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In a constant-volume process, \(209 \mathrm{J}\) of energy is transferred by heat to 1.00 mol of an ideal monatomic gas initially at 300 K. Find (a) the increase in internal energy of the gas, (b) the work done on it, and (c) its final temperature.

Short Answer

Expert verified
The internal energy of the gas increases by 209 J, work done on the gas is 0 J, and to find out the final temperature, calculate the change in temperature using the equation \( \Delta U = n C_v \Delta T \).

Step by step solution

01

Understanding Ischoric Process

In an isochoric process, the volume of the system remains constant. Therefore, it implies that no work is done on the system, since work done \(W = P \Delta V\), where \( P \) is pressure and \( \Delta V = 0\) for isochoric processes.
02

Identify the Equations to use for the Problem

We will use the first law of thermodynamics which is \( \Delta U = Q - W \). We know that the work done \( W = 0 \) for constant volume. And the heat supplied \( Q = 209 J\). So the increase in internal energy will be \( \Delta U = Q - W = Q \).
03

Calculation of Internal Energy Increase

By substituting the heat supply value into the above expression, we get \( \Delta U = 209 J \). So, the increase in internal energy of the gas is 209 J.
04

Calculation of Work done on the Gas

Since there is no volume change for the gas, therefore, the work done on the gas is \( W = P \Delta V = 0 J \).
05

Calculation of Final Temperature

For a monoatomic ideal gas, the change in internal energy can be calculated with \( \Delta U = n C_v \Delta T \). Here, \( n = 1.00 mol\), \( C_v = 3/2 R = 12.47 J/K\cdot mol \) (R is the gas constant, R = 8.314 J/K.mol), and \( \delta U = 209 J\). Solving for \( \Delta T \), we can find the change in temperature. Adding this change in temperature to the initial temperature will yield the final temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Internal Energy
When we talk about the internal energy of a system, we're referring to the total amount of energy contained within it. This encompasses both the kinetic energy of the particles that are moving around and the potential energy that results from the interactions between these particles. In the context of a monatomic gas, the internal energy is largely kinetic, since there are no chemical bonds between atoms.

In our exercise, when heat is transferred to the gas at constant volume, the internal energy increases by the same amount as the heat provided, as no work is done on the gas. The reason for this is that internal energy can be thought of as the 'total change account' for energy within a closed system.
Ideal Gas Law
The ideal gas law is a critical foundation in thermodynamics and describes the relationship between pressure (P), volume (V), temperature (T), and the number of moles (n) of a gas. Mathematically, it's expressed as PV = nRT, where R is the universal gas constant.

While the ideal gas law was not directly applied in this problem, understanding it helps us to know that for a fixed amount of gas at constant volume, an increase in temperature will lead to an increase in pressure. It’s an excellent way to predict the behavior of gases under various conditions, despite the fact that in this scenario volume and moles are constant.
First Law of Thermodynamics
The first law of thermodynamics, also known as the law of energy conservation, states that energy cannot be created or destroyed in an isolated system. The total energy change (ΔU) in a system is equal to the heat (Q) added to the system minus the work (W) done by the system on the surroundings, which can be expressed as ΔU = Q - W.

In the case of our isochoric process, since the volume does not change, no work is done on or by the system, so all of the heat added goes into increasing the internal energy of the gas. Understanding this law is essential for solving thermodynamic problems and predicting system behavior because it relates heat and work – two fundamental energy transfer modes – to the state of a system.
Monatomic Gas
A monatomic gas is a gas which is composed of single atoms, like the noble gases helium, neon, or argon. These gases are ideal for studying basic thermodynamic processes since they don't have rotational or vibrational modes—only translational kinetic energy.

In the exercise, we dealt with a monatomic ideal gas, meaning that it follows the ideal gas law and the specific heats are constants. This simplification allows us to directly relate the increase in internal energy to the increase in temperature. For monatomic gases, the molar specific heat at constant volume, Cv, is (3/2)R, which can be used to calculate the final temperature after the heat transfer.
Heat Transfer
The term heat transfer refers to the movement of energy from one place to another as a result of a temperature difference. It can occur via conduction, convection, and radiation. In thermodynamics, heat transfer is often discussed in terms of how it affects the energy state of a system.

In the described exercise, heat is transferred to the gas, raising its internal energy. The amount of heat transferred is quantified as 209 J. It’s essential to distinguish that heat is a form of energy in transit and not a static property of a system. Whenever there is a temperature difference, heat transfer can occur, altering internal energy, as seen in this isochoric process.

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Most popular questions from this chapter

Twenty particles, each of mass \(m\) and confined to a volume V, have various speeds: two have speed \(v\); three have speed \(2 v ;\) five have speed \(3 v ;\) four have speed \(4 v ;\) three have speed \(5 v ;\) two have speed \(6 v ;\) one has speed \(7 v .\) Find (a) the average speed, (b) the rms speed, (c) the most probable speed, (d) the pressure the particles exert on the walls of the vessel, and (e) the average kinetic energy per particle.

A vessel contains \(1.00 \times 10^{4}\) oxygen molecules at \(500 \mathrm{K}\) (a) Make an accurate graph of the Maxwell-Boltzmann speed distribution function versus speed with points at speed intervals of \(100 \mathrm{m} / \mathrm{s}\). (b) Determine the most probable speed from this graph. (c) Calculate the average and rms speeds for the molecules and label these points on your graph. (d) From the graph, estimate the fraction of molecules with speeds in the range \(300 \mathrm{m} / \mathrm{s}\) to \(600 \mathrm{m} / \mathrm{s}\)

During the compression stroke of a certain gasoline engine, the pressure increases from 1.00 atm to 20.0 atm. If the process is adiabatic and the fuel- air mixture behaves as a diatomic ideal gas, (a) by what factor does the volume change and (b) by what factor does the temperature change? (c) Assuming that the compression starts with 0.0160 mol of gas at \(27.0^{\circ} \mathrm{C},\) find the values of \(Q, W,\) and \(\Delta E_{\text {int }}\) that characterize the process.

A sealed cubical container \(20.0 \mathrm{cm}\) on a side contains three times Avogadro's number of molecules at a temperature of \(20.0^{\circ} \mathrm{C}\). Find the force exerted by the gas on one of the walls of the container.

A certain molecule has \(f\) degrees of freedom. Show that an ideal gas consisting of such molecules has the following properties: (1) its total internal energy is \(f n R T / 2 ;(2)\) its molar specific heat at constant volume is \(f R / 2 ; \quad(3)\) its molar specific heat at constant pressure is \((f+2) R / 2\) (4) its specific heat ratio is \(\gamma=C_{P} / C_{V}=(f+2) / f\)

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