/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 A jet plane lands with a speed o... [FREE SOLUTION] | 91Ó°ÊÓ

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A jet plane lands with a speed of \(100 \mathrm{m} / \mathrm{s}\) and can accelerate at a maximum rate of \(-5.00 \mathrm{m} / \mathrm{s}^{2}\) as it comes to rest.(a) From the instant the plane touches the runway, what is the minimum time interval needed before it can come to rest? (b) Can this plane land on a small tropical island airport where the runway is \(0.800 \mathrm{km}\) long?

Short Answer

Expert verified
The minimum time interval needed for the jet to come to rest is 20 seconds. Unfortunately, the jet cannot land on the small tropical island airport where the runway is 0.800 km long because it needs a stopping distance of 1 km.

Step by step solution

01

Compute the Time to Come to Rest

First, let's calculate the time it takes for the jet plane to come to rest. We know that it lands with a speed of \(100 \mathrm{m} / \mathrm{s}\), and can decelerate at a rate of \(-5.00 \mathrm{m} / \mathrm{s}^{2}\). We can use the first equation of motion \(v = u + at\). Rearranging for \(t\), we get \(t = (v - u) / a\). Substituting in the given values, \(t = (0 - 100) / -5 = 20\) seconds. Thus, it will take 20 seconds for the plane to stop after touching the runway.
02

Compute the Distance Covered to Come to Rest

Now, we need to determine if the plane can stop within the runway length. For this, we'll calculate the distance the plane covers in 20 seconds. We use the second equation of motion \(s = ut + 0.5at^2\). Substituting the given values, we get \(s = (100*20) + 0.5*(-5)*(20)^2\). Upon calculating, we find that \(s = 2000 - 1000 = 1000\) m or 1 km.
03

Comparison with Runway Length

The next step is to compare the distance the plane takes to stop with the runway length. The length of the runway is given as 0.800 km. Since the plane requires a distance of 1 km to stop, but the runway is only 0.800 km long, unfortunately, the plane cannot land at this airport.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Jet Plane Landing
When a jet plane lands, the process is meticulously calculated to ensure the safety of all onboard and the success of the landing. The jet lands with a high speed; in our case study, it touches down at 100 meters per second. However, as soon as the wheels touch the ground, the plane must quickly decelerate to come to a stop. This is achieved through reverse thrust mechanisms and the plane's natural engineering allowing negative acceleration, or deceleration.
The landing scenario is often studied under kinematics to understand how quickly and effectively a plane can stop. It's essential that pilots are trained to manage speed and distance accurately, especially when landing in smaller airports that might have shorter runways.
Understanding landing dynamics involves knowing how speed, acceleration, and distance interact to bring the plane safely to rest.
Equations of Motion
The equations of motion are fundamental in physics, providing a framework to predict the future position and velocity of an object. In the case of a landing jet plane, the primary equations used are:
  • The first equation of motion: \( v = u + at \), where \( v \) is the final velocity, \( u \) is the initial velocity, \( a \) is the acceleration, and \( t \) is the time.
  • The second equation of motion: \( s = ut + 0.5at^2 \), where \( s \) is the distance covered during the time \( t \).

When the plane lands, its initial speed (\( u \)) is known, as well as its deceleration rate (\( a \)). To find the time it takes to stop (\( t \)), we set the final velocity (\( v \)) to zero, since the objective is to stop the plane.
The calculation of the distance covered (\( s \)) while coming to a halt is crucial to determine whether the runway length is sufficient. Using these equations allows us to predict and ensure safety when the plane lands.
Deceleration
Deceleration is the process of slowing down or reducing speed. For a landing jet plane, deceleration is a vital phase. Defined as negative acceleration, it shows how quickly a jet's speed decreases until it stops. This deceleration rate must be controlled accurately for maximum safety.
Typically, aircraft are designed with specific deceleration capabilities. In our scenario, the maximum deceleration rate is \(-5.00 \mathrm{m} / \mathrm{s}^2\). This negative sign indicates slowing down.
Every aspect of deceleration must be calculated precisely. If a plane needs to decelerate too quickly, it might not be safe for passengers; too slowly, and it might overrun the runway.
  • Maximum deceleration rate = the highest rate at which the aircraft can safely slow down.
  • The condition of runways and weather also plays a role in how effectively a plane can decelerate.

Understanding deceleration helps in comprehending whether an airplane can land on a given runway length. The faster a plane can decelerate, the shorter runway it needs to stop.

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