/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 57 An old mining tunnel disappears ... [FREE SOLUTION] | 91Ó°ÊÓ

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An old mining tunnel disappears into a hillside. You would like to know how long the tunnel is, but it's too dangerous to go inside. Recalling your recent physics class, you decide to try setting up standing-wave resonances inside the tunnel. Using your subsonic amplifier and loudspeaker, you find resonances at \(4.5 \mathrm{Hz}\) and 6.3 Hz, and at no frequencies between these. It's rather chilly inside the tunnel, so you estimate the sound speed to be \(335 \mathrm{m} / \mathrm{s}\). Based on your measurements, how far is it to the end of the tunnel?

Short Answer

Expert verified
The length of the tunnel is approximately 37.22 meters.

Step by step solution

01

Identify the first and second harmonics

From the problem, we can see that resonant frequencies of the tunnel are 4.5 Hz and 6.3 Hz. We can assume that these are the fundamental frequency (first harmonic) and the second harmonic. The first harmonic has a frequency of 4.5 Hz, and the second harmonic has a frequency of 6.3 Hz.
02

Applying the formula for resonant frequency

The formula for resonant frequency is \(f = nv / 2L\), where n is the harmonic number, v is the speed of sound, and L is the length of the tunnel. We can rearrange this formula to solve for L: \(L = nv / (2f)\). We are trying to find L, the length of the tunnel.
03

Calculating the length of the tunnel

To find L, we apply the formula using the first harmonic frequency. This means n=1. So, we plug n=1, v=335 m/s, and f= 4.5Hz into the equation to solve for L: \(L = (1*335) / (2*4.5) = 37.22\) meters approximately, which is the length of the tunnel.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sound Speed in Physics
Understanding the speed of sound is crucial when exploring concepts such as standing-wave resonances. In physics, the speed of sound refers to the distance that sound waves travel through an elastic medium per unit of time. It isn't a constant value; rather, it varies depending on the medium (air, water, solids) and factors like temperature, humidity, and pressure. In our exercise, the estimated speed of sound in the tunnel's cold air is 335 meters per second (m/s). This estimate is indispensable for calculating distances with resonance phenomena, as the speed of sound directly impacts the wavelength of sound waves.

It's interesting to note that the speed of sound is faster in solid materials and slower in gases. When dealing with air, a rough estimate is that the speed of sound increases by about 0.6 m/s with each degree Celsius increase in temperature. Hence, colder conditions inside the mining tunnel have led us to use the slightly reduced sound speed in our calculations.
Harmonic Frequencies
When discussing standing-wave resonances, harmonic frequencies come to the fore. Harmonic frequencies are integral multiples of a fundamental frequency—the lowest frequency at which a system naturally vibrates. In other words, harmonics are the various frequencies at which standing waves can form within a given space or object. The first harmonic is the fundamental frequency, while the second harmonic is twice the fundamental frequency, and so on.

Typically, harmonics are produced when boundaries reflect waves back onto themselves, creating a pattern of constructive and destructive interference. In our mining tunnel example, the fact that there were resonances observed at two distinct frequencies indicated that we were likely observing the first and second harmonics. Being aware of the physical properties that allow these harmonic frequencies to occur is crucial to understanding the nature of the sounds we are analyzing and their relationship to the dimensions of the tunnel.
Resonant Frequency Formula
The resonant frequency formula is a fundamental concept in understanding standing waves and their connection to physical dimensions. The formula for resonant frequency, which we used in the exercise, is given by the equation \(f = \frac{nv}{2L}\), where \(f\) represents the resonant frequency, \(n\) is the harmonic number (an integer), \(v\) is the speed of sound within the medium, and \(L\) is the length of the resonating object—in this case, the tunnel.

This equation reveals how the natural frequencies of a space are related to its size, and it allows us to calculate one of these variables if the other three are known. For example, by knowing the harmonic frequencies and the speed of sound, we can calculate the length of the tunnel as demonstrated in the problem. This formula is a powerful tool in areas ranging from musical instrument design to architectural acoustics, as it provides insight into how sound will behave within a particular space.

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Most popular questions from this chapter

A vertical tube, open at both ends, is lowered into a tank of water until it is partially filled. The top portion of the tube, above the water, is filled with a gas that, because it is denser than air, remains in the tube. A 50.0 -cm-long, 1.00 g horizontal wire is stretched just above the top of the tube with \(440 \mathrm{N}\) of tension. Bowing the wire at its center causes the wire to vibrate at its fundamental frequency. The water level in the tube is adjusted until the sound from the vibrating wire sets up a standing sound wave in the gas. The water is then lowered another \(30.5 \mathrm{cm}\) until the next standing sound wave is detected. Use this information to determine the speed of sound in the gas.

Two in-phase speakers \(2.0 \mathrm{m}\) apart in a plane are emitting. \(1800 \mathrm{Hz}\) sound waves into a room where the speed of sound is \(340 \mathrm{m} / \mathrm{s} .\) Is the point \(4.0 \mathrm{m}\) in front of one of the speakers, perpendicular to the plane of the speakers, a point of maximum constructive interference, perfect destructive interference, or something in between?

What are the three longest wavelengths for standing sound waves in a 121 -cm- long tube that is (a) open at both ends and (b) open at one end, closed at the other?

The lowest note on a grand piano has a frequency of \(27.5 \mathrm{Hz}\) The entire string is \(2.00 \mathrm{m}\) long and has a mass of \(400 \mathrm{g}\). The vibrating section of the string is \(1.90 \mathrm{m}\) long. What tension is needed to tune this string properly?

A 75 g bungee cord has an equilibrium length of \(1.20 \mathrm{m}\). The cord is stretched to a length of \(1.80 \mathrm{m},\) then vibrated at \(20 \mathrm{Hz}\) This produces a standing wave with two antinodes. What is the spring constant of the bungee cord?

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