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A certain molecule has \(f\) degrees of freedom. Show that an ideal gas consisting of such molecules has the following properties: (1) its total internal energy is \(f n R T / 2 ;(2)\) its molar specific heat at constant volume is \(f R / 2 ; \quad(3)\) its molar specific heat at constant pressure is \((f+2) R / 2\) (4) its specific heat ratio is \(\gamma=C_{P} / C_{V}=(f+2) / f\)

Short Answer

Expert verified
The total internal energy is given by \(fnRT/2\), the molar specific heat at constant volume is \(fR/2\), the molar specific heat at constant pressure is \((f+2)R/2\) and the specific heat ratio is \((f+2)/f\).

Step by step solution

01

Find total internal energy

The total internal energy (\(E\)) of an ideal gas can be given by \(E = fNkT/2\), where \(f\) is degree of freedom, \(N\) is the number of molecules, \(k\) is Boltzmann constant and \(T\) is the temperature in kelvin. But, the ideal gas law states that \(Nk = nR\), where \(n\) is the number of moles and \(R\) is the molar gas constant. Thus, we substitute \(Nk\) for \(nR\) in our energy equation and end up with \(E = fnRT/2\)
02

Find molar specific heat at constant volume

The molar specific heat at constant volume (\(C_v\)) is the change in internal energy with respect to the change in temperature, holding volume constant. So, \(C_v = dE/dT\) at constant \(V\). Differentiating the expression for the internal energy we found in Step 1 will yield \(C_v = fnR/2\). So, \(C_v = fR/2\) is proven.
03

Find molar specific heat at constant pressure

The molar specific heat at constant pressure (\(C_p\)) is always \(R\) more than \(C_v\) for ideal gases. So, \(C_p = C_v + R\) which when substituted with the value of \(C_v\) found in Step 2 and simplified gives us \(C_p = (f+2)R/2.\)
04

Find specific heat ratio

The specific heat ratio (\(\gamma\)) is defined as \(C_p/C_v\). Plug in the \(C_p\) and \(C_v\) we found in Steps 2 and 3 respectively. After carrying out the division, we see that \(\gamma = (f+2)/f\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Internal Energy of Ideal Gas
When it comes to understanding how an ideal gas stores energy, it's crucial to wrap your head around the concept of internal energy. In simple terms, internal energy is the total energy contained within the gas due to the motion of its molecules. It encompasses all the kinetic energy resulting from the random, disorderly movement of the gas particles.

Imagine countless tiny particles constantly zipping around in all directions; this image helps you visualize the internal energy. It depends directly on two things: the temperature, which relates to the average kinetic energy of these frenetic particles, and the degrees of freedom, which are essentially the ways in which these particles can move in space. For a monatomic gas, this could be simple x, y, z translations, but for more complex molecules, rotations and vibrations come into play.

In our context, for an ideal gas comprised of molecules with 'f' degrees of freedom, the internal energy is quantitatively expressed as \(E = \frac{f n R T}{2}\), where 'n' is the number of moles, 'R' is the gas constant, and 'T' is the absolute temperature. The key takeaway here: as temperature increases, so does the internal energy, indicative of livelier, more energetic particles.
Molar Specific Heat
Molar specific heat might sound fancy, but it's simply a measure of how much heat energy is needed to raise the temperature of one mole of a substance by one degree Celsius. There are two flavors here: the molar specific heat at constant volume (\(C_v\)) and at constant pressure (\(C_p\)).

Let's dig into the molar specific heat at constant volume. In a controlled volume, adding heat only increases the internal energy, as the gas particles speed up and heat up. There's no work done on the environment since the volume doesn't change. For an ideal gas, this is where the degrees of freedom come into play again - the molar specific heat at constant volume for a gas with 'f' degrees of freedom is \(C_v = \frac{f R}{2}\).

Molar Specific Heat at Constant Pressure

When you're dealing with constant pressure, a gas expands as it heats up, which means part of the heat input goes into doing the work of expansion. This is why \(C_p\) is always higher than \(C_v\), by an amount equal to the gas constant 'R'. The equation for an ideal gas turns out to be \(C_p = \frac{(f+2) R}{2}\). These equations reveal a deeper story about the substance you're dealing with and its inherent properties.
Specific Heat Ratio
The specific heat ratio, denoted as \(\gamma\), is the proportion of the molar specific heat at constant pressure to that at constant volume (\(\gamma = C_p / C_v\)). This ratio has no units since it's a pure number, but it holds a lot of significance in thermodynamics.

