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At most, how many bright fringes can be formed on either side of the central bright fringe when light of wavelength 625 \(\mathrm{nm}\) falls on a double slit whose slit separation is \(3.76 \times 10^{-6} \mathrm{m} ?\)

Short Answer

Expert verified
At most, 6 bright fringes can be formed on either side of the central fringe.

Step by step solution

01

Identify the Formula

To determine the number of bright fringes on either side of the central fringe in a double-slit experiment, we use the formula for the position of bright fringes: \( d \sin\theta = m\lambda \), where \(d\) is the slit separation, \(\lambda\) is the wavelength, \(m\) is the fringe order (an integer), and \(\theta\) is the angle of diffraction.
02

Set Up the Fringe Condition

The maximum angle \( \theta \) occurs when \( \sin \theta = 1 \). Therefore, the condition for the maximum number of fringes is \( m \lambda \leq d \). We rearrange this to find \( m \leq \frac{d}{\lambda} \).
03

Calculate the Maximum Order

Plug the known values into the condition: \( \lambda = 625 \times 10^{-9} \text{ m} \) and \( d = 3.76 \times 10^{-6} \text{ m} \). Calculate \( \frac{d}{\lambda} = \frac{3.76 \times 10^{-6}}{625 \times 10^{-9}} \).
04

Perform the Calculation

Calculate the fraction: \( \frac{3.76 \times 10^{-6}}{625 \times 10^{-9}} = 6.016 \). As we cannot have a non-integer number of fringes, we take the largest integer less than or equal to \(6.016\), which is 6.
05

Conclude the Maximum Number

Thus, there can be at most 6 bright fringes on either side of the central bright fringe.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Fringe Order in Double-Slit Experiments
In the context of the double-slit experiment, the term 'fringe order' refers to the integer values that describe the positions of bright and dark fringes relative to the central bright fringe. Each bright fringe corresponds to a specific order, symbolized as \( m \), where \( m \) is an integer. These fringes result from constructive interference of light waves passing through the two slits. The central bright fringe is considered the zeroth order fringe, \( m = 0 \). Bright fringes appear on either side of the central fringe, designated by positive and negative values of \( m \) (e.g., \( m = 1, 2, ... \) for fringes on one side, and \( m = -1, -2, ... \) on the opposite side). Key points about fringe order:
  • Each fringe order corresponds to a path difference that is an integer multiple of the wavelength, \( m\lambda \).
  • The maximum number of fringes visible is determined by the width of the slits and the wavelength of the light.
Understanding fringe order helps in predicting where the fringes will form and how many will be visible given specific experimental conditions.
The Role of Diffraction Angle in the Experiment
The diffraction angle, often denoted as \( \theta \), is crucial in determining the positions of the bright and dark fringes in a double-slit experiment. It is the angle at which light from the slits intersects to construct an interference pattern. Diffraction occurs when waves bend around the edges of the slits, allowing the slit-separated waves to overlap and interfere. Using the condition for bright fringes, the formula \( d \sin \theta = m\lambda \) helps us calculate \( \theta \) for each fringe order \( m \). Here, \( \sin \theta \) indicates the path difference between waves from each slit that leads to constructive interference:
  • When \( \sin \theta = 1 \), this creates the maximum diffraction angle where fringes no longer appear beyond this value.
  • At smaller angles, more fringes can be observed as \( \theta \) decreases, allowing more overlapping waves to construct additional fringes.
Understanding this angle enhances comprehension of how light waves interact within the slits to produce the interference pattern observed.
Exploring the Interference Pattern
The interference pattern in the double-slit experiment is the observable distribution of alternating bright and dark fringes on a screen, caused by the overlapping of waves. This pattern is a direct result of wave interference and is visible evidence of the wave nature of light.Constructive and Destructive Interference
  • Constructive interference occurs when the path difference between light waves from the slits is an integer multiple of the wavelength (\( m\lambda \)), resulting in bright fringes.
  • Destructive interference arises when the path difference is a half-integer multiple of the wavelength, causing dark fringes to appear.
Pattern Characteristics
  • The central bright fringe is always aligned with the original light direction and is usually the brightest.
  • Brightness and spacing depend on the wavelength of the light and the slit separation.
By analyzing the interference pattern, experimenters can measure wavelengths and understand light's wave properties. Thus, the pattern isn't just a display but a source of scientific insights, illustrating fundamental wave interactions.

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Most popular questions from this chapter

Light that has a wavelength of 668 nm passes through a slit \(6.73 \times 10^{-6} \mathrm{m}\) wide and falls on a screen that is 1.85 \(\mathrm{m}\) away. What is the distance on the screen from the center of the central bright fringe to the third dark fringe on either side?

For a wavelength of \(420 \mathrm{nm},\) a diffraction grating produces a bright fringe at an angle of \(26^{\circ} .\) For an unknown wavelength, the same grating produces a bright fringe at an angle of \(41^{\circ} .\) In both cases the bright fringes are of the same order \(m .\) What is the unknown wavelength?

The dark fringe for \(m=0\) in a Young's double-slit experiment is located at an angle of \(\theta=15^{\circ} .\) What is the angle that locates the dark fringe for \(m=1 ?\)

A large group of football fans comes to the game with colored cards that spell out the name of their team when held up simultaneously. Most of the cards are colored blue \(\left(\lambda_{\text { vacum }}=480 \mathrm{nm}\right)\) . When displayed, the average distance between neighboring cards is 5.0 \(\mathrm{cm} .\) If the cards are to blur together into solid blocks of color when viewed by a spectator at the other end of the stadium \((160 \mathrm{m}\) away), what must be the maximum diameter (in \(\mathrm{mm}\) ) of the spectator's pupils?

In a Young's double-slit experiment, the seventh dark fringe is located 0.025 \(\mathrm{m}\) to the side of the central bright fringe on a flat screen, which is 1.1 \(\mathrm{m}\) away from the slits. The separation between the slits is \(1.4 \times 10^{-4} \mathrm{m} .\) What is the wavelength of the light being used?

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