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(III) \(\operatorname{An} 8.00 \mu \mathrm{C}\) charge is on the \(x\) axis of a coordinate system at \(x=+5.00 \mathrm{~cm} .\) A \(-2.00 \mu \mathrm{C}\) charge is at \(x=-5.00 \mathrm{~cm}\) (a) Plot the \(x\) component of the electric field for points on the \(x\) axis from \(x=-30.0 \mathrm{~cm}\) to \(x=+30.0 \mathrm{~cm} .\) The sign of \(E_{x}\) is positive when \(\overrightarrow{\mathbf{E}}\) points to the right and negative when it points to the left. \((b)\) Make a plot of \(E_{x}\) and \(E_{y}\) for points on the \(y\) axis from \(y=-30.0\) to \(+30.0 \mathrm{~cm}\)

Short Answer

Expert verified
Calculate electric fields from both charges at each position, sum them at each point, and plot the resultant fields on the x and y axes.

Step by step solution

01

Conceptualize Electric Field

Firstly, recall that the electric field due to a point charge \(q\) at a distance \(r\) is given by the formula \(E = \frac{k \, |q|}{r^2}\), where \(k\) is Coulomb's constant \(8.99 \times 10^9 \, \text{N m}^2/\text{C}^2\). The direction of the electric field is away from the charge if it is positive, and towards the charge if it is negative.
02

Calculate Electric Field on the x-axis

For each point \(x\) on the x-axis from \(-30.0 \textrm{ cm}\) to \(+30.0 \textrm{ cm}\), calculate the electric field contribution from both charges: the \(+8.00 \, \mu \text{C}\) at \(+5.00 \, \text{cm}\) and the \(-2.00 \, \mu \text{C}\) at \(-5.00 \, \text{cm}\). Use the formula \(E = \frac{k \, |q|}{(x - x_q)^2}\). Remember that the direction of the electric field depends on the sign of the charges.
03

Sum the Electric Fields on x-axis

At each point \(x\), sum the electric fields from both charges. The overall electric field \(E_x\) will be a superposition of the individual electric fields based on their directions (signs). Remember to assign positive or negative signs based on the direction of each field vector at each given point.
04

Visualize and Plot E_x on the x-axis

Plot the summed electric field \(E_x\) as a function of \(x\) from \(x = -30.0 \, \text{cm}\) to \(x = +30.0 \, \text{cm}\). This involves creating a graph with \(x\)-axis positions and corresponding \(E_x\) values, showing how the electric field changes along the x-axis.
05

Electric Field on the y-axis - Components

For points on the y-axis, at position \(y\), calculate the contributions to \(E_x\) and \(E_y\). Use \(E_x = \frac{k \, |q| \, x}{(x^2 + y^2)^{3/2}}\) and \(E_y = \frac{k \, |q| \, y}{(x^2 + y^2)^{3/2}}\). This reorientation accounts for distances and the vector component direction away or towards the charged points.
06

