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A woman has a mass of 55 kg. a. What is her weight while standing on earth? b. What are her mass and her weight on the moon, where \(g=1.62 \mathrm{m} / \mathrm{s}^{2} ?\)

Short Answer

Expert verified
a. The woman's weight on Earth is 539.55 N. b. The woman's mass on the moon is still 55 kg, but her weight is 89.1 N.

Step by step solution

01

Calculate weight on earth

To find the woman's weight on Earth, use the formula Weight = Mass * Gravity. We know that her mass is 55 kg, and the gravity on Earth is 9.81 m/s^2. Multiplying these together, we obtain the weight: Weight = 55 kg * 9.81 m/s^2.
02

Calculate mass and weight on the moon

The woman's mass will remain the same on the moon because mass is a measure of the amount of matter in an object, which does not change with location. Thus, her mass is still 55 kg. To find her weight on the moon, use the formula for weight mentioned before, but now use the moon's gravitational constant, which is given as 1.62 m/s^2: Weight = 55 kg * 1.62 m/s^2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Weight Calculation
Calculating weight involves understanding the relationship between mass, gravitational acceleration, and weight itself. The formula to use is:
\[\text{Weight} = \text{Mass} \times \text{Gravitational Acceleration}\]This simple formula helps us calculate the weight of an object depending on where it is located. For example, on Earth, gravitational acceleration is approximately 9.81 m/s². Thus, if a woman has a mass of 55 kg, her weight is found by multiplying her mass by Earth's gravity:
\[\text{Weight on Earth} = 55 \text{ kg} \times 9.81 \text{ m/s}^2 = 539.55 \text{ N}\]Weight is expressed in Newtons (N), a unit that describes forces. Changing the location, such as moving from Earth to the Moon, only requires replacing the gravitational value in the formula.
Mass Versus Weight
Understanding the difference between mass and weight is crucial:
  • Mass is the measure of the amount of matter in an object. It remains constant no matter where the object is in the universe.
  • Weight, however, is the force exerted by gravity on that mass. It can change depending on the location.
For example, the woman's mass on Earth is 55 kg, and it will be the same on the Moon. Her weight, due to different gravitational forces, will vary. On the Moon, with a gravitational acceleration of 1.62 m/s²:
\[\text{Weight on Moon} = 55 \text{ kg} \times 1.62 \text{ m/s}^2 = 89.1 \text{ N}\]Understanding these differences helps in distinguishing between the physical concept of mass and the experience of weight under different gravitational conditions.
Gravitational Acceleration
Gravitational acceleration is a key factor in determining an object's weight. It measures how quickly an object's velocity changes due to gravitational force:
  • On Earth, gravitational acceleration is about 9.81 m/s².
  • On the Moon, it is much less, at 1.62 m/s².
This difference in gravitational acceleration explains why things feel lighter on the Moon. Less gravitational force means less weight on the same mass. Therefore, understanding gravitational acceleration helps us appreciate how weight can vary drastically depending on where you are in the universe. This concept helps us explore how astronauts experience weightlessness, as different gravitational pulls affect how they feel their mass.

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Most popular questions from this chapter

A particle of mass \(m\) moving along the \(x\) -axis experiences the net force \(F_{x}=c l,\) where \(c\) is a constant. The particle has velocity \(v_{\mathrm{dr}}\) at \(t=0 .\) Find an algebraic expression for the particle's velocity \(v_{x}\) at a later time \(t\).

What thrust does a \(200 \mathrm{g}\) model rocket need in order to have a vertical acceleration of \(10 \mathrm{m} / \mathrm{s}^{2}\) a. On Earth? b. On the moon, where \(g=1.62 \mathrm{m} / \mathrm{s}^{2} ?\)

A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes. The friction force on the sled is \(1000 \mathrm{N}\) and the angle between the two ropes is \(20^{\circ} .\) How hard must each player pull to drag the coach at a steady \(2.0 \mathrm{m} / \mathrm{s} ?\)

A \(50 \mathrm{kg}\) box hangs from a rope. What is the tension in the rope if: a. The box is at rest? b. The box moves up at a steady \(5.0 \mathrm{m} / \mathrm{s} ?\) c. The box has \(v_{y}=5.0 \mathrm{m} / \mathrm{s}\) and is speeding up at \(5.0 \mathrm{m} / \mathrm{s}^{2} ?\) d. The box has \(v_{y}=5.0 \mathrm{m} / \mathrm{s}\) and is slowing down at \(5.0 \mathrm{m} / \mathrm{s}^{2} ?\)

A \(10 \mathrm{kg}\) crate is placed on a horizontal conveyor belt. The materials are such that \(\mu_{\varepsilon}=0.5\) and \(\mu_{k}=0.3\) a. Draw a free-body diagram showing all the forces on the crate if the conveyer belt runs at constant speed. b. Draw a free-body diagram showing all the forces on the crate if the conveyer belt is speeding up. c. What is the maximum acceleration the belt can have without the crate slipping?

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