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(II) Compare the electric force holding the electron in orbit \(\left( r = 0.53 \times 10 ^ { - 10 } \mathrm { m } \right)\) around the proton nucleus of the hydrogen atom, with the gravitational force between the same electron and proton. What is the ratio of these two forces?

Short Answer

Expert verified
The ratio of the electric force to the gravitational force is approximately \(2.27 \times 10^{39}\).

Step by step solution

01

Understand the Forces Involved

The exercise requires us to compare two forces: the electric force and the gravitational force between an electron and a proton. Both forces are central forces and act over the distance given by the radius of the electron's orbit, which is \( r = 0.53 \times 10^{-10} \text{ m} \).
02

Calculate the Electric Force

The electric force \( F_e \) between two charges can be calculated using Coulomb's Law: \[ F_e = \frac{k \cdot |q_1 \cdot q_2|}{r^2} \] where \( k \) is Coulomb's constant \( 8.99 \times 10^9 \text{ Nm}^2/\text{C}^2 \), and \( q_1 \) and \( q_2 \) are the charges of the electron and proton respectively, both equal to the elementary charge, \( e = 1.60 \times 10^{-19} \text{ C} \). Substitute these values to find \( F_e \).
03

Calculate the Gravitational Force

The gravitational force \( F_g \) between two masses can be calculated using Newton's Law of Gravitation: \[ F_g = \frac{G \cdot m_1 \cdot m_2}{r^2} \]where \( G \) is the gravitational constant \( 6.674 \times 10^{-11} \text{ Nm}^2/\text{kg}^2 \), and \( m_1 \) and \( m_2 \) are the masses of the electron and proton, \( m_e = 9.11 \times 10^{-31} \text{ kg} \) and \( m_p = 1.67 \times 10^{-27} \text{ kg} \). Substitute these values to find \( F_g \).
04

Compute the Ratio of the Forces

To find the ratio of the electric force to the gravitational force, use the formula: \[ \frac{F_e}{F_g} = \frac{\frac{k \cdot e^2}{r^2}}{\frac{G \cdot m_e \cdot m_p}{r^2}} \]Simplifying, \[ \frac{F_e}{F_g} = \frac{k \cdot e^2}{G \cdot m_e \cdot m_p} \]Plug in the values: \[ \frac{F_e}{F_g} = \frac{(8.99 \times 10^9)(1.60 \times 10^{-19})^2}{(6.674 \times 10^{-11})(9.11 \times 10^{-31})(1.67 \times 10^{-27})} \]
05