Sum and Plot E_x and E_y on the y-axis

Plot \(E_x\) and \(E_y\) separately for each point on the y-axis from \(y = -30.0 \, \text{cm}\) to \(y = +30.0 \, \text{cm}\). Again, ensure to correctly sum vector components and signify direction based on their respective charge influence.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law is a cornerstone principle in understanding electric fields and how they arise from charges. It quantifies the amount of force between two stationary, electrically charged particles. This law is expressed mathematically as \[F = \frac{k \cdot |q_1 \cdot q_2|}{r^2}\]where:
  • \(F\) is the magnitude of the force between the charges,
  • \(k\) is Coulomb's constant, equal to \(8.99 \times 10^9 \text{ N m}^2/\text{C}^2 \),
  • \(q_1\) and \(q_2\) are the amounts of each charge,
  • \(r\) is the distance between the centers of the two charges.
The force is attractive if the charges are of opposite signs, and repulsive if they are the same. This fundamental law helps us predict how charges will interact on a basic level and forms the foundation for calculating electric fields. By applying Coulomb's Law, one can determine not just the force but also the distribution of this force in space, dictating how electric fields manifest.
Point Charges
Point charges are idealized charges that are assumed to occupy a single point in space. This simplification allows us to easily apply formulas like those from Coulomb's Law to calculate forces and fields in theoretical scenarios. Understanding point charges is essential when working with electric fields. Since real charges are often distributed over a volume, considering them as point charges simplifies mathematical calculations and visualizations of the field. In practice, a point charge is a useful simplification for charges where dimensions are negligible compared to the distances of interest. In our given exercise, the charges are considered as point charges positioned along the axis: an \(8.00 \mu \text{C}\) charge at \(+5.00 \text{ cm}\) and a \(-2.00 \mu \text{C}\) charge at \(-5.00\text{ cm}\). This simplification helps in plotting and calculating the electric field components without complicating the model with physical dimensions.
Electric Field Components
An electric field represents the force a charge would experience at a specific location, described as a vector field. Understanding the components of an electric field is crucial for solving complex problems in electrodynamics. When a charge is placed in an electric field, it experiences force given by \[\mathbf{E} = \frac{\mathbf{F}}{q}\]where \( \mathbf{E} \) is the electric field, \( \mathbf{F} \) is force, and \( q \) is charge. The vector nature of electric fields allows for decomposition into components, usually on x, y, and z axes.For the exercise at hand, we focused on electric field components along x and y axes:
  • On the x-axis, the electric field \( E_x \) was influenced directly by the line charges, determined by their respective positions and magnitudes.
  • On the y-axis, both \(E_x\) and \( E_y \) components had to be calculated, considering their positions perpendicular to the line of charges on the x-axis.
This component analysis enables precise plotting of both magnitude and direction at various points along the axes, showcasing how electric fields react across distances and orientations.

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Most popular questions from this chapter

(II) Two charged spheres are \(8.45 \mathrm{~cm}\) apart. They are moved, and the force on each of them is found to have been tripled. How far apart are they now?

(II) A person scuffing her feet on a wool rug on a dry day accumulates a net charge of \(-46 \mu\) C. How many excess electrons does she get, and by how much does her mass increase?

(III) A thin ring-shaped object of radius \(a\) contains a total charge \(Q\) uniformly distributed over its length. The electric field at a point on its axis a distance \(x\) from its center is given in Example 9 of "Electric Charge and Electric Field" as \(E = \frac { 1 } { 4 \pi \epsilon _ { 0 } } \frac { Q x } { \left( x ^ { 2 } + a ^ { 2 } \right) ^ { \frac { 3 } { 2 } } }\) (a) Take the derivative to find where on the \(x\) axis \(( x > 0 ) E _ { x }\) is a maximum. Assume \(Q = 6.00 \mu \mathrm { C }\) and \(a = 10.0 \mathrm { cm } .\) (b) Calculate the electric field for \(x = 0\) to \(x = + 12.0 \mathrm { cmin }\) steps of \(0.1 \mathrm { cm } ,\) and make a graph of the electric field. Does the maximum of the graph coincide with the maximum of the electric field you obtained analytically? Also, calculate and graph the electric field \(( c )\) due to the ring, and \(( d )\) due to a point charge \(Q = 6.00 \mu C\) at the center of the ring. Make a single graph, from \(x = 0\) (or \(x = 1.0 \mathrm { cm }\) ) out to \(x = 50.0 \mathrm { cm }\) in 1.0\(\mathrm { cm }\) steps, with two curves of the electric fields, and show that both fields converge at large distances from the center. (e) At what distance does the electric field of the ring differ from that of the point charge by 10\(\% ?\)

(II) Compare the electric force holding the electron in orbit \(\left( r = 0.53 \times 10 ^ { - 10 } \mathrm { m } \right)\) around the proton nucleus of the hydrogen atom, with the gravitational force between the same electron and proton. What is the ratio of these two forces?

(I) Determine the magnitude and direction of the electric field 16.4\(\mathrm { cm }\) directly above an isolated \(33.0 \times 10 ^ { - 6 }\) Ccharge.

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