/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 A uniform magnetic field is perp... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A uniform magnetic field is perpendicular to the plane of a single-turn circular coil. The magnitude of the field is changing, so that an emf of 0.80 \(\mathrm{V}\) and a current of 3.2 \(\mathrm{A}\) are induced in the coil. The wire is then reformed into a single-turn square coil, which is used in the same magnetic field (again perpendicular to the plane of the coil and with a magnitude changing at the same rate). What emf and current are induced in the square coil?

Short Answer

Expert verified
Induced emf: 0.63 V, Current: 2.51 A.

Step by step solution

01

Understand the Problem

We have a circular coil that is replaced by a square coil. We know the induced emf and current for the circular coil. We want to find the induced emf and current for the square coil in the same changing magnetic field.
02

Use Faraday's Law of Induction

Faraday's Law states that the induced emf (\( \mathcal{E} \)) in the coil is given by \( \mathcal{E} = - \frac{d\Phi_B}{dt} \), where \( \Phi_B \) is the magnetic flux. Since the coil is changing from a circle to a square, only the area changes, but the rate of change of magnetic flux \( \frac{d\Phi_B}{dt} \) remains constant.
03

Analyze the Circular Coil

Given the induced emf is 0.80 V and current is 3.2 A, calculate the resistance \( R = \frac{\mathcal{E}}{I} = \frac{0.80\, \text{V}}{3.2\, \text{A}} = 0.25\, \text{Ohms} \).
04

Determine the Area Ratio

Let the radius of the circular coil be \( r \). The area of the circle is \( A = \pi r^2 \). When reformed into a square, the side of the square is \( s \) such that \( 4s = 2\pi r \Rightarrow s = \frac{\pi r}{2} \). The area of the square is \( A_s = s^2 = \left(\frac{\pi r}{2}\right)^2 = \frac{\pi^2 r^2}{4} \).
05

Calculate the Emf in the Square Coil

The changing magnetic flux depends on area; hence, \( \frac{\mathcal{E}_{\text{square}}}{\mathcal{E}_{\text{circle}}} = \frac{A_s}{A_c} = \frac{\frac{\pi^2 r^2}{4}}{\pi r^2} = \frac{\pi}{4} \). Thus, \( \mathcal{E}_{\text{square}} = \mathcal{E}_{\text{circle}} \times \frac{\pi}{4} = 0.80 \times \frac{\pi}{4} \approx 0.80 \times 0.785 = 0.628\, V \).
06

Calculate the Current in the Square Coil

Using Ohm's Law, \( I = \frac{\mathcal{E}}{R} \), the resistance of the wire stays the same. Thus, \( I_{\text{square}} = \frac{\mathcal{E}_{\text{square}}}{R} = \frac{0.628\, \text{V}}{0.25\, \text{Ohms}} = 2.512\, \text{A} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux
Magnetic flux is an important concept in understanding electromagnetic induction. It is represented by the symbol \( \Phi_B \) and can be thought of as the amount of magnetic field passing through a given area. Imagine you have a paper and there is a magnetic field going through it. The magnetic flux would be how much of that field is cutting across the paper.

The formula for magnetic flux is given by \( \Phi_B = B \cdot A \cdot \cos(\theta) \), where:
  • \( B \) is the magnetic field strength (measured in Tesla).
  • \( A \) is the area through which the field lines pass.
  • \( \theta \) is the angle between the magnetic field and the normal (a perpendicular line) to the surface.
In this exercise, we consider the coil initially as a circle and then as a square while the field remains perpendicular, simplifying to \( \cos(\theta) = 1 \). Therefore, magnetic flux is directly related to the area in this exercise.
Induced EMF
The concept of induced electromotive force (emf) is central to understanding Faraday's Law of Induction. This law helps us comprehend how changing magnetic fields can induce an electric current. According to Faraday's Law, the induced emf in any closed loop is equal to the negative rate of change of magnetic flux through the loop.

