/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 A 60.000 -cm guitar string under... [FREE SOLUTION] | 91Ó°ÊÓ

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A 60.000 -cm guitar string under a tension of \(50.000 \mathrm{N}\) has a mass per unit length of \(0.10000 \mathrm{g} / \mathrm{cm} .\) What is the highest resonant frequency that can be heard by a person capable of hearing frequencies up to \(20000 \mathrm{Hz} ?\)

Short Answer

Expert verified
The highest resonant frequency that can be heard by a person capable of hearing frequencies up to \( 20000 Hz \) is approximately \( 19947 Hz \).

Step by step solution

01

Convert units and Prepare the Variables

Firstly, convert the given variables to SI units for consistency. The length of the string, \( L \), is given as 60.000 cm, converted to meters is 0.60000 m. The tension in the string, \( F \), is given as 50.000 N, which is already in SI units, so no need to convert. The mass per unit length, \( \mu \), is given as 0.10000 g/cm, converted to SI units (kg/m) is 0.0010000 kg/m.
02

Calculation of the wave speed

Now, using the formula \( v = \sqrt {F / \mu} \), we can calculate the wave speed. \( v = \sqrt {(50.000 N) / (0.0010000 kg/m)} = 223.61 m/s \).
03

Determination of the fundamental frequency

The formula that relates fundamental frequency, wave speed and length of the string is \( f_1 = v / (2L) \). So \( f_1 = (223.61 m/s) / (2*0.60000 m) =186.34 Hz \). This is the fundamental frequency.
04

Calculation of the highest resonant frequency

Now we need to figure out the highest resonant frequency someone can hear. This would be a harmonic of the fundamental frequency \( f_1 \). We know that the highest audible frequency for humans is typically 20000 Hz. We divide this frequency by the fundamental frequency to see how many harmonics are possible, i.e. \( 20000 Hz / 186.34 Hz = 107.32 \). Since we can't have part of a harmonic, we round down to the nearest whole number, in this case, 107. The highest resonant frequency heard by a person capable of hearing frequencies up to \( 20000 Hz \) will therefore be \( 107*186.34 Hz = 19947 Hz \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Speed
Understanding wave speed is fundamental to solving various problems in physics, especially those related to waves on strings. Wave speed, denoted as 'v', is defined as the speed at which a wave travels through a medium. The formula used to calculate wave speed on a string is given by the equation: \[\begin{equation} v = \frac{F}{\rho} = \frac{F}{\frac{m}{L}} = \frac{F}{\frac{\text{mass per unit length} *L}{L}} = \frac{F}{\text{mass per unit length}} \end{equation}\]Here, \( v \) is the wave speed, \( F \) is the string tension, and \( \rho \) is the mass density (not to be confused with mass per unit length \( \rho = \frac{m}{L} \)within this context).

