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A student taking a quiz finds on a reference sheet the two equations $$f=1 / T \text { and } v=\sqrt{T / \mu}$$ She has forgotten what \(T\) represents in each equation. (a) Use dimensional analysis to determine the units required for \(T\) in each equation. (b) Identify the physical quantity each \(T\) represents.

Short Answer

Expert verified
In the equation \(f=1 / T\), \(T\) represents Time period with units of seconds (sec). In the equation \(v=\sqrt{T / \mu}\), \(T\) represents Tension with units of square meters (m^2).

Step by step solution

01

Identifying the Units for \(f=1 / T\)

First, consider the equation \(f=1 / T\). Here \(f\) represents frequency. Frequency is measured in Hertz (Hz) or sec^-1. Setting the dimensions on both sides equal to each other gives \(T\) units as seconds (sec).
02

Identifying the Physical Quantity for \(T\) in \(f=1 / T\)

Based on the identified units (seconds), \(T\) in the equation \(f=1 / T\) represents Time period.
03

Identifying the Units for \(v=\sqrt{T / \mu}\)

Next, consider the equation \(v=\sqrt{T / \mu}\). Here \(v\) represents velocity which is measured in meters per second (m/s), and \(\mu\) represents mass per unit length, measured in kilograms per meter (Kg/m). The square root makes \(T\) to have units of square meters (m^2).
04

Identifying the Physical Quantity for \(T\) in \(v=\sqrt{T / \mu}\)

Given the identified units (m^2), \(T\) in the equation \(v=\sqrt{T / \mu}\) represents Tension.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Frequency in Physics
Understanding frequency is crucial in physics, especially when studying waves and vibrations. Frequency, denoted by the symbol \(f\), represents the number of cycles of a repetitive event per unit time. The SI unit for frequency is the Hertz (Hz), equivalent to one cycle per second. It's often calculated using the relationship \(f=1/T\), where \(T\) is the period of the wave, the time it takes for one full cycle to complete.

In context, if you're listening to a musical note with a frequency of 440 Hz, that note is vibrating 440 times every second. Higher frequencies correspond to a higher pitch in sound, and in light, a higher frequency means higher energy and a color shift towards the violet end of the spectrum. Frequency is a fundamental aspect in many areas of physics, including the study of electrical circuits, acoustic engineering, and medical imaging technologies like MRI and ultrasound.
Period of a Wave
The period of a wave, represented as \(T\), is the time taken for a single cycle of a wave to pass a given point. It's the inverse of frequency, which is why the formula \(f=1/T\) is so important; it allows us to switch between talking about wave cycles in terms of time or number of occurrences. The period is measured in seconds.

For example, the gentle ebb and flow of ocean waves might have a period of about 10 seconds, meaning each wave cycle takes 10 seconds to pass through. The relationship between period and frequency is fundamental because it helps predict how often events happen and is critical in tuning musical instruments, understanding the nature of light, and analyzing electrical signals.
Tension in Strings
In physics, especially in the study of waves on strings and harmonic oscillators, tension plays a pivotal role. Tension, often denoted by \(T\), is the force conducted along a string or wire when it's pulled taut by forces acting from opposite ends. This force is responsible for creating waves that travel along the string when it's plucked or struck.

The Impact of Tension on Wave Velocity

In the formula \(v=\sqrt{T/\mu}\), \(v\) stands for the velocity of the wave on the string, and \(\mu\) is the linear mass density, the mass per unit length of the string. An increase in tension results in a higher wave velocity, assuming the mass density remains constant. This concept is exploited by musicians when tuning their instruments; tightening a guitar string increases the tension, thereby raising the pitch of the sound produced as the wave velocity increases.
Velocity of a Wave
The velocity of a wave, \(v\), refers to the speed at which the wave propagates through a medium. For transverse waves on a string, this can be derived from the relationship \(v=\sqrt{T/\mu}\), with tension (\(T\)) and linear mass density (\(\mu\)) of the medium. The unit of wave velocity is meters per second (m/s).

Factors Affecting Wave Velocity

The velocity depends on the properties of the medium and, in the case of strings, is directly influenced by tension and inversely by mass density. If you were to compare two identical guitar strings, where one is tightened to a greater tension, the string with higher tension would have waves traveling faster along it. In different mediums like air or water, wave velocity is affected by factors such as temperature, density, and elasticity of the medium.

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Most popular questions from this chapter

A two-dimensional water wave spreads in circular ripples. Show that the amplitude \(A\) at a distance \(r\) from the initial disturbance is proportional to \(1 / \sqrt{r}\). (Suggestion: Consider the energy carried by one outward- moving ripple.)

Two points \(A\) and \(B\) on the surface of the Earth are at the same longitude and \(60.0^{\circ}\) apart in latitude. Suppose that an earthquake at point \(A\) creates a \(P\) wave that reaches point \(B\) by traveling straight through the body of the Earth at a constant speed of \(7.80 \mathrm{km} / \mathrm{s} .\) The earthquake also radiates a Rayleigh wave, which travels across the surface of the Earth in an analogous way to a surface wave on water, at \(4.50 \mathrm{km} / \mathrm{s}\). (a) Which of these two seismic waves arrives at \(B\) first? (b) What is the time difference between the arrivals of the two waves at \(B ?\) Take the radius of the Earth to be \(6370 \mathrm{km}\).

A string of length \(L\) consists of two sections. The left half has mass per unit length \(\mu=\mu_{0} / 2,\) while the right has a mass per unit length \(\mu^{\prime}=3 \mu=3 \mu_{0} / 2 .\) Tension in the string is \(T_{0} .\) Notice from the data given that this string has the same total mass as a uniform string of length \(L\) and mass per unit length \(\mu_{0}\). (a) Find the speeds \(v\) and \(v^{\prime}\) at which transverse pulses travel in the two sections. Express the speeds in terms of \(T_{0}\) and \(\mu_{0},\) and also as multiples of the speed \(v_{0}=\left(T_{0} / \mu_{0}\right)^{1 / 2} .\) (b) Find the time interval required for a pulse to travel from one end of the string to the other. Give your result as a multiple of \(\Delta t_{0}=L / v_{0}\).

Ocean waves with a crest-to-crest distance of \(10.0 \mathrm{m}\) can be described by the wave function $$y(x, t)=(0.800 \mathrm{m}) \sin [0.628(x-v t)]$$ where \(v=1.20 \mathrm{m} / \mathrm{s} .\) (a) Sketch \(y(x, t)\) at \(t=0 .\) (b) Sketch \(y(x, t)\) at \(t=2.00 \mathrm{s} .\) Note that the entire wave form has shifted \(2.40 \mathrm{m}\) in the positive \(x\) direction in this time interval.

A \(2.00-\mathrm{kg}\) block hangs from a rubber cord, being supported so that the cord is not stretched. The unstretched length of the cord is \(0.500 \mathrm{m},\) and its mass is 5.00 g. The "spring constant" for the cord is \(100 \mathrm{N} / \mathrm{m} .\) The block is released and stops at the lowest point. (a) Determine the tension in the cord when the block is at this lowest point. (b) What is the length of the cord in this "stretched" position? (c) Find the speed of a transverse wave in the cord if the block is held in this lowest position.

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