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A motorcycle is traveling up one side of a hill and down the other side. The crest of the hill is a circular arc with a radius of 45.0 m. Determine the maximum speed that the cycle can have while moving over the crest without losing contact with the road.

Short Answer

Expert verified
Maximum speed is approximately 21.0 m/s.

Step by step solution

01

Understanding the Problem

We need to find the maximum speed a motorcycle can have at the top of a hill with a circular crest without losing contact with the road. This involves applying the concept of circular motion and the forces acting on the motorcycle.
02

Identify the Forces at the Crest

At the crest of the hill, the two forces acting on the motorcycle are the gravitational force (weight) pointing downwards and the normal force from the road. For the motorcycle to just stay in contact with the road, the normal force must be zero at maximum speed.
03

Apply Newton's Second Law

At the top of the hill, the centripetal force required to keep the motorcycle in circular motion is provided entirely by the gravitational force when the normal force is zero. Thus, we have: \( mg = \frac{mv^2}{r} \), where \( m \) is the mass, \( v \) is the velocity, and \( r \) is the radius of curvature.
04

Solve for the Maximum Speed

Rearrange the equation \( mg = \frac{mv^2}{r} \) to solve for \( v \). We get \( v = \sqrt{gr} \), where \( g \) is the acceleration due to gravity (approximately \(9.81 \text{ m/s}^2\)), and \( r = 45.0 \text{ m} \).
05

Calculate the Numerical Value

Substitute \( g = 9.81 \text{ m/s}^2 \) and \( r = 45.0 \text{ m} \) into the formula. Thus, \( v = \sqrt{9.81 \times 45.0} \approx 21.0 \text{ m/s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centripetal Force
Centripetal force is a crucial concept when understanding motion along a curved path, like the motorcycle traversing a hill. This force acts on an object moving in a circle, directing it towards the center of the circle. It is what keeps the object moving in a circular motion rather than tangentially flying off the curve. When a motorcycle is at the top of the hill, the necessary centripetal force is provided by the weight of the motorcycle itself, due to the gravitational pull. If the motorcycle’s speed is too high, however, it will not maintain its path and might lose contact with the road. This is why calculating the maximum speed, as seen in the exercise, is essential.
  • Centripetal force always points towards the center of the circle.
  • This force does not exist on its own but is the result of other forces such as gravity.
  • In the motorcycle's case, it ensures the vehicle remains on its circular path over the hill's crest.
Understanding centripetal force helps in determining safe speeds for vehicles navigating curves or hills.
Gravitational Force
Gravitational force is one of the most familiar concepts, pulling objects towards the center of the Earth. This force is constant and plays a key role in the problem of the motorcycle on the hill. When the motorcycle is at the crest, gravitational force acts as the only contributor to the centripetal force needed for circular motion.
Gravity ensures that objects have weight and dictates how they move through space. Despite seeming simple, its role is integral for many calculations of motion, like those for the maximum speed in circular paths. For example:
  • The force of gravity is what provides the necessary downward pull on objects.
  • It ensures that an object like a motorcycle remains connected to the surface unless countered by enough opposing force.
Understanding gravitational force is essential for knowing how and why objects move in particular ways, especially in non-linear paths.
Newton's Second Law
Newton's Second Law of Motion provides the groundwork for understanding the relationship between an object's mass, the forces acting upon it, and its motion. In mathematical terms, it's denoted as \( F = ma \), which translates to force equals mass times acceleration.
For our motorcycle problem, this law helps explain how the gravitational force contributes to the centripetal force necessary for circular motion at the hill's crest. By setting up the equation \( mg = \frac{mv^2}{r} \), we connect gravitational force (\( mg \)) with centripetal force requirements (\( \frac{mv^2}{r} \)).
  • The law helps calculate how much speed the motorcycle can sustain without leaving contact with the road.
  • It also shows the direct proportionality between force and acceleration, essential when managing speeds over curves.
  • Newton's Second Law clarifies how mass and forces interplay, crucial for understanding motion on circular paths.
With this fundamental principle, predicting how an object will behave under certain forces becomes a more straightforward process. The law provides clarity when we need to calculate and ensure safe velocities, like with a motorcycle on a hilly curve.

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Most popular questions from this chapter

A stone is tied to a string (length 1.10 m) and whirled in a circle at the same constant speed in two different ways. First, the circle is horizontal and the string is nearly parallel to the ground. Next, the circle is vertical. In the vertical case the maximum tension in the string is 15.0% larger than the tension that exists when the circle is horizontal. Determine the speed of the stone.

Two banked curves have the same radius. Curve A is banked at an angle of \(13^{\circ},\) and curve \(B\) is banked at an angle of \(19^{\circ} .\) A car can travel around curve \(A\) without relying on friction at a speed of 18 \(\mathrm{m} / \mathrm{s}\) . At what speed can this car travel around curve \(\mathrm{B}\) without relying on friction?

An 830-kg race car can drive around an unbanked turn at a maximum speed of 58 m/s without slipping. The turn has a radius of curvature of 160 m. Air flowing over the car’s wing exerts a downward-pointing force (called the downforce) of 11 000 N on the car. (a) What is the coefficient of static friction between the track and the car’s tires? (b) What would be the maximum speed if no downforce acted on the car?

A rigid massless rod is rotated about one end in a horizontal circle. There is a particle of mass \(m_{1}\) attached to the center of the rod and a particle of mass \(m_{2}\) attached to the outer end of the rod. The inner section of the rod sustains a tension that is three times as great as the tension that the outer section sustains. Find the ratio \(m_{1} / m_{2}\) .

A satellite is in a circular orbit about the earth \(\left(M_{\mathrm{E}}=5.98 \times\right.\) \(10^{24} \mathrm{kg} .\) The period of the satellite is \(1.20 \times 10^{4} \mathrm{s}\) . What is the speed at which the satellite travels?

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