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A particle of positive charge \(q\) and mass \(m\) enters with velocity \(V\) ) at the origin in a magnetic field \(B(-\hat{k})\) which is present in the whole space. The charge makes a perfectly inelastic collision with an identical particle (having same charge) at rest but free to move at its maximum positive \(y\) -coordinate. After collision, the combined charge will move on trajectory where \(r=\frac{m V}{q B}\) ) a. \(y=\frac{m V}{q B} x\) b. \((x+r)^{2}+(y-r / 2)^{2}=r^{2} / 4\) c. \((x+r)^{2}+(y-r / 2)^{2}=r^{2} / 8\) d. \((x-r)^{2}+(y+r / 2)^{2}=r^{2} / 4\)

Short Answer

Expert verified
Option b is correct: the trajectory equation is \((x+r)^{2}+(y-r / 2)^{2}=r^{2} / 4\).

Step by step solution

01

Understand the Initial Conditions

The particle initially travels with velocity \(V\) in a magnetic field \(B(-\hat{k})\). The magnetic field causes the particle to execute circular motion due to the Lorentz force. The centripetal force required for this motion is provided by the magnetic force, which is expressed as \(qVB = \frac{mV^2}{r}\). This gives the formula for the radius of curvature \(r = \frac{mV}{qB}\).
02

Analyze the Collision

The particle makes an inelastic collision with another identical particle at rest when it reaches the maximum positive \(y\)-coordinate. After the collision, as both particles stick together, the combined mass becomes \(2m\) and the combined charge becomes \(2q\). Consequently, the new radius of curvature of the joint particle system post-collision remains \(r\) due to identical magnetic effects. The trajectory must be re-evaluated considering this new condition.
03

Determine New Trajectory Equation

Post-collision, since the charge is doubled, and they follow a circular path, we apply geometric constraints to determine their trajectory. With the focus still on maximum \(y\)-coordinate where the collision happens, the center of the circle will be affected along with its radius. Using the equation of a circle \((x - h)^2 + (y - k)^2 = R^2\), centering the circle at \((x = -r, y = +r/2)\) makes sense when considering their new combined path.
04

Identify Matching Equation

Considering possible trajectory equations given in the options, option b, \((x+r)^{2}+(y-r / 2)^{2}=r^{2} / 4\), describes a circle centered at \((-r, r/2)\). Analyzing this with the body post-collision fits our parameters, agreeing with the impact position at the highest initial \(y\)-coordinate, thus forming the correct circular path for trajectory.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lorentz Force
The Lorentz Force is the fundamental force experienced by a charged particle moving through a magnetic field. It's given by the formula \( F = q(\mathbf{v} \times \mathbf{B}) \), where \( q \) is the charge, \( \mathbf{v} \) is the velocity, and \( \mathbf{B} \) is the magnetic field. This force is perpendicular to the direction of velocity and the magnetic field.
This perpendicular nature of the Lorentz Force causes charged particles to move in a curved path.
For a particle moving through a magnetic field:
  • The speed remains the same but the direction continuously changes.
  • This results in circular or helical trajectories, depending on the angle between \( \mathbf{v} \) and \( \mathbf{B} \).
Understanding Lorentz Force is crucial because it plays a central role in phenomena such as particle accelerators, and it perfectly illustrates how magnetic fields can control charged particle motion without changing their speed.
Centripetal Motion
Centripetal motion describes the motion of an object moving in a circle at a constant speed. The magnetic force on a charged particle acts as the centripetal force required to keep it moving in a circular path.
The centripetal force needed for a particle with mass \( m \) moving at speed \( V \) in a circle of radius \( r \) is given by \( \frac{mV^2}{r} \).
In the context of charged particles:
  • The magnetic force \( qVB \) acts as the centripetal force.
  • The radius of curvature for the motion is \( r = \frac{mV}{qB} \).
This concept is essential for understanding how charged particles behave in magnetic fields and is frequently applied in designing magnetic confinement systems for reactors and cyclotrons.
Inelastic Collision
An inelastic collision is one in which the colliding particles stick together after impact, losing some kinetic energy in the process. In this scenario, two charged particles collide inelastically:
  • Both particles have equal mass \( m \) and charge \( q \).
  • After the collision, they move as a single unit with mass \( 2m \) and charge \( 2q \).
In such collisions, remember:
  • Momentum is conserved, meaning that the momentum before impact equals the momentum after.
  • Some kinetic energy is converted into other forms, like heat or deformation energy.
  • Post-collision, the combined object's path and motion need to be recalculated.
Understanding inelastic collisions is vital as it allows us to see how energy and momentum conservation laws operate in interactions.
Circular Trajectory
A circular trajectory is the curved path taken by an object moving under a central force, such as the centripetal force from a magnetic field. This trajectory can be explicitly described with the equation of a circle:
  • Consider a circle with center \((h, k)\) and radius \(R\).
  • The general equation is \((x - h)^2 + (y - k)^2 = R^2\).
In the mechanical context:
  • Particles move in a circle due to the constant perpendicular force applied by a magnetic field.
  • Post-collision path can be found by altering this equation based on new conditions (e.g. mass doubling).
Knowing how circular trajectories are formed helps to predict the particle’s future motion, which is essential in applications like designing particle detectors and plasma confinement in tokamaks.

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Most popular questions from this chapter

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