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(II) \(\mathrm{A} 220\) -g top spinning at 15 \(\mathrm{rev} / \mathrm{s}\) makes an angle of \(25^{\circ}\) to the vertical and precesses at a rate of 1.00 rev per 6.5 \(\mathrm{s}\) . If its \(\mathrm{CM}\) is 3.5 \(\mathrm{cm}\) from its tip along its symmetry axis, what is the moment of inertia of the top?

Short Answer

Expert verified
The moment of inertia of the top is calculated to be approximately 0.0025 kg·m².

Step by step solution

01

Convert Angular Velocities

First, convert the given angular velocities from revolutions to radians per second. The spinning rate is given as \(15 \text{ rev/s}\), which is equivalent to \(\omega_s = 15 \times 2\pi = 30\pi \text{ rad/s}\). The precession rate is \( 1.00 \text{ rev per 6.5 s} \), so \( \omega_p = \frac{2\pi}{6.5} \text{ rad/s} \).
02

Calculate Torque

The torque \( \tau \) due to gravity acting on the top can be calculated. The force due to gravity \( F = mg \), with \( m = 220 \text{ g} = 0.22 \text{ kg} \) and \( g = 9.8 \, \text{m/s}^2 \). The torque is given by: \[ \tau = r \cdot F \cdot \sin(\theta) = 0.035 \cdot 0.22 \cdot 9.8 \cdot \sin(25^{\circ}) \].
03

Relate Torque and Angular Momentum

The relation between torque, precessional angular velocity \( \omega_p \), and angular momentum \( L \) is \( \tau = \omega_p L \). Substituting for \( \tau \) and rearranging gives \( L = \frac{\tau}{\omega_p} \). Calculate \( L \) using the calculated values for \( \tau \) and \( \omega_p \).
04

Use Angular Momentum Equation

The relationship between angular momentum \( L \), moment of inertia \( I \), and the spinning angular velocity \( \omega_s \) is given by \( L = I \omega_s \). Solve for \( I \) by substituting the value of \( L \) found from Step 3 into this equation: \( I = \frac{L}{\omega_s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Momentum
Angular momentum can be thought of as the rotational equivalent of linear momentum. It is a vector quantity reflecting how much rotation an object possesses. Angular momentum, often denoted by the symbol \( L \), depends on three factors:
  • the object's moment of inertia \( I \),
  • the spinning rate or angular velocity \( \omega \),
  • and the axis about which it rotates.
For objects like spinning tops, the angular momentum \( L \) can be given by the equation \( L = I \omega_s \), where \( \omega_s \) is the spinning angular velocity.
Angular momentum plays a crucial role in how objects rotate, and because it is conserved in isolated systems, it can help predict how objects will behave when they encounter external forces, like the torque produced by gravity on a tilted spinning top.
Precession
Precession refers to the slow and continuous change in orientation of the axis of a rotating object. It often occurs in spinning tops, where the axis of rotation moves in a circular path due to external torques, like gravity.
In the example of our spinning top, precession is observed due to gravity acting at the center of mass creating a torque that tries to topple the top. However, because of the top's spin, it doesn't fall over. Instead, its axis traces a small circle in space. This behavior is quantified by the precession angular velocity \( \omega_p \).
Precession also illustrates the fascinating interplay of forces, angular momentum, and stability, a key aspect in gyroscopes and other applications like navigation systems and even the orbits of celestial bodies.
Angular Velocity
Angular velocity \( \omega \) measures how fast an object rotates or spins around an axis. It's analogous to linear velocity for rotating systems. This quantity is vectorial, indicating both the speed of rotation and its direction.
In problems involving rotation, there are often multiple angular velocities to consider. For instance:
  • The spinning angular velocity \( \omega_s \) represents how fast the top spins around its own axis.
  • The precession angular velocity \( \omega_p \) describes the rate at which the top's rotation axis moves in space.
Angular velocity is central to connecting rotational motion with linear concepts such as speed, enabling the computation of rotational energy and dynamics in systems.
Torque
Torque, often symbolized by \( \tau \), can be seen as the rotational equivalent of force. It measures how much a force acting on an object causes that object to rotate. The larger the torque, the more it changes the object's rotational motion.
The equation for torque is \( \tau = r \, F \, \sin(\theta) \), where:
  • \( r \) is the distance from the pivot point to the line of action of the force,
  • \( F \) is the magnitude of the force applied,
  • \( \theta \) is the angle between the force and the lever arm.
In the case of our spinning top, torque due to gravity provides a crucial cause of the precessional motion. It's essential in determining how the forces affect the angular momentum and the rate at which the top processes.

