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Transverse waves travel with a speed of \(20.0 \mathrm{m} / \mathrm{s}\) in a string under a tension of \(6.00 \mathrm{N} .\) What tension is required for a wave speed of \(30.0 \mathrm{m} / \mathrm{s}\) in the same string?

Short Answer

Expert verified
The tension required for a wave speed of \(30.0 m/s\) in the same string is \(13.5 N\).

Step by step solution

01

Write down the given values and formula

Given that the initial wave speed \(v_{1} = 20 m/s\), tension \(F_{1} = 6 N\) and the final wave speed \(v_{2} = 30 m/s\). We need to find the final tension \(F_{2}\). The wave speed formula for a string under tension is given by \(v= \sqrt{\frac{F}{\mu}}\).
02

Set up the ratio using the wave speed formula

Using the wave speed formulas: \(v_{1}= \sqrt{\frac{F_{1}}{\mu}}\) and \(v_{2}= \sqrt{\frac{F_{2}}{\mu}}\), we can create a ratio: \(\frac{v_{2}}{v_{1}} = \frac{\sqrt{\frac{F_{2}}{\mu}}}{\sqrt{\frac{F_{1}}{\mu}}}\). Notice that \(\mu\) will cancel out in the ratio, because it remains constant.
03

Solve the ratio for the unknown final tension

Substitute the given wave speeds and initial tension into the ratio: \(\frac{30}{20} = \frac{\sqrt{F_{2}}}{\sqrt{6}}\). Squaring both sides to eliminate the square root gives: \((\frac{30}{20})^{2} = \frac{F_{2}}{6}\). Therefore, \(F_{2} = 6 \cdot (\frac{30}{20})^{2}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Transverse Waves
Transverse waves are fascinating phenomena in physics where the particle displacement is perpendicular to the direction of wave propagation. Think of a wave on a string: as the wave travels horizontally, the particles of the string move up and down. This perpendicular motion to the direction of travel is the key characteristic of transverse waves.

These waves can be observed in various forms, from the ripples on a pond to electromagnetic waves like light. In the context of our exercise, the string represents the medium through which the transverse waves are traveling. It is important to visualize the up-and-down movement of the string's particles, while the wave itself moves horizontally across the string. Understanding this fundamental behavior is crucial for grasping further concepts like wave speed and wave tension.
Exploring Wave Tension
Wave tension plays a significant role in determining the behavior and speed of a wave traveling through a medium. Imagine pulling a string tautly; the tension is the force you're applying to keep it tight. In physics, this tension greatly influences how fast a wave can move along the string.

For a given wave, the higher the tension in the string, the faster the wave will travel. This is because greater tension reduces the wave's reliance on inertia and allows the energy to move more efficiently. Therefore, when analyzing problems related to wave speed, like the one in our exercise, understanding the relationship between tension and wave speed is essential. If you increase the tension, you're likely to increase the speed of the wave, provided other factors remain constant.
Using the Wave Formula
The wave formula is a valuable tool for anyone solving problems involving wave speed and tension. It is expressed as: \[ v = \sqrt{\frac{F}{\mu}} \]where:
  • \(v\) is the wave speed,
  • \(F\) represents the tension in the string, and
  • \(\mu\) is the linear mass density of the string (mass per unit length).

This formula shows that the wave speed is proportional to the square root of the tension divided by the linear mass density. One critical aspect to note here is that the linear mass density \(\mu\) remains constant if we're dealing with the same string or material. This constancy allows us to compare different scenarios effectively, such as when the wave speed changes while the medium remains unchanged, as illustrated in the exercise.

By setting up ratios of wave speeds and tensions, you can solve for unknowns, realizing that wave speed increases when tension is increased, given a constant linear mass density.
Mastering Physics Problem Solving
Solving physics problems involving wave mechanics requires a strategic approach. The key steps often include understanding the problem, identifying known and unknown values, and applying the appropriate formulas. This systematic method is quite evident in solving our current exercise.

First, it is essential to clearly outline what is given and what is required. In this case, we start by noting the initial and final wave speeds and the initial tension, and then use the wave formula to find the unknown final tension. Next, setting up a ratio of the known and unknown variables helps simplify and solve the problem effectively, leveraging the concept that certain variables, like linear mass density, often cancel out in similar situations.

Critical thinking and analytical skills are pivotal in assessing the physics problem effectively. Breaking down each step and ensuring clarity in the solution pathway allows for better understanding and mastery of wave mechanics and other physics-related problems.

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Most popular questions from this chapter

(a) Show that the function \(y(x, t)=x^{2}+v^{2} t^{2}\) is a solution to the wave equation. (b) Show that the function in part (a) can be written as \(f(x+v t)+g(x-v t),\) and determine the functional forms for \(f\) and \(g\). (c) What If? Repeat parts (a) and (b) for the function \(y(x, t)=\sin (x) \cos (v t)\).

A telephone cord is \(4.00 \mathrm{m}\) long. The cord has a mass of \(0.200 \mathrm{kg} .\) A transverse pulse is produced by plucking one end of the taut cord. The pulse makes four trips down and back along the cord in 0.800 s. What is the tension in the cord?

The wave function for a traveling wave on a taut string is (in SI units) $$y(x, t)=(0.350 \mathrm{m}) \sin (10 \pi t-3 \pi x+\pi / 4)$$ (a) What are the speed and direction of travel of the wave? (b) What is the vertical position of an element of the string at \(t=0, x=0.100 \mathrm{m} ?\) (c) What are the wavelength and frequency of the wave? (d) What is the maximum magnitude of the transverse speed of the string?

A string of length \(L\) consists of two sections. The left half has mass per unit length \(\mu=\mu_{0} / 2,\) while the right has a mass per unit length \(\mu^{\prime}=3 \mu=3 \mu_{0} / 2 .\) Tension in the string is \(T_{0} .\) Notice from the data given that this string has the same total mass as a uniform string of length \(L\) and mass per unit length \(\mu_{0}\). (a) Find the speeds \(v\) and \(v^{\prime}\) at which transverse pulses travel in the two sections. Express the speeds in terms of \(T_{0}\) and \(\mu_{0},\) and also as multiples of the speed \(v_{0}=\left(T_{0} / \mu_{0}\right)^{1 / 2} .\) (b) Find the time interval required for a pulse to travel from one end of the string to the other. Give your result as a multiple of \(\Delta t_{0}=L / v_{0}\).

A taut rope has a mass of \(0.180 \mathrm{kg}\) and a length of \(3.60 \mathrm{m}\) What power must be supplied to the rope in order to generate sinusoidal waves having an amplitude of \(0.100 \mathrm{m}\) and a wavelength of \(0.500 \mathrm{m}\) and traveling with a speed of \(30.0 \mathrm{m} / \mathrm{s} ?\)

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