/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 A \(10 \mathrm{kg}\) crate is pl... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(10 \mathrm{kg}\) crate is placed on a horizontal conveyor belt. The materials are such that \(\mu_{\varepsilon}=0.5\) and \(\mu_{k}=0.3\) a. Draw a free-body diagram showing all the forces on the crate if the conveyer belt runs at constant speed. b. Draw a free-body diagram showing all the forces on the crate if the conveyer belt is speeding up. c. What is the maximum acceleration the belt can have without the crate slipping?

Short Answer

Expert verified
The maximum acceleration of the conveyor belt to prevent the crate from slipping is \(\mu_{\varepsilon} g = 0.5 * 9.8 = 4.9 \, \mathrm{m/s^{2}}\)

Step by step solution

01

Understand the Problem

Firstly, it is crucial to clearly understand what forces are acting on the crate. The crate is being acted upon by gravity, the normal force perpendicular to the surface, and the frictional forces that oppose intended motion. The frictional force could either be static (\(\mu_{\varepsilon}\)) when the crate is not moving relative to the conveyor belt, or kinetic (\(\mu_{k}\)) when it is. In this step, draw the free-body diagram for the crate on a conveyor running at a constant speed. Gravity acts downward which is balanced by the normal force. The frictional force keeps the crate moving at the same speed as the conveyor and points in the direction of motion.
02

Illustrate Acceleration

Neither the gravitational force nor the normal force change in part b. However, because the conveyor belt is accelerating, the static frictional force must increase to prevent the crate from slipping backwards. The second free-body diagram is nearly identical to the first, but the friction vector is longer, representing the larger force.
03

Calculate Maximum Acceleration

The maximum acceleration occurs when the static frictional force is at its maximum, hence the crate is on the verge of slipping. The maximum static frictional force (\(f_{\varepsilon max}\)) can be calculated using the equation \(f_{\varepsilon max} = \mu_{\varepsilon} N\) where \(N\) is the normal force. The maximum acceleration (\(a_{max}\)) can be calculated by using Newton's second law \(F = ma\). In this case, \(f_{\varepsilon max} = ma_{max}\) so \(a_{max} = \frac{f_{\varepsilon max}}{m}\). Plugging the equation of \(f_{\varepsilon max}\) into it, we get \(a_{max} = \frac{\mu_{\varepsilon} N}{m}\). The normal force for a horizontal plane is equal to the weight of the object, hence \(N = mg\), where \(g\) is the acceleration due to gravity. Substituting \(N\) in the equation of \(a_{max}\) we get \(a_{max} = \frac{\mu_{\varepsilon} mg}{m} = \mu_{\varepsilon} g\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Static Friction
Understanding static friction is crucial in solving problems where objects are in contact, but not moving relative to each other. When a crate is placed on a stationary or constantly moving conveyor belt, static friction is what prevents it from slipping. It is the force that must be overcome to start moving the crate.

Static friction has a maximum value, often denoted as \( f_{\varepsilon max} \), which is the product of the coefficient of static friction \( \mu_{\varepsilon} \) and the normal force \( N \) exerted by the surface. The formula for maximum static friction is:\[ f_{\varepsilon max} = \mu_{\varepsilon} \cdot N \]
In scenarios where an object like our crate is on the verge of slipping, the static frictional force will have reached this maximum value. It's important to note that actual static friction can be any value from zero up to this maximum, depending on the external force applied.
Kinetic Friction
Once an object overcomes static friction and starts moving, kinetic friction comes into play. Kinetic friction, also known as sliding friction, acts between surfaces in relative motion. For the crate on the conveyor belt, if it starts sliding, it experiences a kinetic frictional force.

Like static friction, kinetic friction is the product of the coefficient of kinetic friction \( \mu_{k} \) and the normal force \( N \): \[ f_{k} = \mu_{k} \cdot N \]The coefficient of kinetic friction is typically less than the coefficient of static friction, which means that it requires less force to keep an object moving than it does to start it moving. It is essential for students to recognize the shift from static to kinetic friction in problems involving motion.
Newton's Second Law
Newton's second law of motion forms the foundation for analyzing the motion of objects when forces are applied. According to this principle:\[ F = ma \]where \( F \) represents the net force applied to an object, \( m \) is the mass, and \( a \) is the acceleration. For a crate on a conveyor belt, as in our example, the motion can be described by this law.

When the belt accelerates or decelerates, the forces acting on the crate must be considered to determine the resulting acceleration of the crate. In the case of achieving maximum acceleration without slipping, Newton's second law allows us to equate the maximum static frictional force to the product of the crate's mass and its acceleration.
Maximum Acceleration
The maximum acceleration of an object without causing it to slide is an important concept in physics, often encountered in problems involving friction. For our crate on the conveyor belt, calculating maximum acceleration involves setting the maximum static frictional force equal to the force required to accelerate the crate.

To find the maximum acceleration, we use the equation from Newton's second law:\[ a_{max} = \frac{f_{\varepsilon max}}{m} = \frac{\mu_{\varepsilon} N}{m} = \mu_{\varepsilon} g \]where \( a_{max} \) is the maximum acceleration, \( f_{\varepsilon max} \) is the maximum static frictional force, \( m \) is the mass of the crate, and \( g \) is the acceleration due to gravity. This ensures the crate remains stationary relative to the moving belt even as the belt's speed changes.

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