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Most popular questions from this chapter

(II) A figure skater can increase her spin rotation rate from an initial rate of 1.0 rev every 1.5 \(\mathrm{s}\) a final rate of 2.5 \(\mathrm{rev} / \mathrm{s} .\) If her initial moment of inertia was 4.6 \(\mathrm{kg} \cdot \mathrm{m}^{2}\) , what is her final moment of inertia? How does she physi- cally accomplish this change?

The directions of vectors \(\overrightarrow{\mathbf{A}}\) and \(\overrightarrow{\mathbf{B}}\) are given below for several cases. For each case, state the direction of \(\overrightarrow{\mathbf{A}} \times \overrightarrow{\mathbf{B}}\). (a) \(\overrightarrow{\mathbf{A}}\) points east, \(\overrightarrow{\mathbf{B}}\) points south. \((b) \overrightarrow{\mathbf{A}}\) points east, \(\overrightarrow{\mathbf{B}}\) points straight down. ( \(c\) ) \(\overrightarrow{\mathbf{A}}\) points straight up, \(\overrightarrow{\mathbf{B}}\) points north. (d) \(\overrightarrow{\mathbf{A}}\) points straight up, \(\overrightarrow{\mathbf{B}}\) points straight down.

(1) If vector \(\vec{\mathbf{A}}\) points along the negative \(x\) axis and vector \(\vec{\mathbf{B}}\) along the positive \(z\) axis, what is the direction of \((a) \vec{\mathbf{A}} \times \vec{\mathbf{B}}\) and \((b) \mathbf{B} \times \vec{\mathbf{A}} ?(c)\) What is the magnitude of \(\overline{\mathbf{A}} \times \vec{\mathbf{B}}\) and \(\vec{\mathbf{B}} \times \vec{\mathbf{A}} ?\)

Figure \(11-39\) shows a thin rod of mass \(M\) and length \(\ell\) resting on a frictionless table. The rod is struck at a distance \(x\) from its CM by a clay ball of mass \(m\) moving at speed \(v\). The ball sticks to the rod. (a) Determine a formula for the rotational motion of the system after the collision. (b) Graph the rotational motion of the system as a function of \(x,\) from \(x=0\) to \(x=\ell / 2,\) with values of \(M=450 \mathrm{~g}, \quad m=15 \mathrm{~g}\) \(\ell=1.20 \mathrm{~m},\) and \(v=12 \mathrm{~m} / \mathrm{s} .\) (c) Does the translational motion depend on \(x ?\) Explain.

$$ \begin{array}{l}{\text { (1) Show that }(a) \hat{\mathbf{i}} \times \hat{\mathbf{i}}=\hat{\mathbf{j}} \times \hat{\mathbf{j}}=\hat{\mathbf{k}} \times \hat{\mathbf{k}}=0,(b) \hat{\mathbf{i}} \times \hat{\mathbf{j}}=\hat{\mathbf{k}},} \\ {\hat{\mathbf{i}} \times \hat{\mathbf{k}}=-\hat{\mathbf{j}}, \text { and } \hat{\mathbf{j}} \times \hat{\mathbf{k}}=\hat{\mathbf{i}}}\end{array} $$

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