Chapter 9: Problem 92
A long, straight, hollow conductor (tube) carrying a current has two sections
\(A\) and \(C\) of unequal cross sections joined by a conical section \(B\). 1,2 and
3 are points on a line parallel
to the axis of the conductor. The magnetic fields at 1,2 and 3 have magnitudes
\(B_{1}, B_{2}\) and \(B_{3}\). Then,
a. \(B_{1}=B_{2}=B_{3}\)
b. \(B_{1}=B_{2} \neq B_{3}\)
c. \(B_{1}
Short Answer
Step by step solution
Understanding the Magnetic Field in a Conductor
Analyzing Point Locations Relative to Conductor Sections
Applying Ampère's Law
Evaluating the Given Choices
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ampère's Law
Magnetic Field
- It is generated by electric currents.
- Its direction can be determined using the right-hand rule.
- In a hollow conductor, the field inside remains zero unless current is present inside that region.
Hollow Conductor
Current Distribution
- Current flows along the outer surface of a hollow conductor.
- This results in zero magnetic field inside the hollow section because there is no current enclosed there.
- The magnetic properties outside the surface are uniform, leading to predictable patterns of magnetic flux.