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A 60.0-W lamp is placed in series with a resistor and a 120.0-V source. If the voltage across the lamp is 25 V, what is the resistance R of the resistor?

Short Answer

Expert verified
The resistance of the resistor is approximately 39.58 ohms.

Step by step solution

01

Calculate the Current in the Circuit

First, we need to find the current through the lamp. Given that the lamp is 60.0 W and the voltage across it is 25 V, we can use the power formula for electrical devices: \[ P = V imes I \]where \(P\) is the power, \(V\) is the voltage, and \(I\) is the current. Rearranging for \(I\), we get:\[ I = \frac{P}{V} = \frac{60.0}{25} = 2.4 \, \text{A} \]The current in the series circuit is 2.4 A.
02

Calculate Total Voltage Drop Across the Resistor

In a series circuit, the total voltage supplied by the source (120 V) is the sum of the voltages across each component:\[ V_{\text{total}} = V_{\text{lamp}} + V_{\text{resistor}} \]where \(V_{\text{lamp}} = 25 \, V\) and \(V_{\text{total}} = 120 \, V\). Therefore:\[ V_{\text{resistor}} = V_{\text{total}} - V_{\text{lamp}} = 120 - 25 = 95 \, V \]
03

Calculate the Resistance of the Resistor

Now that we have the voltage across the resistor and the current through it, we can find the resistance using Ohm’s law:\[ V = I \times R \]Rearranging for \(R\), we have:\[ R = \frac{V}{I} = \frac{95 \, V}{2.4 \, A} \approx 39.58 \, \Omega \]Thus, the resistance \(R\) of the resistor is approximately 39.58 ohms.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ohm's Law
Ohm's Law is a fundamental principle in the study of electric circuits. It explains the relationship between voltage, current, and resistance in an electrical circuit. Mathematically, Ohm's Law is expressed as:\[ V = I \times R \]where:
  • \(V\) is the voltage (in volts)
  • \(I\) is the current (in amperes)
  • \(R\) is the resistance (in ohms)
This formula tells us that the voltage across a conductor is equal to the product of the current flowing through it and its resistance.
Ohm's Law is crucial for calculating unknown quantities in a circuit, such as finding the voltage across a component, if the current and resistance are known. It's also useful to determine the necessary resistance to achieve a desired current or voltage in a circuit. In our exercise, we used Ohm's Law to find the resistance of the resistor once we knew the voltage across it and the current through the circuit.
Series Circuit
A series circuit is a type of electric circuit in which components are connected end-to-end, forming a single path for the current to flow. This means:
  • The same current flows through all components
  • The total voltage in the circuit is divided among the components
  • The total resistance is the sum of individual resistances
In a series circuit, each component's voltage is added up to equal the total voltage from the source. In our example, a series circuit was set up with a 60.0-W lamp and a resistor connected to a 120.0-V source.
The voltage across the lamp was known, which allowed us to deduct the remaining voltage across the resistor. Understanding how series circuits work helps solve problems where both current and voltage distribution need to be comprehended.
Electrical Resistance
Electrical resistance is a measure of how much an object opposes the flow of electric current. It is a crucial factor in determining how much current will flow through a component for a given voltage. Resistance is measured in ohms (\(\Omega\)).
Factors that affect resistance include:
  • Material: Conductors like copper have low resistance, while insulators have high resistance
  • Length: Longer components have higher resistance
  • Cross-sectional Area: Wider components have lower resistance
  • Temperature: Higher temperatures typically increase resistance
In the exercise, we calculated the resistance of a resistor using the voltage across it and the current flowing through it, by applying Ohm's Law. This understanding is vital for designing circuits based on specific requirements of current and voltage.
Power Formula in Electricity
The power formula in electricity is a basic principle used to determine how much energy is consumed or the rate of doing work in an electrical circuit. Power is measured in watts (W) and is given by the formula:\[ P = V \times I \]Here:
  • \(P\) is the power
  • \(V\) is the voltage
  • \(I\) is the current
The formula can be rearranged based on which quantity is unknown. In our exercise, we used it to find the current through the lamp, by rearranging it to solve for current as \(I = \frac{P}{V}\).
Understanding this formula helps in efficiently managing energy use in electrical devices and systems. It provides insights into how much power a device will consume when operating under certain voltage and current conditions. This is particularly important for ensuring that electrical components are used within their power limits to prevent damage.

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Most popular questions from this chapter

The rms current in a copy machine is \(6.50 \mathrm{A},\) and the resistance of the machine is 18.6\(\Omega\) . What are \((\mathrm{a})\) the average power and \((\mathrm{b})\) the peak power delivered to the machine?

You have three capacitors: \(C_{1}=67 \mu \mathrm{F}, C_{2}=45 \mu \mathrm{F},\) and \(C_{3}=33 \mu \mathrm{F}\) . Determine the maximum equivalent capacitance you can obtain by connecting two of the capacitors in parallel and then connecting the parallel combination in series with the remaining capacitor.

A car battery has a rating of 220 ampere \cdothours (A \(\cdot \mathrm{h} ) .\) This rating is one indication of the total charge that the battery can provide to a circuit before failing. \(\quad\) (a) What is the total charge (in coulombs) that this battery can provide? \(\quad\) (b) Determine the maximum current that the battery can provide for 38 minutes.

To save on heating costs, the owner of a greenhouse keeps 660 kg of water around in barrels. During a winter day, the water is heated by the sun to \(10.0^{\circ} \mathrm{C}\) . During the night the water freezes into ice at \(0.0^{\circ} \mathrm{C}\) in nine hours. What is the minimum ampere rating of an electric heating system \((240 \mathrm{V})\) that would provide the same heating effect as the water does?

When a light bulb is connected across the terminals of a battery, the battery delivers 24 \(\mathrm{W}\) of power to the bulb. A voltage of 11.8 \(\mathrm{V}\) exists between the terminals of the battery, which has an internal resistance of 0.10\(\Omega\) . What is the emf of the battery?

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