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One form of mass spectrometer accelerates ions by a voltage \(V\) before they enter a magnetic field \(B .\) The ions are assumed to start from rest. Show that the mass of an ion is \(m=q B^{2} R^{2} / 2 V,\) where \(R\) is the radius of the ions' path in the magnetic field and \(q\) is their charge.

Short Answer

Expert verified
The mass of the ion is given by \( m = \frac{q B^{2} R^{2}}{2 V} \).

Step by step solution

01

Understand the Concepts Involved

A mass spectrometer measures the mass-to-charge ratio of ions. Here, ions are accelerated by a voltage \(V\) and then enter a magnetic field \(B\), tracing a circular path of radius \(R\). We aim to derive a formula for the mass \(m\) of the ion.
02

Apply Conservation of Energy

When ions are accelerated by a voltage \(V\), they gain kinetic energy. The work done on the ions is equal to their kinetic energy: \( qV = \frac{1}{2}mv^2 \).
03

Use the Equation for Circular Motion

In a magnetic field, a charged particle moves in a circular path, and the magnetic force provides the centripetal force. We use the equation: \( qvB = \frac{mv^2}{R} \). Simplifying, we get the speed as \( v = \frac{qBR}{m} \).
04

Equate Energy and Circular Motion Formulas

From Step 2, we have \( \frac{1}{2}mv^2 = qV \). Substitute \( v = \frac{qBR}{m} \) from Step 3 into this equation: \( \frac{1}{2}m\left(\frac{qBR}{m}\right)^2 = qV \).
05

Simplify the Equation

\( \frac{1}{2} \frac{q^2 B^2 R^2}{m} = qV \). Divide both sides by \(q\) and solve for \(m\): \( m = \frac{q B^2 R^2}{2V} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field
A magnetic field is a fundamental concept in physics that describes the influence a magnetic material or moving electric charges can have in space. When an ion enters a magnetic field, this field exerts a force on it. This force is perpendicular to both the motion of the ion and the direction of the magnetic field.
In the context of a mass spectrometer, the magnetic field is crucial. It affects the path of ions, causing them to move in a circular path. The strength of the magnetic field, denoted as \( B \), plays a significant role in determining the radius of this circle. When ions are exposed to a uniform magnetic field, different ions will have different circular paths based on their mass-to-charge ratios.
By observing these paths, scientists can derive information about the mass and charge of the ions, helping to identify them.
Ions
Ions are atoms or molecules that have gained or lost electrons, resulting in a net charge. In a mass spectrometer, ions are the main subjects of study. These charged particles are accelerated through an electric field before entering the magnetic region.
The charge of ions, represented as \( q \), influences how they react to the magnetic field. Positive ions, having lost electrons, and negative ions, having gained electrons, will deflect in opposite directions within the magnetic field. The extent of this deflection is dependent on the ion's charge and other factors like velocity and magnetic field strength.
Understanding ions and their properties is crucial for interpreting mass spectrometer data, as different ions will behave differently, providing insights into their identity and quantity.
Kinetic Energy
Kinetic energy is the energy that an object possesses due to its motion. When ions are accelerated in a mass spectrometer, they gain kinetic energy. The amount of kinetic energy imparted onto the ions depends on the voltage \( V \) used to accelerate them.
The relationship between kinetic energy and voltage is given by the equation \( qV = \frac{1}{2}mv^2 \). Here, \( m \) is the mass of the ion, \( q \) is the charge, and \( v \) is the velocity. This equation is derived from the work-energy principle, where the work done on the ion equals the change in kinetic energy.
By understanding kinetic energy, we can calculate the velocity of the ions before they enter the magnetic field, which is essential for determining their path within the field.
Circular Motion
Circular motion occurs when an object moves in a path that forms a circle. In a mass spectrometer, ions exhibit circular motion when they are subjected to the magnetic field. This motion is governed by the balance between the magnetic force and the centripetal force required to keep the ion in a circular path.
The formula \( qvB = \frac{mv^2}{R} \) describes how the magnetic force \( qvB \) provides the centripetal force necessary to maintain the circular motion. Here, \( R \) is the radius of the circle. Solving for velocity \( v \), we use \( v = \frac{qBR}{m} \), which links the ion's speed with its charge and mass, magnetic field strength, and the radius of its path.
Understanding circular motion allows us to deduce critical properties of ions such as their mass, when combined with kinetic energy insights. This is a key concept in analyzing and interpreting data from mass spectrometry experiments.

