressed as \[ \Delta E \cdot \Delta t \geq \frac{\hbar}{2} \] where \( \hbar \) represents the reduced Planck's constant.
This uncertainty relation implies that a shorter duration of time in an excited state corresponds to a larger uncertainty in energy. For instance, in our exercise, an electron remains in the excited state for \( 10^{-8} \) seconds, leading to a calculation of a minimum energy uncertainty which manifests the inherent quantum fluctuations in such a brief existence.
Reduced Planck's Constant
To fully grasp the calculations in quantum mechanics, one must appreciate the role of the reduced Planck's constant \( \hbar \) . It is a fundamental constant of nature, defined as \( \hbar = \frac{h}{2\pi} \) , where \( h \) is Planck's constant \( 6.62607015 \times 10^{-34} \) Js. It is used extensively in equations that describe the physical universe at quantum scales.
In our calculation of energy uncertainty, \( \hbar \) acts as a bridge between energy and time. Its small value illustrates the minute scale at which quantum effects operate and sets a fundamental limit to how accurately we can measure such quantities.
This smallness makes sense when we consider that quantum effects, like those we calculate here with energy uncertainties, become significant only at the microscopic level. Thus, \( \hbar \) plays a central role in dictating the accuracy and limits of what can be known about a quantum system's energy and time characteristics.
Excited State of an Atom
Atoms have various energy levels and an "excited state" is where an electron resides at a higher energy level than its ground state. When an electron absorbs energy, it moves to a higher level, entering an excited state temporarily.
The stability of these excited states can vary, but they are typically fleeting, as in our problem where the electron remains excited for only \( 10^{-8} \) seconds. During this brief period, the concept of energy uncertainty explains the lack of precision in measuring the exact energy levels of the electron.
This temporary nature of excited states is why emitted energy (often as light or radiation) returns the electron to a more stable state. The emission processes contribute to observable phenomena such as atomic spectra. Understanding the excited state helps explain why such atoms can emit certain amounts of energy and how uncertainty in this emission can be calculated.

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Most popular questions from this chapter

By how much does the tunneling current through the tip of an STM change if the tip rises 0.020 nm from some initial height above a sodium surface with a work function \(W_{0}=2.28 \mathrm{cV}\) ? [Hint: Let the work function equal the energy needed to raise the electron to the top of the barrier.

(II) An electron with an energy of \(8.0 \mathrm{eV}\) is incident on a potential barrier which is \(9.2 \mathrm{eV}\) high and \(0.25 \mathrm{nm}\) wide. (a) What is the probability that the electron will pass through the barrier? (b) What is the probability that the electron will be reflected?

(II) Consider an atomic nucleus to be a rigid box of width \(2.0 \times 10^{-14} \mathrm{~m} .\) What would be the ground-state energy for (a) an electron, (b) a neutron, and ( \(c\) ) a proton in this nucleus?

(II) Use the uncertainty principle to show that if an electron were present in the nucleus \(\left(r \approx 10^{-15} \mathrm{m}\right),\) its kinetic energy (use relativity) would be hundreds of MeV. (Since such electron energies are not observed, we conclude that electrons are not present in the nucleus) [Hint: Assume a particle can have energy as large as its uncertainty.]

(II) An electron in the \(n=2\) state of hydrogen remains there on average about \(10^{-8}\) s before jumping to the \(n=1\) state. (a) Estimate the uncertainty in the energy of the \(n=2\) state. (b) What fraction of the transition energy is this? (c) What is the wavelength, and width (in \(\mathrm{nm}\) ), of this line in the spectrum of hydrogen?

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