For one, this ratio is crucial in understanding how gases behave under different thermodynamic processes. Take, for example, adiabatic processes where no heat is exchanged with the surroundings; the specific heat ratio is central to predicting how pressure and volume will change.

An ideal gas with 'f' degrees of freedom has a specific heat ratio of \(\gamma = (f+2)/f\). This value is greater than 1 because \(C_p\) is always larger than \(C_v\), due to the need for extra energy in the form of work done when a gas expands at constant pressure. The ratio relates to speed of sound in a gas and even its ability to do work with efficiency - key concepts in engines and various other applications in physics and engineering.
Degrees of Freedom in Physics
Degrees of freedom in physics sounds abstract, but it's pretty grounded in motion. Basically, they're the independent ways a system (or an individual particle) can move without violating any constraints. Think of it as options for movement. In three-dimensional space, a particle can move up/down, left/right, and back/forth – giving it three translational degrees of freedom.

More complex particles, like diatomic molecules, can also rotate and vibrate, adding to their count of degrees of freedom. And here's the kicker: The number of degrees of freedom determines how energy is partitioned within a gas. The more ways a particle can move, the more ways it can store energy.

The Link to Internal Energy

Understanding degrees of freedom helps explain the internal energy of a gas and how it responds to changes in temperature. It directly influences the heat capacities \(C_v\) and \(C_p\), affecting everything from engine thermodynamics to atmospheric science. So, when you hear 'degrees of freedom,' think of the myriad ways particles express their energy as they whisk through space.

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Most popular questions from this chapter

A gas is at \(0^{\circ} \mathrm{C}\). If we wish to double the rms speed of its molecules, to what temperature must the gas be brought?

At what temperature would the average speed of helium atoms equal (a) the escape speed from Earth, \(1.12 \times 10^{4} \mathrm{m} / \mathrm{s}\) and \((\mathrm{b})\) the escape speed from the Moon, \(2.37 \times 10^{3} \mathrm{m} / \mathrm{s} ?\) (See Chapter 13 for a discussion of escape speed, and note that the mass of a helium atom is \(\left.6.64 \times 10^{-27} \mathrm{kg} .\right)\)

A house has well-insulated walls. It contains a volume of \(100 \mathrm{m}^{3}\) of air at \(300 \mathrm{K}\). (a) Calculate the energy required to increase the temperature of this diatomic ideal gas by \(1.00^{\circ} \mathrm{C} .\) (b) What If? If this energy could be used to lift an object of mass \(m\) through a height of \(2.00 \mathrm{m},\) what is the value of \(m ?\)

During the compression stroke of a certain gasoline engine, the pressure increases from 1.00 atm to 20.0 atm. If the process is adiabatic and the fuel- air mixture behaves as a diatomic ideal gas, (a) by what factor does the volume change and (b) by what factor does the temperature change? (c) Assuming that the compression starts with 0.0160 mol of gas at \(27.0^{\circ} \mathrm{C},\) find the values of \(Q, W,\) and \(\Delta E_{\text {int }}\) that characterize the process.

(a) Show that the speed of sound in an ideal gas is $$v=\sqrt{\frac{\gamma R T}{M}}$$ where \(M\) is the molar mass. Use the general expression for the speed of sound in a fluid from Section \(17.1,\) the definition of the bulk modulus from Section \(12.4,\) and the result of Problem 59 in this chapter. As a sound wave passes through a gas, the compressions are either so rapid or so far apart that thermal conduction is prevented by a negligible time interval or by effective thickness of insulation. The compressions and rarefactions are adiabatic. (b) Compute the theoretical speed of sound in air at \(20^{\circ} \mathrm{C}\) and compare it with the value in Table \(17.1 .\) Take \(M=\) \(28.9 \mathrm{g} / \mathrm{mol} .\) (c) Show that the speed of sound in an ideal gas is $$v=\sqrt{\frac{\gamma k_{\mathrm{B}} T}{m}}$$ where \(m\) is the mass of one molecule. Compare it with the most probable, average, and rms molecular speeds.

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