/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 70 The output of an electrocardiogr... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The output of an electrocardiogram amplifier has an impedance of \(45 \mathrm{k} \Omega\). It is to be connected to an \(8.0-\Omega\) loud speaker through a transformer. What should be the turns ratio of the transformer?

Short Answer

Expert verified
The turns ratio should be 75:1.

Step by step solution

01

Understanding Impedance Matching

To ensure maximum power transfer from the amplifier to the loudspeaker, we need to match the impedance of the load (loudspeaker) to the impedance of the source (amplifier). This is done through impedance matching using a transformer.
02

Recall the Transformer Impedance Matching Formula

The turns ratio of a transformer () is related to the impedances by the formula: \[ n^2 = \frac{Z_{primary}}{Z_{secondary}} \]where \( n \) is the turns ratio of the transformer, \( Z_{primary} \) is the impedance of the amplifier, and \( Z_{secondary} \) is the impedance of the loudspeaker.
03

Substitute the Given Values

Given:\( Z_{primary} = 45\,\mathrm{k}\Omega = 45000\,\Omega \) (impedance of the amplifier),\( Z_{secondary} = 8\,\Omega \) (impedance of the loudspeaker).Substitute these values into the formula:\[ n^2 = \frac{45000}{8} \]
04

Calculate the Turns Ratio (n)

Calculate the value of \( n^2 \):\[ n^2 = \frac{45000}{8} = 5625 \]Then solve for \( n \):\[ n = \sqrt{5625} = 75 \]
05

Conclude with the Required Turns Ratio

The turns ratio of the transformer to match the impedance from the amplifier to the loudspeaker should be 75:1. This means the primary coil should have 75 times more turns than the secondary coil.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Impedance Matching
Impedance matching is a key concept in electrical engineering, particularly when dealing with the transmission of signals or power. In simple terms, it refers to making the impedance (opposition to current flow) of two circuits equal to ensure that power is transferred efficiently between them. This is important when you have a source like an amplifier and a load like a loudspeaker. If the impedances are not matched, only some of the power gets to the loudspeaker, and the rest is wasted, primarily as heat.

This is why transformers are often used: they allow engineers to adjust the impedance levels, so they match perfectly. By using the correct turns ratio, power loss is minimized, and the device operates more efficiently. This principle of impedance matching plays a crucial role in various fields, including audio equipment, telecommunications, and especially when dealing with sensitive medical devices like an electrocardiogram amplifier.
Electrocardiogram Amplifier
An electrocardiogram (ECG or EKG) amplifier is an essential component in medical diagnostics, particularly for monitoring heart activity. ECG amplifiers must be highly sensitive, as they pick up electrical signals from the heart which are very small compared to electrical noise from other sources.

The main role of an ECG amplifier is to amplify these weak signals for further processing, display, or storage. In our problem, the ECG amplifier has an output impedance of 45 kΩ. This high impedance is typical for such amplifiers, which need to maintain fidelity while amplifying small signals.

However, when you connect an ECG amplifier to a loudspeaker or other output device with significantly different impedance, you often need a transformer to ensure the amplifier output is correctly delivered to the loudspeaker, maintaining signal strength and quality.
Maximum Power Transfer
The Maximum Power Transfer Theorem is a fundamental principle in electrical circuits, stating that maximum power is transferred to the load when the load resistance equals the source resistance—this includes both real and imaginary parts in AC circuits. When both the source and load are not matched, power delivered to the load is less than the maximum possible.

Applying this theorem in the context of our problem, we use impedance matching via a transformer to adjust the load impedance (in this case, the loudspeaker's 8 Ω) to be equal to the source impedance (the amplifier's 45 kΩ). By setting the turns ratio of the transformer, we effectively "transform" the loudspeaker’s impedance to be seen by the amplifier as 45 kΩ, achieving maximum power transfer.

In mathematical terms, the turns ratio formula was given as \( n^2 = \frac{Z_{primary}}{Z_{secondary}} \). By plugging in our values, we calculated \( n = 75 \), indicating that the primary winding of the transformer needed 75 times more turns than the secondary to achieve the impedance match necessary for maximum power transfer.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An inductance coil draws 2.5\(\mathrm { A }\) de when connected to a \(45 - \mathrm { V }\) battery. When connected to a \(60 - \mathrm { Hz } 120 - \mathrm { V } ( \mathrm { rms } )\) source, the current drawn is 3.8\(\mathrm { A }\) (rms). Determine the inductance and resistance of the coil.

(II) In some experiments, short distances are measured by using capacitance. Consider forming an \(L C\) circuit using a parallel-plate capacitor with plate area \(A ,\) and a known inductance \(L . ( a )\) If charge is found to oscillate in this circuit at frequency \(f = \omega / 2 \pi\) when the capacitor plates are separated by distance \(x ,\) show that \(x = 4 \pi ^ { 2 } A \epsilon _ { 0 } f ^ { 2 } L\) . (b) When the plate separation is changed by \(\Delta x ,\) the circuit's oscillation frequency will change by \(\Delta f .\) Show that \(\Delta x / x \approx 2 ( \Delta f / f ) . ( c )\) If \(f\) is on the order of 1\(\mathrm { MHz }\) and can be measured to a precision of \(\Delta f = 1 \mathrm { Hz } ,\) with what percent accuracy can \(x\) be determined? Assume fringing effects at the capacitor's edges can be neglected.

(I) For a \(120 - \mathrm { V } , 60 - \mathrm { Hz }\) voltage, a current of 70\(\mathrm { mA }\) passing through the body for 1.0 s could be lethal. What must be the impedance of the body for this to occur?

(II) A damped \(L C\) circuit loses 3.5\(\%\) of its electromagnetic energy per cycle to thermal energy. If \(L = 65 \mathrm { mH }\) and \(C = 1.00 \mu \mathrm { F } ,\) what is the value of \(R ?\)

(II) ( \(a\) ) Determine a formula for the average power \(\bar{P}\) dissipated in an \(L R C\) circuit in terms of \(L, R, C, \omega,\) and \(V_{0}\) (b) At what frequency is the power a maximum? (c) Find an approximate formula for the width of the resonance peak in average power, \(\Delta \omega\), which is the difference in the two (angular) frequencies where \(\bar{P}\) has half its maximum value. Assume a sharp peak.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.