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In an automatic clothes dryer, a hollow cylinder moves the clothes on a vertical circle (radius r 0.32 m), as the drawing shows. The appliance is designed so that the clothes tumble gently as they dry. This means that when a piece of clothing reaches an angle of \(\theta\) above the horizontal, it loses contact with the wall of the cylinder and falls onto the clothes below. How many revolutions per second should the cylinder make in order that the clothes lose contact with the wall when \(\theta=70.0^{\circ} ?\)

Short Answer

Expert verified
The dryer should make approximately 0.66 revolutions per second.

Step by step solution

01

Understand the Forces Involved

When clothes are in contact with the wall of the cylinder, they're subjected to the gravitational force pulling them downwards and the normal force from the cylinder acting inward. As the cylinder rotates, a centrifugal force acts outward which is the required centripetal force to keep the clothes moving in a circle.
02

Set Up the Condition for Losing Contact

Clothes lose contact with the cylinder when the centripetal force is just about to equal the gravitational force component acting perpendicular to the cylinder wall. At the angle of \(70^{\circ}\), this component is \(mg \cos(\theta)\).
03

Express the Centripetal Force

The centripetal force needed to keep the clothes in motion along the cylinder can be expressed as \(F_c = m v^2 / r\), where \(v\) is the tangential velocity of clothes and \(r\) is the radius of the circle.
04

Equate Forces at the Point of Losing Contact

Equate the gravitational force component to the centripetal force: \(m g \cos(\theta) = m v^2 / r\). Simplify by cancelling out the mass \(m\) from both sides of the equation.
05

Solve for Velocity

Rearrange the formula to solve for the tangential velocity \(v\): \[v^2 = g r \cos(\theta)\qquad \Rightarrow \qquad v = \sqrt{g r \cos(\theta)}\\] where \(g = 9.81 \, \text{m/s}^2\), \(r = 0.32 \, \text{m}\) and \(\theta = 70^{\circ}\).
06

Calculate Tangential Velocity

Plug in the values and solve: \[v = \sqrt{9.81 \times 0.32 \times \cos(70^{\circ})}_\approx 1.33 \, \text{m/s}\\] Use \(\cos(70^{\circ}) \approx 0.342\) in the calculation.
07

Convert Tangential Velocity to Revolutions Per Second

Convert \(v\) to revolutions per second using the formula \(v = 2 \pi r f\), where \(f\) is the frequency. Solve for \(f\): \[f = \frac{v}{2 \pi r} = \frac{1.33}{2 \pi \times 0.32} \approx 0.66 \, \text{revolutions per second}\\]
08

Conclusion

Therefore, the dryer should make approximately \0.66\ revolutions per second for the clothes to lose contact at an angle of \(70^{\circ}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centripetal Acceleration
Centripetal acceleration is a fundamental concept in mechanics, especially when dealing with circular motion. It explains how objects moving in a circular path seem to be pushed outwards. But in reality, they are constantly being accelerated towards the center of the circle. For a body moving in a circle of radius \(r\) with a velocity \(v\), the centripetal acceleration \(a_c\) can be described by the formula:
\[a_c = \frac{v^2}{r}\]This acceleration is always directed towards the center of the circle. If you think of it in terms of an automatic clothes dryer, it's what keeps the clothes plastered against the wall of the cylinder as it spins. As the dryer rotates, the clothes continuously change their direction while maintaining a constant speed.
  • This shift in direction without a change in speed results in centripetal acceleration.
  • It's essential, as without it, the clothes would not follow a circular path.
  • The magnitude of this acceleration is directly proportional to the square of the tangential velocity and inversely proportional to the radius of the circular path.
Understanding centripetal acceleration helps in comprehending why and how clothes lose contact in a rotating dryer when certain speed and angle conditions are met.
Gravitational Force
Gravitational force is the force of attraction between two masses. On Earth, this force gives weight to physical objects and causes them to fall towards the ground when dropped. In the context of the clothes dryer, gravitational force is what pulls the clothes downwards. It is important to understand its components when observing motion in a circle.
  • In a circular motion scenario, gravity can be split into two components: one parallel to the movement and one perpendicular.
  • When clothes rotate inside the dryer, the perpendicular component of gravitational force plays a critical role in determining when the clothes will lose contact with the drum wall.
  • This is determined by the angle at which clothes are at the point of letting go, indicated by \(mg \cos(\theta)\).
Thus, calculating the forces involved at any given time lets us predict the motion changes, such as losing contact with the cylinder's wall.
Tangential Velocity
Tangential velocity is the linear speed of a point on a rotating object. This type of velocity looks at how fast something is moving along a tangent line that touches the circle's edge. For the clothes in a dryer, tangential velocity determines how quickly they move around inside the cylinder.
  • The formula for tangential velocity \(v\) is given by \(v = r \omega\) where \(\omega\) is the angular velocity.
  • Here, \(r\) is the radius of the drum, and knowing \(v\), one can find out how these velocities affect the object鈥檚 motion.
  • By solving the centripetal force equation, \(mg \cos(\theta) = \frac{mv^2}{r}\), you can find the tangential velocity required for the clothes to lose contact.
Ultimately, having a correct tangential velocity ensures a fine balance between staying in motion and losing grip, crucial for a smooth tumble without damaging the clothes.
Rotational Motion
Rotational motion refers to the motion of an object around a center point or axis. In physics, understanding these concepts can help explain how objects like clothes in a dryer maintain a smooth, repetitive path. In rotational motion, both angular velocity and frequency of revolution play a critical role.
  • Angular velocity is how fast an object rotates about the circle's center and is usually measured in radians per second.
  • An automatic dryer must strike the right balance, making enough revolutions per second so clothes are dried evenly but gently.
  • Formulas such as \(f = \frac{v}{2 \pi r}\), where \(f\) is frequency, let us determine how many rotations the drum should make to ensure optimal contact for drying clothes.
Understanding rotational motion, including how changes in frequency and speed affect the items inside the cylinder, allows us to understand the balance of forces that makes devices like dryers work effectively.

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