/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 A planar coil of wire has a sing... [FREE SOLUTION] | 91Ó°ÊÓ

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A planar coil of wire has a single turn. The normal to this coil is parallel to a uniform and constant (in time) magnetic field of 1.7 \(\mathrm{T}\) . An emf that has a magnitude of 2.6 \(\mathrm{V}\) is induced in this coil because the coil's area \(A\) is shrinking. What is the magnitude of \(\Delta A / \Delta t,\) which is the rate (in \(\mathrm{m}^{2} / \mathrm{s} )\) at which the area changes?

Short Answer

Expert verified
The area changes at approximately -1.529 m²/s.

Step by step solution

01

Understand the Problem

To solve this, we need to use Faraday's law of electromagnetic induction, which states that the induced emf in a coil is equal to the negative rate of change of magnetic flux through the coil. Here, the coil has a magnetic field of 1.7 T and an emf of 2.6 V.
02

Write Faraday's Law

Faraday's law for this coil is given by the equation: \( \text{emf} = - \frac{d\Phi}{dt} \), where \( \Phi \) is the magnetic flux. \( \Phi = B \times A \times \cos(\theta) \). Since the norm of the coil is parallel to the magnetic field, \( \theta = 0 \) and \( \cos(0) = 1 \), so \( \Phi = B \times A \). Thus, the equation becomes \( \text{emf} = - B \times \frac{dA}{dt} \).
03

Solve for Rate of Area Change

Rearrange the equation \( \text{emf} = - B \times \frac{dA}{dt} \) to solve for \( \frac{dA}{dt} \): \( \frac{dA}{dt} = - \frac{\text{emf}}{B} \).
04

Substitute Known Values

Substitute the given values \( \text{emf} = 2.6 \) V and \( B = 1.7 \) T into the equation: \[ \frac{dA}{dt} = - \frac{2.6}{1.7} \].
05

Calculate the Result

Perform the division to obtain: \( \frac{dA}{dt} \approx -1.529 \). This is the rate at which the area of the coil is decreasing in \( \text{m}^2/\text{s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux
Magnetic flux is a measure of the quantity of magnetism, taking account of the strength and extent of a magnetic field. Imagine lines of a magnetic field passing through a surface, like wind blowing through a window. The amount of magnetic field lines that pass through the window is equivalent to the magnetic flux.
Mathematically, magnetic flux (\( \Phi \)) through a surface is calculated using the equation:
  • \( \Phi = B \times A \times \cos(\theta) \)
Here, \( B \) is the magnetic field strength measured in Tesla (T), \( A \) is the area the field is passing through, and \( \theta \) is the angle between the magnetic field lines and the perpendicular (normal) to the surface.
In our original exercise, \( \theta = 0 \) since the field lines are parallel to the normal, making \( \cos(0) = 1 \). This simplifies the flux calculation to \( \Phi = B \times A\). Magnetic flux plays a crucial role in determining induced emf as it is directly related to how the magnetic field interacts with surfaces like coils.
Induced emf
Induced emf, or electromotive force, is the voltage generated in a coil or conductor exposed to changing magnetic flux. This fundamental concept of electromagnetism is explained through Faraday's law of electromagnetic induction. It states that the induced emf in a closed loop is equal to the negative rate of change of the magnetic flux through the loop. Induced emf is why we can generate electricity by moving magnets near coils.
The formula for Faraday’s law is:
  • \( \text{emf} = - \frac{d\Phi}{dt} \)
This equation shows that a change in magnetic flux over time causes an emf. The negative sign in the equation indicates the direction of the induced emf, opposing the change in flux, a principle known as Lenz's Law. For the problem at hand, since the flux changes due to a shrinking area, the induced emf helps to determine the rate of area change.
Rate of Change of Area
The rate of change of area, particularly in the context of electromagnetic induction, refers to how fast the area within a magnetic field changes. This is crucial in calculating the induced emf. If you imagine a loop of wire with a shrinking area, it means fewer magnetic field lines pass through it over time, altering the magnetic flux.
In our exercise, the rate at which the area shrinks (\( \frac{dA}{dt} \)) needed to be calculated. Using Faraday's Law, the formula for induced emf became:
  • \( \text{emf} = -B \times \frac{dA}{dt} \)
By rearranging this formula, we get an expression for the rate of change of area:
  • \( \frac{dA}{dt} = - \frac{\text{emf}}{B} \)
Inserting the values provided (\( \text{emf} = 2.6 \) V and \( B = 1.7 \) T), the calculated rate of area change was approximately \(-1.529\) square meters per second, indicating how fast the coil's area is decreasing.

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Most popular questions from this chapter

A vacuum cleaner is plugged into a \(120.0-\mathrm{V}\) socket and uses 3.0 \(\mathrm{A}\) of current in normal operation when the back emf generated by the electric motor is 72.0 \(\mathrm{V}\) . Find the coil resistance of the motor.

A uniform magnetic field is perpendicular to the plane of a single-turn circular coil. The magnitude of the field is changing, so that an emf of 0.80 \(\mathrm{V}\) and a current of 3.2 \(\mathrm{A}\) are induced in the coil. The wire is then reformed into a single-turn square coil, which is used in the same magnetic field (again perpendicular to the plane of the coil and with a magnitude changing at the same rate). What emf and current are induced in the square coil?

ssm A \(3.0-\mu \mathrm{F}\) capacitor has a voltage of 35 \(\mathrm{V}\) between its plates. What must be the current in a \(5.0-\mathrm{mH}\) inductor so that the energy stored in the inductor equals the energy stored in the capacitor?

The battery charger for an MP3 player contains a step-down trans- former with a turns ratio of 1: 32, so that the voltage of 120 V available at a wall socket can be used to charge the battery pack or operate the player. What voltage does the secondary coil of the transformer provide?

A 0.80 -m aluminum bar is held with its length parallel to the east-west direction and dropped from a bridge. Just before the bar hits the river below, its speed is 22 \(\mathrm{m} / \mathrm{s}\) , and the emf induced across its length is \(6.5 \times 10^{-4} \mathrm{V}\) . Assuming the horizontal component of the earth's magnetic field at the location of the bar points directly north, (a) determine the magnitude of the horizontal component of the earth's magnetic field, and (b) state whether the east end or the west end of the bar is positive.

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