Calculate the Numerical Result

By calculating the expression from Step 4, we find:\[ \frac{F_e}{F_g} \approx 2.27 \times 10^{39} \]This shows that the electric force is vastly stronger than the gravitational force between the electron and the proton in the hydrogen atom.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law helps us calculate the electric force between two charged particles. It's a fundamental principle in electromagnetism dealing with the force of attraction or repulsion between charged particles. The law can be expressed in the formula:
  • \[ F_e = \frac{k \cdot |q_1 \cdot q_2|}{r^2} \]
Here, \( F_e \) represents the magnitude of the electric force, \( k \) is Coulomb's constant, and \( q_1 \) and \( q_2 \) are the charges of the interacting particles. The separation distance between these charges is denoted by \( r \).
  • \( k \), also known as Coulomb's constant, is approximately \( 8.99 \times 10^9 \text{ Nm}^2/\text{C}^2 \).
To fully understand Coulomb's Law, imagine two small charged spheres placed a certain distance apart. If both spheres have the same type of charge, they will repel each other. Conversely, if they have opposite charges, they will attract each other. This relationship allows us to precisely calculate the force acting on one sphere caused by the other.
The importance of Coulomb's Law lies in predicting how particles interact. This isn't limited to simple systems but extends to complex molecular structures and even astronomical objects. Its scope is vast, making it a cornerstone in the study of physics.
Newton's Law of Gravitation
Newton's Law of Gravitation describes the attraction between two masses due to gravity. It's a classic law of physics, portraying how every object with mass in the universe is drawn towards every other object. The formula is as follows:
  • \[ F_g = \frac{G \cdot m_1 \cdot m_2}{r^2} \]
Where \( F_g \) is the gravitational force between two masses, \( G \) is the gravitational constant, \( m_1 \) and \( m_2 \) are the masses being considered, and \( r \) is the distance separating those masses.
  • The gravitational constant, \( G \), has a known value of \( 6.674 \times 10^{-11} \text{ Nm}^2/\text{kg}^2 \).
This law was revolutionary in providing an understanding of how objects interact across vast distances in space. Whether calculating the gravitational pull between the Earth and the Moon or the attraction between a pen and the Earth, the same foundational principle applies.
Newton's Law is crucial for comprehending the dynamics of celestial bodies. Its predictive power is evident when planning satellites' orbits, understanding planetary motions, or even grasping the possibility of black holes. Its universality showcases its importance, bridging concepts across scales from minuscule to astronomical.
Elementary Charge
The elementary charge is a fundamental physical constant representing the smallest unit of charge possible in isolated particles. It is symbolized by \( e \) and has a value of approximately \( 1.60 \times 10^{-19} \text{ C} \). This value reflects the charge of a single proton, or equivalently, the charge of a single electron (though electrons have a negative charge).Here's why understanding the elementary charge is important:
  • It provides a base for measuring other charges in systems, especially in atomic and molecular physics.
  • It's a critical component in equations like Coulomb's Law, influencing how electrostatic forces are calculated.
  • The notion of quantized charge is foundational for the concept of charge conservation, a pillar in physics ensuring that the total charge remains constant in an isolated system.
In practical terms, recognizing the elementary charge allows scientists and engineers to predict electric interactions on a micro-scale. Whether dealing with atom interactions, designing tiny semiconductor devices, or understanding biological ion channels, this constant plays an indispensable role. Grasping how charged particles behave and interact starts here.
Coulomb's Constant
Coulomb's constant, denoted by \( k \), is pivotal in the study of electrostatics, especially within Coulomb's Law. Its value is approximately \( 8.99 \times 10^9 \text{ Nm}^2/\text{C}^2 \), and it quantifies the strength of the electrostatic force between charges. Here are a few key points about Coulomb's constant:
  • It has been experimentally determined and is fundamental to calculations involving electric forces between point charges.
  • \( k \) influences how strongly two charged particles will attract or repel each other in space.
  • It is derived from deeper principles relating to the permittivity of free space, showcasing its link to broader electromagnetic theory.
Although it might seem like just a number, Coulomb's constant serves as a bridge between theoretical physics and practical calculations. When calculating forces in diverse contexts, from atomic bonding to large-scale electric fields, this constant ensures precision and consistency. Understanding \( k \) means appreciating the profound influences it has on microscopic phenomena and large-scale electric systems alike. This knowledge aids in technological advancements, innovation in electronics, and insights into natural electric patterns.

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Most popular questions from this chapter

(II) An electron with speed \(v_{0}=27.5 \times 10^{6} \mathrm{~m} / \mathrm{s}\) is traveling parallel to a uniform electric field of magnitude \(E=11.4 \times 10^{3} \mathrm{~N} / \mathrm{C} .\) (a) How far will the electron travel before it stops? (b) How much time will elapse before it returns to its starting point?

(II) Calculate the electric field at the center of a square \(52.5 \mathrm{~cm}\) on a side if one corner is occupied by a \(-38.6 \mu \mathrm{C}\) charge and the other three are occupied by \(-27.0 \mu \mathrm{C}\) charges.

Two small, identical conducting spheres \(A\) and \(B\) are a distance \(R\) apart; each carries the same charge \(Q . ( a )\) What is the force sphere B exerts on sphere A? (b) An identical sphere with zero charge, sphere \(C\) , makes contact with sphere \(B\) and is then moved very far away. What is the net force now acting on sphere A? (c) Sphere \(C\) is brought back and now makes contact with sphere \(A\) and is then moved far away. What is the force on sphere \(A\) in this third case?

A 3.0-g copper penny has a positive charge of \(38 \mu\) C. What fraction of its electrons has it lost?

When clothes are removed from a dryer, a 40 -g sock is stuck to a sweater, even with the sock clinging to the sweater's underside. Estimate the minimum attractive force between the sock and the sweater. Then estimate the minimum charge on the sock and the sweater. Assume the charging came entirely from the sock rubbing against the sweater so that they have equal and opposite charges, and approximate the sweater as a flat sheet of uniform charge

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