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(1I) An unknown particle moves in a straight line through crossed electric and magnetic fields with \(E=1.5 \mathrm{kV} / \mathrm{m}\) and \(B=0.034 \mathrm{T}\) . If the electric field is turned off, the particle moves in a circular path of radius \(r=2.7 \mathrm{cm} .\) What might the particle be?

Short Answer

Expert verified
The particle is likely an electron.

Step by step solution

01

Understanding the Forces Involved

Initially, the particle moves undisturbed in a straight line through crossed electric and magnetic fields. The electric field exerts a force of magnitude \( F_e = qE \), and the magnetic field exerts a force \( F_m = qvB \), where \( q \) is the particle's charge and \( v \) is its velocity. Since the particle moves straight, these forces balance: \( qE = qvB \).
02

Calculating the Velocity of the Particle

From the balanced forces \( qE = qvB \), we can solve for the velocity \( v \): \[ v = \frac{E}{B} \] Using the given values \( E = 1.5 \times 10^3 \text{ V/m} \) and \( B = 0.034 \text{ T} \), we find: \[ v = \frac{1500}{0.034} \approx 44117.65 \text{ m/s} \].
03

Analyzing Motion in the Magnetic Field

Once the electric field is off, the particle only experiences the magnetic force and moves in a circle of radius \( r \). The magnetic force \( F_m = qvB \) provides the centripetal force necessary for circular motion: \[ qvB = \frac{mv^2}{r} \].
04

Solving for the Mass-to-Charge Ratio

From the centripetal force equation \( qvB = \frac{mv^2}{r} \), we can isolate \( \frac{m}{q} \): \[ \frac{m}{q} = \frac{v}{rB} \]. Substitute \( v = 44117.65 \text{ m/s} \), \( r = 0.027 \text{ m} \), and \( B = 0.034 \text{ T} \) to find: \[ \frac{m}{q} = \frac{44117.65}{0.027 \times 0.034} \approx 47540.92 \text{ kg/C} \].
05

Identifying the Particle

The calculated mass-to-charge ratio can be compared to known particles. Multiply the obtained \( \frac{m}{q} \) by the charge of the electron (\( 1.6 \times 10^{-19} \) C) to find the mass: \[ m \approx 47540.92 \times 1.6 \times 10^{-19} \approx 7.6 \times 10^{-15} \text{ kg} \]. The mass suggests the particle is an electron.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Forces in Physics
In the scenario where a particle moves through crossed electric and magnetic fields, understanding the forces at play is crucial. The electric field, denoted as \( E \), applies a force \( F_e \) on a charged particle, calculated as \( qE \). Here, \( q \) represents the charge of the particle. Simultaneously, the magnetic field \( B \) exerts a magnetic force \( F_m \) given by \( qvB \), with \( v \) being the particle's velocity.

When these fields are crossed, the forces can balance each other. This results in the particle moving in a straight line. In such cases, the electric force equals the magnetic force: \( qE = qvB \). This equality ensures the particle's unaltered straight-line motion through the fields. Understanding the balance and interaction of these forces provides insight into how electric and magnetic influences operate on charged particles in physics.

These principles are foundational, as they aid in deciphering different particle interactions under specific field conditions. Studying these forces bridges knowledge gaps related to particle dynamics and serves as a stepping stone towards more advanced concepts.
Mass-to-Charge Ratio
The mass-to-charge ratio \((m/q)\) is an essential parameter in understanding how particles behave in electromagnetic fields. It represents how much mass per unit charge a particle has, influencing its trajectory and response to forces. In calculations, this ratio can be deduced from the formula \( \frac{m}{q} = \frac{v}{rB} \) derived from equating the magnetic force to the centripetal force needed for circular motion: \( qvB = \frac{mv^2}{r} \).

Here, \( v \) is the velocity of the particle, \( r \) is the radius of the circular path, and \( B \) is the magnetic field strength. By knowing these values, such as velocity and magnetic field, you can determine the mass-to-charge ratio. This step is pivotal when identifying unknown particles because each type of particle, like an electron or proton, has a distinct mass-to-charge ratio.

For instance, a computed mass-to-charge ratio near that of an electron's known value allows us to hypothesize about the nature of the particle involved. The precision in this calculation is essential for correctly identifying and categorizing particles in experimental physics.
Circular Motion in Magnetic Fields
When a charged particle enters a magnetic field perpendicularly, the result is typically a circular motion. This is due to the magnetic force acting as the centripetal force that retains the particle in its circular path. The magnetic force is expressed as \( qvB \), which is equal to the centripetal force \( \frac{mv^2}{r} \), maintaining this movement.

The radius \( r \) of the circle can inform us about the particle's velocity and charge based on the surrounding magnetic field. Smaller radii indicate higher speeds or larger charges, given a constant magnetic force. The understanding of this motion is imperative since it helps determine the path and fate of particles in fields.

Practically, observing such motion allows scientists to explore and measure properties of particles—like their velocities and charges—by altering the magnetic field. Tools such as cyclotrons and mass spectrometers utilize this principle to analyze particle behavior and composition. Circular motion in magnetic fields thus forms an integral tool in the exploration of particles at the microscopic level.

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Most popular questions from this chapter

A 2.0-m-long wire carries a current of \(8.2 \mathrm{~A}\) and is immersed within a uniform magnetic field \(\overrightarrow{\mathbf{B}}\). When this wire lies along the \(+x\) axis, a magnetic force \(\overrightarrow{\mathbf{F}}=(-2.5 \hat{\mathbf{j}}) \mathbf{N}\) acts on the wire, and when it lies on the \(+y\) axis, the force is \(\overrightarrow{\mathbf{F}}=(2.5 \hat{\mathbf{i}}-5.0 \hat{\mathbf{k}}) \mathbf{N} .\) Find \(\overrightarrow{\mathbf{B}}\)

(II) An electron experiences a force \(\vec{\mathbf{F}}=(3.8 \hat{\mathbf{i}}-2.7 \hat{\mathbf{j}}) \times 10^{-13} \mathrm{N}\) when passing through a magnetic field \(\quad \vec{\mathbf{B}}=(0.85 \mathrm{T}) \hat{\mathbf{k}}\) . Determine the components of the electron's velocity.

(II) An electron moves with velocity \(\vec{\mathbf{v}}=(7.0 \hat{\mathbf{i}}-6.0 \hat{\mathbf{j}}) \times 10^{4} \mathrm{m} / \mathrm{s}\) in a magnetic field \(\vec{\mathbf{B}}=(-0.80 \hat{\mathrm{i}}+0.60 \hat{\mathrm{j}}) \mathrm{T}\) . Determine the magnitude and direction of the force on the electron.

In a probe that uses the Hall effect to measure magnetic fields, a 12.0-A current passes through a 1.50 -cm-wide 1.30-mm-thick strip of sodium metal. If the Hall emf is \(1.86 \mu \mathrm{V},\) what is the magnitude of the magnetic field (take it perpendicular to the flat face of the strip)? Assume one free electron per atom of \(\mathrm{Na}\), and take its specific gravity to be 0.971 .

A proton follows a spiral path through a gas in a magnetic field of \(0.018 \mathrm{~T}\), perpendicular to the plane of the spiral, as shown in Fig. \(27-54 .\) In two successive loops, at points \(P\) and \(\mathrm{Q},\) the radii are \(10.0 \mathrm{~mm}\) and \(8.5 \mathrm{~mm},\) respectively. Calculate the change in the kinetic energy of the proton as it travels from \(P\) to \(Q\)

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