/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Two satellites are in circular o... [FREE SOLUTION] | 91Ó°ÊÓ

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Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 360 km above the earth’s surface, while that for satellite B is at a height of 720 km. Find the orbital speed for each satellite.

Short Answer

Expert verified
Satellite A's speed: 7706 m/s, Satellite B's speed: 7380 m/s.

Step by step solution

01

Understand the Problem

We are to find the orbital speed of two satellites orbiting at different heights above Earth's surface. Satellite A orbits at 360 km and satellite B orbits at 720 km.
02

Recall the Orbital Speed Formula

The formula for orbital speed is given by \( v = \sqrt{\frac{GM}{r}} \), where \( G \) is the gravitational constant \( 6.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \), \( M \) is Earth's mass \( 5.972 \times 10^{24} \, \text{kg} \), and \( r \) is the satellite's distance from Earth's center.
03

Calculate Distance from Earth's Center

Earth's radius is approximately 6371 km. For Satellite A, the distance from Earth's center is \( 6371 + 360 = 6731 \, \text{km} = 6.731 \times 10^6 \, \text{m} \). For Satellite B, it is \( 6371 + 720 = 7091 \, \text{km} = 7.091 \times 10^6 \, \text{m} \).
04

Calculate Orbital Speed for Satellite A

Plug in Satellite A's distance into the orbital speed formula: \( v_A = \sqrt{\frac{6.674 \times 10^{-11} \, \times 5.972 \times 10^{24}}{6.731 \times 10^6}} \). Simplifying, \( v_A \approx 7706 \, \text{m/s} \).
05

Calculate Orbital Speed for Satellite B

Plug in Satellite B's distance into the orbital speed formula: \( v_B = \sqrt{\frac{6.674 \times 10^{-11} \, \times 5.972 \times 10^{24}}{7.091 \times 10^6}} \). Simplifying, \( v_B \approx 7380 \, \text{m/s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Satellite Orbits
Satellites move in orbits around celestial bodies like Earth. An orbit is a circular or elliptical path that a satellite follows while maintaining a consistent speed and altitude.
For a satellite to stay in orbit, it must balance gravitational forces pulling it toward Earth with its tendency to move forward. This creates a stable path. In this exercise, we have two satellites, A and B, each in a circular orbit at different heights. Satellite A is 360 km above the surface, while B is at 720 km. The difference in orbit height affects their orbital speed, as we'll discuss.
  • Satellites orbits can be circular or elliptical
  • An orbit's altitude influences the satellite's speed
  • The higher the orbit, the slower the speed needed
Understanding orbits is crucial as they determine how fast a satellite must travel to remain in balance with Earth's gravity. Higher orbits require slower speeds, as reflected in the speeds of satellites A and B.
Gravitational Constant
The gravitational constant, denoted by the symbol G, is a fundamental part of the law of universal gravitation. It quantifies the strength of gravitational attraction between two masses.
Isaac Newton formulated this constant, which is crucial for calculating forces in scenarios involving gravity. In the provided formula for orbital speed, \[ v = \sqrt{\frac{GM}{r}} \], G is a key component. This formula shows how the gravitational pull from Earth's mass (M) affects satellite velocity.
  • The value of G is approximately \( 6.674 \times 10^{-11} \text{Nm}^2/\text{kg}^2 \)
  • G is a constant used in the formula for calculating gravitational force
  • It helps determine the balance of forces in an orbit
In essence, G helps us compute how strong the gravitational pull is between Earth and the satellite. It's this pulling force that keeps satellites in their respective orbits and directly influences their speed and path.
Distance from Earth's Center
To determine orbital speed, it's essential to understand the satellite's distance from Earth's center.
This distance includes both Earth's radius and the satellite's height above Earth's surface.
Earth's average radius is about 6371 km, forming the baseline for calculating a satellite's total distance from Earth's center.
  • Satellite A: Earth radius (6371 km) + height (360 km) = 6731 km
  • Satellite B: Earth radius (6371 km) + height (720 km) = 7091 km
  • This distance is crucial for the orbital speed formula
By converting these distances to meters, as used in scientific calculations, we accurately insert them into the orbital speed equation. Each satellite's unique distance influences its speed. For instance, a greater distance implies a larger orbit and slower speed necessary to maintain circular motion. Understanding this concept clarifies why Satellite A, being closer to Earth, travels faster than Satellite B.

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Most popular questions from this chapter

A motorcycle has a constant speed of 25.0 m/s as it passes over the top of a hill whose radius of curvature is 126 m. The mass of the motorcycle and driver is 342 kg. Find the magnitudes of (a) the centripetal force and (b) the normal force that acts on the cycle.

Two newly discovered planets follow circular orbits around a star in a distant part of the galaxy. The orbital speeds of the planets are determined to be 43.3 km/s and 58.6 km/s. The slower planet’s orbital period is 7.60 years. (a) What is the mass of the star? (b) What is the orbital period of the faster planet, in years?

In an automatic clothes dryer, a hollow cylinder moves the clothes on a vertical circle (radius r 0.32 m), as the drawing shows. The appliance is designed so that the clothes tumble gently as they dry. This means that when a piece of clothing reaches an angle of \(\theta\) above the horizontal, it loses contact with the wall of the cylinder and falls onto the clothes below. How many revolutions per second should the cylinder make in order that the clothes lose contact with the wall when \(\theta=70.0^{\circ} ?\)

At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats facing the axis, their backs against the outer wall. At one instant the outer wall moves at a speed of 3.2 m/s, and an 83-kg person feels a 560-N force pressing against his back. What is the radius of the chamber?

The drawing shows a baggage carousel at an airport. Your suitcase has not slid all the way down the slope and is going around at a constant speed on a circle \((r=11.0 \mathrm{m})\) as the carousel turns. The coefficient of static friction between the suitcase and the carousel is 0.760 , and the angle \(\theta\) in the drawing is \(36.0^{\circ} .\) How much time is required for your suitcase to go around once?

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