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The central bright fringe in a single-slit diffraction pattern has a width that equals the distance between the screen and the slit. Find the ratio \(\lambda / W\) of the wavelength \(\lambda\) of the light to the width \(W\) of the slit.

Short Answer

Expert verified
\( \frac{\lambda}{W} = \frac{1}{2} \).

Step by step solution

01

Understanding the Problem

We have a single-slit diffraction pattern where the central bright fringe has a width equal to the distance between the screen and the slit. We need to find the ratio \( \frac{\lambda}{W} \), where \( \lambda \) is the wavelength of the light and \( W \) is the width of the slit.
02

Setting Up the Equation

The width \( \Delta y \) of the central bright fringe in a single-slit diffraction pattern is given by \( \Delta y = \frac{2\lambda L}{W} \), where \( L \) is the distance between the slit and the screen. In this problem, \( \Delta y = L \), so we substitute this into the equation.
03

Simplifying the Expression

Substituting \( \Delta y = L \) into \( \Delta y = \frac{2\lambda L}{W} \), we get \( L = \frac{2\lambda L}{W} \). Notice that \( L \) appears on both sides of the equation.
04

Solving for \( \lambda / W \)

Divide both sides of the equation \( L = \frac{2\lambda L}{W} \) by \( L \) (assuming \( L eq 0 \)) to isolate the terms involving \( \lambda \): \[ 1 = \frac{2\lambda}{W} \]. Rearrange this to solve for the ratio: \[ \frac{\lambda}{W} = \frac{1}{2} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Central Bright Fringe
In single-slit diffraction, the central bright fringe, also known as the central maximum, is a prominent feature. It represents the broadest and most luminous band in the diffraction pattern. This occurs at the center where light waves constructively interfere. The central bright fringe is simply the area on the screen where the most light is diffracted to. It is flanked by alternating dark and bright fringes.

Understanding the size of this central region is crucial. In our context, the width of the central bright fringe is equal to the distance from the slit to the screen. This means that all light waves converge optimally at this focal point, leading to the brightest possible display of light.

The depiction of this width as a function of the slit parameters forms the basis of many diffraction problems and provides insight into the behavior of light as a wave.
Wavelength
Wavelength (\( \lambda \)) is a fundamental property of waves, including light. It is the distance between consecutive peaks of the wave pattern. In diffraction, the wavelength determines how light spreads out after passing through a slit. A longer wavelength results in a more substantial spreading of the light waves.
  • Longer wavelengths typically lead to broader diffraction patterns.
  • They also affect the positioning and width of the central and additional bright fringes.
In the exercise, we relate the wavelength to slit width to find the ratio \( \frac{\lambda}{W} \). This ratio indicates the relative size of the central fringe, dictated in part by the wavelength of the light used.
Slit Width
Slit width (\( W \)) is instrumental in shaping the diffraction pattern. It refers to the physical opening through which light passes before diffracting. The width of the slit determines the extent to which light divides and spreads out. As slit width decreases:
  • The central bright fringe becomes wider, showcasing more diffraction.
  • More light waves interfere constructively and destructively, altering the pattern's arrangement.
The exercise presents a scenario where the slit width affects the spread of the central bright fringe. By establishing a connection between the slit width and the wavelength, we calculate the ratio \( \frac{\lambda}{W} \) to understand how closely or widely the light spreads.
Diffraction Pattern
A diffraction pattern is a series of light and dark bands formed due to the bending of light waves around obstacles. In the case of single-slit diffraction, light waves interfere with each other, causing a distinctive pattern of alternating bright and dark streaks.
  • The central bright fringe is the most significant feature in a diffraction pattern.
  • Secondary maxima and minima surround the central bright fringe, decreasing in intensity outwardly.
  • The pattern reflects the interaction of light’s waveform character with physical barriers like slits.
Understanding the diffraction pattern helps in deriving various physical properties of light, including fringe width and intensity. Identifying the central and surrounding fringes aids in practical applications, like determining the resolution capabilities of optical instruments.

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Most popular questions from this chapter

A spotlight sends red light (wavelength \(=694.3 \mathrm{nm})\) to the moon. At the surface of the moon, which is \(3.77 \times 10^{8} \mathrm{~m}\) away, the light strikes a reflector left there by astronauts. The reflected light returns to the earth, where it is detected. When it leaves the spotlight, the circular beam of light has a diameter of about \(0.20 \mathrm{~m},\) and diffraction causes the beam to spread as the light travels to the moon. In effect, the first circular dark fringe in the diffraction pattern defines the size of the central bright spot on the moon. Determine the diameter (not the radius) of the central bright spot on the moon.

There are 5620 lines per centimeter in a grating that is used with light whose wavelength is 471 nm. A flat observation screen is located at a distance of 0.750 m from the grating. What is the minimum width that the screen must have so the centers of all the principal maxima formed on either side of the central maximum fall on the screen?

A hunter who is a bit of a braggart claims that from a distance of 1.6 km he can selectively shoot either of two squirrels who are sitting ten centimeters apart on the same branch of a tree. What’s more, he claims that he can do this without the aid of a telescopic sight on his rifle. (a) Determine the diameter of the pupils of his eyes that would be required for him to be able to resolve the squirrels as separate objects. In this calculation use a wavelength of 498 nm (in vacuum) for the light. (b) State whether his claim is reasonable, and provide a reason for your answer. In evaluating his claim, consider that the human eye automatically adjusts the diameter of its pupil over a typical range of 2 to 8 mm, the larger values coming into play as the lighting becomes darker. Note also that under dark conditions, the eye is most sensitive to a wavelength of 498 nm.

The dark fringe for \(m=0\) in a Young's double-slit experiment is located at an angle of \(\theta=15^{\circ} .\) What is the angle that locates the dark fringe for \(m=1 ?\)

At most, how many bright fringes can be formed on either side of the central bright fringe when light of wavelength 625 \(\mathrm{nm}\) falls on a double slit whose slit separation is \(3.76 \times 10^{-6} \mathrm{m} ?\)

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