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Most popular questions from this chapter

(II) A Hall probe used to measure magnetic field strengths consists of a rectangular slab of material (free-electron density \(n )\) with width \(d\) and thickness \(t,\) carrying a current \(I\) along its length \(\ell\) . The slab is immersed in a magnetic field of magnitude \(B\) oriented perpendicular to its rectangular face (of area \(\ell d ),\) so that a Hall emf \(\mathscr{E}_{\mathrm{H}}\) is produced across its width \(d .\) The probe's magnetic sensitivity, defined as \(K_{\mathrm{H}}=8_{\mathrm{H}} / I B,\) indicates the magnitude of the Hall emf achieved for a given applied magnetic field and current. A slab with a large \(K_{H}\) is a good candidate for use as a Hall probe. (a) Show that \(K_{H}=1 /\) ent. Thus, a good Hall probe has small values for both \(n\) and \(t\) . \((b)\) As possible candidates for the material used in a Hall probe, consider \(\left(\) i) a typical metal \(\left(n \approx 1 \times 10^{29} / \mathrm{m}^{3}\right)\) and \right. (ii) a (doped) semiconductor \(\left(n \approx 3 \times 10^{22} / \mathrm{m}^{3}\right) .\) Given that a semiconductor slab can be manufactured with a thickness of \(0.15 \mathrm{mm},\) how thin \((\mathrm{nm})\) should a metal slab be to yield a \(K_{\mathrm{H}}\) value equal to that of the semiconductor slab? Compare this metal slab thickness with the 0.3 -nm size of a typical metal atom. (c) For the typical semiconductor slab described in part \((b),\) what is the expected value for \(\mathscr{E}_{\mathrm{H}}\) when \(I=100 \mathrm{mA}\) and \(B=0.1 \mathrm{T}\) ?

(1) A 13.0 -cm-diameter circular loop of wire is placed with the plane of the loop parallel to the uniform magnetic field between the pole pieces of a large magnet. When 4.20 \(\mathrm{A}\) flows in the coil, the torque on it is 0.185 \(\mathrm{m} \cdot \mathrm{N}\) . What is the magnetic field strength?

An electron experiences a force \(\overrightarrow{\mathbf{F}}=(3.8 \hat{\mathbf{i}}-2.7 \hat{\mathbf{j}}) \times 10^{-13} \mathbf{N}\) when passing through a magnetic field \(\overrightarrow{\mathbf{B}}=(0.85 \mathrm{~T}) \hat{\mathbf{k}}\). Determine the electron's velocity.

A proton moves through a region of space where there is a magnetic field \(\overrightarrow{\mathbf{B}}=(0.45 \hat{\mathbf{i}}+0.38 \hat{\mathbf{j}}) \mathrm{T}\) and an electric field \(\overrightarrow{\mathbf{E}}=(3.0 \hat{\mathbf{i}}-4.2 \hat{\mathbf{j}}) \times 10^{3} \mathrm{~V} / \mathrm{m}\). At a given instant, the proton's velocity is \(\overrightarrow{\mathbf{v}}=(6.0 \hat{\mathbf{i}}+3.0 \hat{\mathbf{j}}-5.0 \hat{\mathbf{k}}) \times 10^{3} \mathrm{~m} / \mathrm{s}\). Determine the components of the total force on the proton.

(I) If the restoring spring of a galvanometer weakens by 15\(\%\) over the years, what current will give full-scale deflection if it originally required 46\(\mu \mathrm{A}\) ?

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