The faster the wave speed, the quicker the wave travels through the string. Wave speed is crucial for determining the fundamental frequency and harmonics of a string, as it directly influences their values.
Fundamental Frequency
The fundamental frequency, often denoted as \( f_1 \), is the lowest frequency of vibration of a standing wave. It's the first harmonic and is the tone we typically associate with the pitch of a musical note played on a stringed instrument. To find the fundamental frequency of a wave on a string, we use the formula:\[\begin{equation} f_1 = \frac{v}{2L} \end{equation}\]where \( v \) is the wave speed, and \( L \) is the length of the string. This equation states that the fundamental frequency is dependent on both the speed of the wave and the length of the string. A longer string or a slower wave speed results in a lower fundamental frequency, whereas a shorter string or faster wave speed results in a higher fundamental frequency.
Harmonics
Harmonics are integral multiples of the fundamental frequency, \(f_1\), of a string. They represent the various modes of vibration that a string can sustain. The frequency of the nth harmonic is the fundamental frequency times n, expressed mathematically as:\[\begin{equation} f_n = n \times f_1 \end{equation}\]The term 'harmonic' comes from music, where different harmonics create different musical notes. In terms of resonance, these harmonics show at which frequencies the string will naturally vibrate. The highest audible harmonic is determined by dividing the maximum frequency a human ear can detect by the fundamental frequency and using the largest whole number multiple below this value.
Mass Per Unit Length
Mass per unit length, \( \mu \) in scientific notation, is a property of a string that affects how it vibrates. It is determined by dividing the mass of the string by its length. A greater mass per unit length means the string is denser and generally vibrates slower compared to a lighter string. This property is key for calculating the wave speed on a string and thus affects the frequencies at which the string resonates. The equation for wave speed incorporating mass per unit length is given by:\[\begin{equation} v = \frac{F}{\mu} \end{equation}\]Understanding mass per unit length is essential in musical instrument design, as it affects the pitch and timbre of the notes produced.
String Tension
String tension, denoted as \( F \), is the force exerted along the length of a string. It's an influential factor in the dynamics of wave propagation along the string. In general, increasing the tension in a string raises the speed of waves traveling through it, thereby increasing the frequency of standing waves, which includes both the fundamental frequency and the harmonics. Therefore, tension is directly proportional to the square of the wave speed, as shown in the wave speed formula:\[\begin{equation} v = \sqrt{F / \mu} \end{equation}\]where \( F \) is the tension and \( \mu \) is the mass per unit length. By manipulating the tension, musicians can tune their instruments to produce the desired pitch.

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Most popular questions from this chapter

A series of pulses, each of amplitude \(0.150 \mathrm{m},\) is sent down a string that is attached to a post at one end. The pulses are reflected at the post and travel back along the string without loss of amplitude. What is the net displacement at a point on the string where two pulses are crossing, (a) if the string is rigidly attached to the post? (b) if the end at which reflection occurs is free to slide up and down?

When beats occur at a rate higher than about 20 per second, they are not heard individually but rather as a steady hum, called a combination tone. The player of a typical pipe organ can press a single key and make the organ produce sound with different fundamental frequencies. She can select and pull out different stops to make the same key for the note \(\mathrm{C}\) produce sound at the following frequencies: \(65.4 \mathrm{Hz}\) from a so-called eight-foot pipe; \(2 \times 65.4=\) \(131 \mathrm{Hz}\) from a four-foot pipe; \(3 \times 65.4=196 \mathrm{Hz}\) from a two-and-two-thirds-foot pipe; \(4 \times 65.4=262 \mathrm{Hz}\) from a two-foot pipe; or any combination of these. With notes at low frequencies, she obtains sound with the richest quality by pulling out all the stops. When an air leak develops in one of the pipes, that pipe cannot be used. If a leak occurs in an eight-foot pipe, playing a combination of other pipes can create the sensation of sound at the frequency that the eight-foot pipe would produce. Which sets of stops, among those listed, could be pulled out to do this?

The windpipe of one typical whooping crane is \(5.00 \mathrm{ft}\) long. What is the fundamental resonant frequency of the bird's trachea, modeled as a narrow pipe closed at one end? Assume a temperature of \(37^{\circ} \mathrm{C}.\)

The wave function for a standing wave is given in Equation 18.3 as \(y=2 A \sin k x \cos \omega t .\) (a) Rewrite this wave function in terms of the wavelength \(\lambda\) and the wave speed \(v\) of the wave. (b) Write the wave function of the simplest standing wave vibration of a stretched string of length \(L\). (c) Write the wave function for the second harmonic. (d) Generalize these results and write the wave function for the \(n\)th resonance vibration.

Standing Waves in Rods and Membranes An aluminum rod \(1.60 \mathrm{m}\) long is held at its center. It is stroked with a rosin-coated cloth to set up a longitudinal vibration. The speed of sound in a thin rod of aluminum is\(5100 \mathrm{m} / \mathrm{s} .\) (a) What is the fundamental frequency of the waves established in the rod? (b) What harmonics are set up in the rod held in this manner? (c) What If? What would be the fundamental frequency if the rod were made of copper, in which the speed of sound is \(3560 \mathrm{m} / \mathrm{s} ?\)

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