/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 One cubic meter of atomic hydrog... [FREE SOLUTION] | 91Ó°ÊÓ

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One cubic meter of atomic hydrogen at \(0^{\circ} \mathrm{C}\) and atmospheric pressure contains approximately \(2.70 \times 10^{25}\) atoms. The first excited state of the hydrogen atom has an energy of 10.2 eV above the lowest energy level, called the ground state. Use the Boltzmann factor to find the number of atoms in the first excited state at \(0^{\circ} \mathrm{C}\) and at \(10000^{\circ} \mathrm{C}\)

Short Answer

Expert verified
The number of atoms in the first excited state at \(0^{\circ} \mathrm{C}\) and \(10000^{\circ} \mathrm{C}\) can be found by using the Boltzmann factor and the given information, knowing that the Boltzmann factor defines the relative probability of a physical system being in a certain energy state. After converting necessary units and carrying out the calculations, the results can be obtained.

Step by step solution

01

Understanding the Boltzmann Factor

The Boltzmann factor gives the relative probability of a system being in a certain state with energy \(E\) at a certain temperature \(T\). The formula for the Boltzmann factor is: \(e^{-E/kT}\), where \(E\) is the energy of the state, \(k\) is the Boltzmann constant, and \(T\) is the temperature in Kelvin.
02

Converting Energy Units

The energy of the excited state is given in electron Volts (eV), but needs to be in Joules for the Boltzmann Factor equation. We can convert eV to Joules using the conversion factor: 1 eV = \(1.602 \times 10^{-19}\) J. So the energy \(E = 10.2 \times 1.602 \times 10^{-19}\) J.
03

Converting Temperatures to Kelvin

The temperature is given in degrees Celsius but needs to be in Kelvin for the Boltzmann Factor equation. We can convert \(T\) in Celsius to \(T\) in Kelvin using the equation: \(T(K) = T(°C) + 273.15\). So the two temperatures are \(T_1 = 0 + 273.15\) K and \(T_2 = 10000 + 273.15\) K.
04

Calculate the Number of Atoms in the Excited State

Finally, we can calculate the number of atoms in the excited state at each temperature. The number of atoms in a state of energy \(E\) at a temperature \(T\) is given by the total number of atoms times the Boltzmann factor, or \(N = N_{total} \times e^{-E/kT}\). The Boltzmann constant \(k\) is \(1.38 \times 10^{-23}\) J/K. Calculating this for both temperatures gives the number of atoms in the excited state.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Hydrogen
Atomic hydrogen refers to hydrogen in its most basic form, consisting of just one electron orbiting a single proton. It is the most abundant chemical substance in the Universe and serves as the building block for other molecules and complex structures. In this simplest form, hydrogen atoms can exist in various energy levels, with the ground state being their lowest energy level.

The significance of understanding atomic hydrogen in exercises like the provided one is because its behavior and properties are foundational to numerous fields, including quantum physics and astrophysics. When we explore phenomena such as the number of atoms in an excited state, we're diving into the transitions hydrogen atoms undergo, which are essential for everything from lighting up neon signs to powering the sun through nuclear fusion.
Excited State of Hydrogen
When we talk about the excited state of hydrogen, we're referring to a condition where its electron has absorbed energy and jumped to a higher energy level, beyond the ground state. Different energy levels are quantized, meaning the electron can only be at specific energy levels and nowhere in between. The excitation typically happens when the atom absorbs a photon or collides with another particle.

The energy required to move an electron from the ground state to an excited state is very specific. In the given exercise, the first excited state of hydrogen is 10.2 eV (electron Volts) higher than the ground state. Understanding these transitions is crucial for interpreting spectroscopic data and has implications in areas such as astrophysics, laser technology, and even quantum computing.
Energy Level in Physics
Energy levels in physics represent the quantized states of an electron in an atom. Imagine them as the rungs of a ladder that an electron can jump to or fall from, each rung corresponding to a specific energy state. These energy levels are fundamental to quantum mechanics and dictate how atoms absorb and emit light.

When solving exercises related to energy levels, like the one provided, we must remember that the energy difference between these levels determines the spectral lines we see in emission and absorption spectra. This information tells us about the composition of stars and other celestial bodies without needing to visit them physically. By calculating the population of atoms in different energy states, scientists can infer temperatures, densities, and the evolutionary state of distant astronomical objects.
Temperature Conversion
Temperature conversion is a critical step when applying the Boltzmann factor in physics exercises because the Boltzmann constant is in terms of energy per unit temperature in Kelvin. The Celsius scale, while convenient for everyday use, is not aligned with absolute zero, making Kelvin the preferred unit for scientific calculations.

To convert Celsius to Kelvin, you simply add 273.15 to the Celsius temperature. This step is imperative to getting the accurate Boltzmann factor. For instance, in the supplied exercise, temperature conversions from Celsius to Kelvin are required to calculate the number of hydrogen atoms in the first excited state at different temperatures. Familiarity with temperature conversion is not just important for this particular exercise, but for all thermodynamic equations where temperature plays a fundamental role.

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Most popular questions from this chapter

A \(4.00-\) L sample of a diatomic ideal gas with specific heat ratio \(1.40,\) confined to a cylinder, is carried through a closed cycle. The gas is initially at 1.00 atm and at \(300 \mathrm{K}\) First, its pressure is tripled under constant volume. Then, it expands adiabatically to its original pressure. Finally, the gas is compressed isobarically to its original volume. (a) Draw a PV diagram of this cycle. (b) Determine the volume of the gas at the end of the adiabatic expansion. (c) Find the temperature of the gas at the start of the adiabatic expansion. (d) Find the temperature at the end of the cycle. (e) What was the net work done on the gas for this cycle?

The largest bottle ever made by blowing glass has a volume of about \(0.720 \mathrm{m}^{3} .\) Imagine that this bottle is filled with air that behaves as an ideal diatomic gas. The bottle is held with its opening at the bottom and rapidly submerged into the ocean. No air escapes or mixes with the water. No energy is exchanged with the ocean by heat. (a) If the final volume of the air is \(0.240 \mathrm{m}^{3},\) by what factor does the internal energy of the air increase? (b) If the bottle is submerged so that the air temperature doubles, how much volume is occupied by air?

The compressibility \(\kappa\) of a substance is defined as the fractional change in volume of that substance for a given change in pressure: $$\kappa=-\frac{1}{V} \frac{d V}{d P}$$ (a) Explain why the negative sign in this expression ensures that \(\kappa\) is always positive. (b) Show that if an ideal gas is compressed isothermally, its compressibility is given by \(\kappa_{1}=1 / P\). (c) What If? Show that if an ideal gas is compressed adiabatically, its compressibility is given by \(\kappa_{2}=1 / \gamma P\). (d) Determine values for \(\kappa_{1}\) and \(\kappa_{2}\) for a monatomic ideal gas at a pressure of 2.00 atm.

A vertical cylinder with a movable piston contains 1.00 mol of a diatomic ideal gas. The volume of the gas is \(V_{i},\) and its temperature is \(T_{i} .\) Then the cylinder is set on a stove and additional weights are piled onto the piston as it moves up, in such a way that the pressure is proportional to the volume and the final volume is \(2 V_{i} .\) (a) What is the final temperature? (b) How much energy is transferred to the gas by heat?

A \(2.00-\) mol sample of oxygen gas is confined to a \(5.00-\mathrm{L}\) vessel at a pressure of 8.00 atm. Find the average translational kinetic energy of an oxygen molecule under these conditions.

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