This is mathematically expressed as \( \mathcal{E} = - \frac{d\Phi_B}{dt} \). The negative sign indicates the direction of the induced emf opposes the change in flux, known as Lenz's Law. This is what we experience when a current is induced in the circular coil and also later in the square coil.

In the given exercise, because the rate of change of magnetic flux remains constant, any change in geometry from circular to square will affect the emf proportionately.
Ohm's Law
Ohm's Law is a fundamental principle in understanding electric circuits. It states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points. This relationship is given by the formula \( I = \frac{V}{R} \), where:
  • \( I \) is the current in amperes (A).
  • \( V \) is the voltage across the conductor in volts (V).
  • \( R \) is the resistance of the conductor in ohms (Ω).
In the scenario with the coil, we first compute the resistance using the circular coil's known emf and current. This resistance is utilized again to find the current in the square coil once its emf is calculated, showcasing the unwavering principles of Ohm's Law.
Coil Geometry
The shape and size of the coil significantly affect the induced emf as they determine the area crucial for calculating magnetic flux. Initially, the coil is circular, and we derive the area using \( A = \pi r^2 \), where \( r \) is the radius.

Upon reshaping the coil into a square, the side length becomes \( s \) such that the perimeter remains constant. Using geometry, \( s = \frac{\pi r}{2} \), we then find the area of the square \( A_s = s^2 = \left(\frac{\pi r}{2}\right)^2 \). This area change influences the new magnetic flux and consequently the induced emf.

By understanding these geometric transformations, we can calculate the induced emf in different coil shapes exposed to the same magnetic conditions.
Electric Current
Electric current in this context results from the induced emf in the coil. The current is the flow of electric charge, and in a circuit, it’s driven by the voltage (emf) pushing it through a resistance.

In our exercise, the initial current for the circular coil is known, allowing us to define the resistance of the wire using Ohm's Law. When switching to the square coil, the emf changes due to the altered area, but the resistance remains the same. Consequently, the current through the square coil is recalculated using \( I = \frac{\mathcal{E}}{R} \), clearly demonstrating how current varies with emf if resistance is unchanged.

Understanding this principle is crucial for applications where different coil shapes are used, such as in transformers and inductive charging systems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

ssm A generating station is producing \(1.2 \times 10^{6} \mathrm{W}\) of power that is to be sent to a small town located 7.0 \(\mathrm{km}\) away. Each of the two wires that comprise the transmission line has a resistance per kilometer of \(5.0 \times 10^{-2} \Omega / \mathrm{km}\) (a) Find the power used to heat the wires if the power is transmitted at 1200 \(\mathrm{V}\) . (b) A \(100 : 1\) step-up transformer is used to raise the voltage before the power is transmitted. How much power is now used to heat the wires?

In some places, insect "zappers," with their blue lights, are a familiar sight on a summer's night. These devices use a high voltage to electrocute insects. One such device uses an ac voltage of 4320 \(\mathrm{V}\) , which is obtained from a standard \(120.0-\mathrm{V}\) outlet by means of a transformer. If the primary coil has 21 turns, how many turns are in the secondary coil?

You need to design a \(60.0-\mathrm{Hz}\) ac generator that has a maximum emf of 5500 \(\mathrm{V}\) . The generator is to contain a 150 -turn coil that has an area per turn of 0.85 \(\mathrm{m}^{2}\) . What should be the magnitude of the magnetic field in which the coil rotates?

A magnetic field has a magnitude of 0.078 \(\mathrm{T}\) and is uniform over a circular surface whose radius is 0.10 \(\mathrm{m}\) . The field is oriented at an angle of \(\phi=25^{\circ}\) with respect to the normal to the surface. What is the magnetic flux through the surface?

Two coils of wire are placed close together. Initially, a current of 2.5 \(\mathrm{A}\) exists in one of the coils, but there is no current in the other. The current is then switched off in a time of \(3.7 \times 10^{-2}\) s. During this time, the average emf induced in the other coil is 1.7 \(\mathrm{V}\) . What is the mutual inductance of the two-coil system?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.