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In Mostar, Bosnia, the ultimate test of a young man's courage once was to jump off a 400 -year-old bridge (now destroyed) into the River Neretva, \(23.0 \mathrm{m}\) below the bridge. (a) How long did the jump last? (b) How fast was the diver traveling upon impact with the water? (c) If the speed of sound in air is \(340 \mathrm{m} / \mathrm{s}\), how long after the diver took off did a spectator on the bridge hear the splash?

Short Answer

Expert verified
a) The jump lasted approximately 2.17 seconds. b) The diver was traveling at approximately 21.3 m/s upon impact. c) A spectator on the bridge would hear the splash approximately 2.24 seconds after the diver took off.

Step by step solution

01

Determine the time for the jump

We can use the free fall equation to determine how long the jump lasted. The equation is as follows \(d = 0.5gt^2\) where \(d = 23.0m\) is the distance jumped, \(g = 9.8m/s^2\) is the acceleration due to gravity, and \(t\) is the time we are trying to determine. Solving for \(t\), we get \(t = \sqrt{(2d) / g}\).
02

Determine the velocity upon impact

We can use the equation \(v = gt\) to find the final velocity upon impact. Here, \(v\) is the final velocity, \(g = 9.8m/s^2\) is the acceleration due to gravity and \(t\) is the time of the fall that we calculated in the previous step.
03

Determine the time the sound of the splash reaches the spectator

To find this, we need to account both for the time the sound of the splash reaches the spectator after the diver hits the water and the time taken for the diver to hit the water. We know the speed of sound in air is \(340m/s\). Hence, the time taken for the sound to reach the spectator is \(d / v = 23m / 340m/s\). Hence, the total time is the time of the free fall plus the time for the sound to reach the spectator.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics in Free Fall
When studying the motion of objects in free fall, we dip into the fascinating world of kinematics, a branch of classical mechanics. Kinematics is the study of motion without considering the forces that cause that motion.

In the context of a person jumping from a bridge, as in the problem from Mostar, Bosnia, we consider the motion to be one dimensional—straight down. The primary kinematic equation for free fall is a beautiful display of simplicity: \(d = 0.5gt^2\). Here, \(d\) is the distance fallen, \(g\) is the gravitational acceleration, and \(t\) is the time of the fall. This equation reflects the tenet that the object accelerates due to gravity alone, with no initial velocity since the jumper starts from rest.

Applying kinematics allows us to solve for the duration of the jumper's fall, answering 'how long' the experience lasts—precisely what we are after in the initial part of the exercise. The ability to predict the outcome, like the time to hit the water, is the power kinematics places in our hands.
The Role of Gravitational Acceleration
Gravitational acceleration, \(g\), is a constant that represents the acceleration due to Earth's gravity. Near the surface of the Earth, it has an average value of \(9.8 \text{m/s}^2\). This value is critical in physics, especially in the realm of free fall, because it tells us how quickly an object's velocity increases as it falls.

In our exercise, when the young man leaps into the air, his velocity starts at zero, but as he falls, his velocity increases due to gravitational acceleration—resulting in a faster descent as time progresses. To calculate the velocity upon impact with the water—key for understanding the ferocity of his meeting with the river—we use another kinematic equation: \(v = gt\).

This equation allows us to calculate the final velocity right before the splash, demonstrating the climactic end of the acceleration period during free fall. This final velocity is crucial for assessing potential outcomes upon the diver making contact with the water.
Sound Propagation After the Dive
The concept of sound propagation relates to the way sound waves travel through a medium—in this case, air. Sound moves at different speeds depending on the medium it is passing through, with a typical speed in air of \(340 \text{m/s}\) under standard conditions.

In our scenario, a spectator is waiting for the auditory confirmation of the diver hitting the water. The sound of the splash travels upwards after the diver's impact, and the time it takes for the sound to reach the spectator's ears is determined by the sound's speed and the distance it needs to cover. The calculation for the time the sound takes to travel is the distance to the spectator divided by the speed of sound, \(d / v\).

Understanding sound propagation adds depth to our exercise, allowing students to grasp that observation involves more than visuals—it takes time for sound to travel from the event (the splash) to the observer on the bridge. Sound propagation completes the picture of what the spectators experience and is an intriguing blend of kinematics and wave physics.

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Most popular questions from this chapter

The position of a particle moving along the \(x\) axis varies in time according to the expression \(x=3 t^{2},\) where \(x\) is in meters and \(t\) is in seconds. Evaluate its position (a) at \(t=3.00 \mathrm{s}\) and (b) at \(3.00 \mathrm{s}+\Delta t\). (c) Evaluate the limit of \(\Delta x / \Delta t\) as \(\Delta t\) approaches zero, to find the velocity at \(t=3.00 \mathrm{s}\).

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