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(I) If the current in a \(280 - \mathrm { mH }\) coil changes steadily from 25.0\(\mathrm { A }\) to 10.0\(\mathrm { A }\) in \(360 \mathrm { ms } ,\) what is the magnitude of the induced emf?

Short Answer

Expert verified
The magnitude of the induced emf is 11.7 V.

Step by step solution

01

Identify the Given Values

We are given the inductance \( L = 280 \, \text{mH} \), the initial current \( I_i = 25.0 \, \text{A} \), the final current \( I_f = 10.0 \, \text{A} \), and the time interval for the change \( \Delta t = 360 \, \text{ms} \).
02

Convert Units Where Necessary

First, convert the inductance from millihenries to henries: \( L = 280 \, \text{mH} = 0.280 \, \text{H} \). Also, convert the time from milliseconds to seconds: \( \Delta t = 360 \, \text{ms} = 0.360 \, \text{s} \).
03

Calculate the Change in Current

Find the change in current \( \Delta I \) using the formula: \[ \Delta I = I_f - I_i = 10.0 \, \text{A} - 25.0 \, \text{A} = -15.0 \, \text{A} \].
04

Use Faraday's Law of Induction

The formula for the induced emf \( \mathcal{E} \) is given by: \[ \mathcal{E} = -L \frac{\Delta I}{\Delta t} \]. Substitute the values: \[ \mathcal{E} = -(0.280 \, \text{H}) \frac{-15.0 \, \text{A}}{0.360 \, \text{s}} \].
05

Perform the Calculations

Calculate the magnitude of the induced emf: \[ \mathcal{E} = 0.280 \times \frac{15.0}{0.360} \]. This simplifies to: \[ \mathcal{E} \approx 11.7 \, \text{V} \].
06

State the Final Answer

The magnitude of the induced emf is \( 11.7 \, \text{V} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law of Induction
Faraday's Law of Induction is a fundamental principle that describes how a change in magnetic field within a loop or coil can induce an electromotive force (emf). Simply put, if you move a magnet through a coil, it creates electricity, and the same happens when you change the current flowing through the coil.
Faraday's Law is mathematically expressed by the formula:
  • \( \mathcal{E} = -\frac{d \Phi}{dt} \), where \( \mathcal{E} \) represents the induced emf and \( \Phi \) is the magnetic flux.
  • In the context of an inductor, a change in current through the coil alters the magnetic field and thus the magnetic flux.
This law is crucial in understanding electrical devices such as transformers and inductors, by showing how electricity can be transferred or transformed by merely changing magnetic fields. By using this principle, Faraday's Law explains the basis of many electrical engineering applications, demonstrating how changes in electricity can efficiently transfer power or information.
Current Change
A change in current is integral to inducing an emf in a coil. When you have a coil, like in our original exercise, and the electrical current changes over time, this will either increase or decrease the magnetic field inside the coil.
Think of the coil's magnetic field as a type of 'magnetic pressure.' When there is a change in that 'pressure,' it drives the flow of electrical charge, creating an emf.
  • \( \Delta I = I_f - I_i \) is the formula used to calculate this change in current, where \( I_f \) is the final current and \( I_i \) is the initial current.
  • In our exercise, reducing the current from 25.0 A to 10.0 A resulted in a current change of \(-15.0 A\).
This concept is essential because without a change in current, no new magnetic field would be created or collapsed, making it impossible to have an induced emf. Understanding current change helps in managing how energy is stored or released in devices such as inductors, which play a key role in controlling electrical signals.
Inductor
An inductor is a passive electrical component that resists changes in current. Often characterized by coils of wire, inductors use the principles of electromagnetism to store energy in a magnetic field when electrical current flows through them.
When there is a change in the current passing through an inductor, it opposes this change by inducing an emf. This property is particularly useful in filtering signals, timing circuits, and managing electrical loads.
An inductor's key property is its inductance, denoted as \(L\), which is measured in henries (H). The inductance value indicates how effectively the inductor can induce an emf for a given current change:
  • In our exercise, the inductor had an inductance of \(0.280 \text{ H}\), demonstrating its capacity to oppose current changes and induce an emf of \(11.7 \text{ V}\).
  • Inductors are used in various applications, such as transformers, chokes, and filters, which require the control of current and voltage.
The understanding and application of inductors are crucial in designing electronic circuits and devices, allowing engineers to effectively manage electrical energy and signals.

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Most popular questions from this chapter

(II) ( \(a\) ) Determine a formula for the average power \(\bar{P}\) dissipated in an \(L R C\) circuit in terms of \(L, R, C, \omega,\) and \(V_{0}\) (b) At what frequency is the power a maximum? (c) Find an approximate formula for the width of the resonance peak in average power, \(\Delta \omega\), which is the difference in the two (angular) frequencies where \(\bar{P}\) has half its maximum value. Assume a sharp peak.

The output of an electrocardiogram amplifier has an impedance of \(45 \mathrm{k} \Omega\). It is to be connected to an \(8.0-\Omega\) loud speaker through a transformer. What should be the turns ratio of the transformer?

A 2200 -pF capacitor is charged to \(120 \mathrm{~V}\) and then quickly connected to an inductor. The frequency of oscillation is observed to be \(17 \mathrm{kHz}\). Determine \((a)\) the inductance, (b) the peak value of the current, and (c) the maximum energy stored in the magnetic field of the inductor.

A \(75-\Omega\) resistor and a \(6.8-\mu \mathrm{F}\) capacitor are connected in series to an ac source. Calculate the impedance of the circuit if the source frequency is \((a) 60 \mathrm{~Hz} ;(b) 6.0 \mathrm{MHz}\)

(II) A 75-W lightbulb is designed to operate with an applied ac voltage of \(120 \mathrm{~V} \mathrm{rms}\). The bulb is placed in series with an inductor \(L,\) and this series combination is then connected to a \(60-\mathrm{Hz} 240-\mathrm{V}\) rms voltage source. For the bulb to operate properly, determine the required value for \(L\). Assume the bulb has resistance \(R\) and negligible inductance.

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