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What are the three longest wavelengths for standing sound waves in a 121 -cm- long tube that is (a) open at both ends and (b) open at one end, closed at the other?

Short Answer

Expert verified
The three longest wavelengths for an open tube are 2.42 m, 1.21 m, and 0.81 m, respectively. For a tube open at one end and closed at the other, they are 4.84 m, 1.61 m, and 0.97 m, respectively.

Step by step solution

01

Find the maximum wavelength for the tube open at both ends

The maximum wavelength \(\lambda_{max}\) is twice the length 'L' of the tube when it's open at both ends. So, for the first case, \(\lambda_{max} = 2L\), where L = 121 cm = 1.21 m. Therefore, \(\lambda_1 = 2 * 1.21\) m.
02

Find the 2nd and 3rd largest wavelengths for the tube open at both ends

For a tube open at both ends, all harmonics are allowed. So, the second largest wavelength is half the maximum wavelength, and the third largest wavelength is a third of the maximum. Therefore, we find \(\lambda_2 = \lambda_{max} / 2\) and \(\lambda_3 = \lambda_{max} / 3\).
03

Find the maximum wavelength for the tube open at one end and closed at the other

When the tube is open at one end and closed at the other, the maximum wavelength \(\lambda_{max}\) is four times the length of the tube 'L'. So, \(\lambda_{max} = 4L = 4 * 1.21\) m for the second case.
04

Find the 2nd and 3rd largest wavelengths for the tube open at one end and closed at the other

For a tube open at one end and closed at the other, only odd harmonics are allowed. So, the second largest wavelength is a third of the maximum, and the third largest is a fifth. Therefore, calculate \(\lambda_2 = \lambda_{max} / 3\) and \(\lambda_3 = \lambda_{max} / 5\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acoustic Resonance
Acoustic resonance is at the heart of how many musical instruments produce sound. It's a phenomenal natural occurrence where an object vibrates at higher amplitudes exclusively at certain frequencies known as the object's resonant frequencies. This is similar to a playground swing that naturally swings at a particular frequency. When sound waves of these frequencies strike the object, like our tube in the exercise, they cause the air inside to resonate, resulting in enhanced sound, or standing sound waves.

In the case of the open tube, the resonance allows the whole spectrum of harmonics to be produced, displaying how a single physical structure can give rise to a complex set of sounds. In contrast, with one end closed, the resonance conditions restrict the harmonic series to only the odd harmonics, which substantially changes the sound produced by the tube.
Harmonic Series
The harmonic series explains the multiple frequencies at which a single system can resonate. In more technical terms, it encompasses all integer multiples of a fundamental frequency. Picture a guitar string: when plucked, it doesn't just vibrate in its entire length—it also vibrates in sections, or harmonics. The fundamental frequency gives the note its pitch, while the harmonics add timbre and richness.

The exercise showcases that in an open tube, vibrations produce a rich set of frequencies, including both odd and even harmonics. Hence, the second and third longest wavelengths correspond to these harmonics, which are fractions of the maximum wavelength (the fundamental frequency).
Wavelength Calculation
Wavelength calculation plays a pivotal role in understanding standing waves. The wavelength of a sound wave correlates to its pitch—shorter wavelengths make for higher pitches and vice versa. In our exercise, we calculate the longest wavelengths, which produce the lowest pitches the tube can resonate. This involves simple mathematical relationships.

For instance, the wavelength for an open tube is twice the tube's length, as the tube can support a standing wave that fits two complete wave cycles within its length. The subsequent longest wavelengths are simply divisions of this first, fundamental wavelength. This hands-on exercise promotes tangible comprehension of theoretical wave behavior in a physical context.
Physics of Musical Instruments
The study of the physics of musical instruments unravels how instruments turn mechanical vibrations into beautiful melodies. Vibrating strings, reeds, and air columns in instruments depend on intricate physical principles to produce sound. This marrying of physics and music can be seen in wind instruments where, much like our tube example, standing waves in the air column correlate directly to the notes played.

By calculating and understanding various wavelengths and how they relate to the construction of the instrument (open or closed ends), we gain a deeper appreciation for the scientific underpinnings of music. Each instrument's design leverages the physics of sound waves to harness specific resonant properties, enabling us to play a wide range of harmonious sounds.

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Most popular questions from this chapter

A narrow column of \(20^{\circ} \mathrm{C}\) air is found to have standing waves at frequencies of \(390 \mathrm{Hz}, 520 \mathrm{Hz},\) and \(650 \mathrm{Hz}\) and at no frequencies in between these. The behavior of the tube at frequencies less than 390 Hz or greater than \(650 \mathrm{Hz}\) is not known. Is this an open-open tube or an open-closed tube? Explain. b. How long is the tube? c. Draw a displacement graph of the 520 Hz standing wave in the tube. d. The air in the tube is replaced with carbon dioxide, which has a sound speed of \(280 \mathrm{m} / \mathrm{s} .\) What are the new frequencies of these three modes?

A vertical tube, open at both ends, is lowered into a tank of water until it is partially filled. The top portion of the tube, above the water, is filled with a gas that, because it is denser than air, remains in the tube. A 50.0 -cm-long, 1.00 g horizontal wire is stretched just above the top of the tube with \(440 \mathrm{N}\) of tension. Bowing the wire at its center causes the wire to vibrate at its fundamental frequency. The water level in the tube is adjusted until the sound from the vibrating wire sets up a standing sound wave in the gas. The water is then lowered another \(30.5 \mathrm{cm}\) until the next standing sound wave is detected. Use this information to determine the speed of sound in the gas.

Two in-phase loudspeakers separated by distance \(d\) emit \(170 \mathrm{Hz}\) sound waves along the \(x\) -axis. As you walk along the axis, away from the speakers, you don't hear anything even though both speakers are on. What are three possible values for d? Assume a sound speed of \(340 \mathrm{m} / \mathrm{s}\).

Two sinusoidal waves with equal wavelengths travel along a string in opposite directions at \(3.0 \mathrm{m} / \mathrm{s}\). The time between two successive instants when the antinodes are at maximum height is \(0.25 \mathrm{s} .\) What is the wavelength?

A soap bubble is essentially a very thin film of water \((n=\) 1.33) surrounded by air. The colors that you see in soap bubbles are produced by interference, much like the colors of dichroic glass. a. Derive an expression for the wavelengths \(\lambda_{\mathrm{c}}\) for which constructive interference causes a strong reflection from a soap bubble of thickness \(d\) Hint: Think about the reflection phase shifts at both boundaries. b. What visible wavelengths of light are strongly reflected from a 390 -nm- thick soap bubble? What color would such a soap bubble appear to be?

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