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The wave function for a standing wave is given in Equation 18.3 as \(y=2 A \sin k x \cos \omega t .\) (a) Rewrite this wave function in terms of the wavelength \(\lambda\) and the wave speed \(v\) of the wave. (b) Write the wave function of the simplest standing wave vibration of a stretched string of length \(L\). (c) Write the wave function for the second harmonic. (d) Generalize these results and write the wave function for the \(n\)th resonance vibration.

Short Answer

Expert verified
The basic wave function: \(y=2A \sin (\frac{2\pi}{\lambda}x) \cos (\frac{2\pi v}{\lambda}t)\)\n For the simple standing wave: \(y=2A \sin (\frac{\pi}{L}x) \cos (\frac{\pi v}{L}t)\)\n For the second harmonic: \(y=2A \sin (\frac{2\pi}{L}x) \cos (\frac{2\pi v}{L}t)\)\n For the \(n\)th harmonic: \(y=2A \sin (\frac{n\pi}{L}x) \cos (\frac{n\pi v}{L}t)\).

Step by step solution

01

Convert wave function to terms of wavelength and wave speed

The wave number \(k\) is related to the wavelength wheren \(k=\frac{2\pi}{\lambda}\). Frequency \(f\) is given by \(f=\frac{v}{\lambda}\). For a wave, the angular frequency \(\omega\) is related to frequency \(f\) by \(\omega = 2\pi f\), so that \(\omega = 2\pi (\frac{v}{\lambda}) = \frac{2\pi v}{\lambda}\). Substituting these in \(y=2 A \sin Kx \cos \omega t\) we get, \(y=2A \sin (\frac{2\pi}{\lambda}x) \cos (\frac{2\pi v}{\lambda}t)\).
02

Finding the wave function for a basic standing wave in a stretched string

The simplest standing wave is the one with only one antinode. This happens when the wavelength is twice the length of the string, \(\lambda = 2L\). Substituting \(\lambda\) in the earlier equation, the function becomes, \(y=2A \sin (\frac{\pi}{L}x) \cos (\frac{\pi v}{L}t)\).
03

Finding the wave function for the second harmonic

The second harmonic of a standing wave on a string fixed at both ends happens when the wavelength is same as the length of the string, \(\lambda = L\). Substituting this in the earlier equation, the function becomes, \(y=2A \sin (\frac{2\pi}{L}x) \cos (\frac{2\pi v}{L}t)\).
04

Generalize the wave function for the \(n\)th resonance vibration

For any \(n\)th harmonic on a string fixed at both ends, the wavelength is calculated by \(\lambda = \frac{2L}{n}\). Substituting \(\lambda\) in the function from step 1, the wave function for the \(n\)th harmonic becomes \(y=2A \sin (\frac{n\pi}{L}x) \cos (\frac{n\pi v}{L}t)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Function
The wave function is a mathematical tool used in physics to describe the behavior of waves. It encapsulates all the information about the wave's shape and motion over time. In the case of a standing wave, as presented in the textbook exercise, the wave function is given by the equation \(y=2 A \sin kx \cos \omega t\). This function demonstrates the propagation of a wave in terms of its amplitude \(A\), wave number \(k\), and angular frequency \(\omega\).

In a learning environment, it's essential to grasp how these constituents—amplitude, wave number, and angular frequency—affect the overall shape and movement of the wave. By manipulating the equation, we expose relationships with physical properties like wavelength \(\lambda\) and wave speed \(v\), which provide a clearer picture of wave behavior in different mediums.
Harmonics in Standing Waves
Harmonics in standing waves are integral to understanding musical instruments and many types of oscillations. Each harmonic represents a resonance frequency at which the system naturally prefers to vibrate. When a stretched string is plucked, it doesn't just vibrate at one frequency—the string supports a whole series of standing wave patterns, known as harmonics or overtones.

The simplest standing wave has only one antinode and is the first harmonic or fundamental frequency. The second harmonic exhibits two anti-nodes and is the first overtone. As demonstrated in the textbook solution, for the second harmonic, the string's length equals the wavelength of the wave, \(\lambda = L\). The general pattern continues wherein the \(n\)th harmonic on a string fixed at both ends has a wavelength \(\lambda = \frac{2L}{n}\), with \(n\) representing the harmonic number.
Wavelength and Wave Speed
In the realm of waves, wavelength \(\lambda\) is the distance between two consecutive points that are in phase, such as crest-to-crest or trough-to-trough. Wave speed \(v\), on the other hand, is how fast the wave travels through a medium. The relationship between wavelength, wave speed, and frequency is pivotal - it's described by the equation \(v=f\lambda\), where \(f\) is the frequency of the wave.

Understanding how altering either the wavelength or the speed of the wave impacts the frequency is a critical piece of the puzzle. In physical sciences, this fundamental concept underpins a wide range of phenomena from the pitch of a musical note to the color of light in optical systems.
Resonance Vibration
Resonance vibration occurs when an object oscillates with a greater amplitude at certain frequencies, known as the object's natural frequencies. These are the frequencies at which the system naturally oscillates in resonance, resulting in standing waves. Resonance can be seen in everyday life, from the strings of a guitar to the destructive potential in bridges and buildings.

Mathematically, as presented in the textbook exercise, the wave function adjusted for the \(n\)th resonance vibration of a string fixed at both ends becomes \(y=2A \sin (\frac{n\pi}{L}x) \cos (\frac{n\pi v}{L}t)\) where \(n\) represents the mode of vibration. Each mode corresponds to a specific pattern and frequency of the standing wave, illustrating the rich tapestry of possible movements a vibrating object can undertake.

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Most popular questions from this chapter

Two train whistles have identical frequencies of \(180 \mathrm{Hz}\) When one train is at rest in the station and the other is moving nearby, a commuter standing on the station platform hears beats with a frequency of 2.00 beats/s when the whistles sound at the same time. What are the two possible speeds and directions that the moving train can have?

Two waves are described by the wave functions $$ y_{1}(x, t)=5.0 \sin (2.0 x-10 t) $$ and $$ y_{2}(x, t)=10 \cos (2.0 x-10 t) $$ where \(y_{1}, y_{2},\) and \(x\) are in meters and \(t\) is in seconds. Show that the wave resulting from their superposition is also sinusoidal. Determine the amplitude and phase of this sinusoidal wave.

An air column in a glass tube is open at one end and closed at the other by a movable piston. The air in the tube is warmed above room temperature, and a \(384-\mathrm{Hz}\) tuning fork is held at the open end. Resonance is heard when the piston is \(22.8 \mathrm{cm}\) from the open end and again when it is \(68.3 \mathrm{cm}\) from the open end. (a) What speed of sound is implied by these data? (b) How far from the open end will the piston be when the next resonance is heard?

A shower stall measures \(86.0 \mathrm{cm} \times 86.0 \mathrm{cm} \times 210 \mathrm{cm} .\) If you were singing in this shower, which frequencies would sound the richest (because of resonance)? Assume that the stall acts as a pipe closed at both ends, with nodes at opposite sides. Assume that the voices of various singers range from \(130 \mathrm{Hz}\) to \(2000 \mathrm{Hz}\). Let the speed of sound in the hot shower stall be \(355 \mathrm{m} / \mathrm{s}.\)

A string fixed at both ends and having a mass of \(4.80 \mathrm{g},\) a length of \(2.00 \mathrm{m},\) and a tension of \(48.0 \mathrm{N}\) vibrates in its second \((n=2)\) normal mode. What is the wavelength in air of the sound emitted by this vibrating string?

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