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Three resistors, \(25,45,\) and \(75 \Omega,\) are connected in series, and a \(0.51-\mathrm{A}\) current passes through them. What are \((\text { a ) the equivalent }\) resistance and \((b)\) the potential difference across the three resistors?

Short Answer

Expert verified
(a) Equivalent resistance is 145 Ω; (b) Potential difference is 73.95 V.

Step by step solution

01

Understanding Series Resistors

When resistors are connected in series, their resistances add up. The formula to calculate the equivalent resistance \( R_{eq} \) of resistors in series is:\[ R_{eq} = R_1 + R_2 + R_3 \]where \( R_1 = 25 \ \Omega \), \( R_2 = 45 \ \Omega \), and \( R_3 = 75 \ \Omega \).
02

Calculate the Equivalent Resistance

Substitute the given resistances into the formula:\[ R_{eq} = 25 + 45 + 75 = 145 \ \Omega \]. Thus, the equivalent resistance is \( 145 \ \Omega \).
03

Understand Ohm's Law

Ohm's Law relates voltage (V), current (I), and resistance (R) with the formula \( V = IR \). This formula will be used to find the potential difference across the resistors.
04

Calculate the Potential Difference

The current passing through the resistors is given as \( 0.51 \ A \). Using Ohm's Law and the equivalent resistance calculated, the potential difference (V) can be found with:\[ V = I \times R_{eq} = 0.51 \times 145 = 73.95 \ V \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equivalent Resistance
When dealing with circuits, understanding how resistors combine is crucial. In a series circuit, resistors are aligned end-to-end in a single path for current to flow. This configuration gives rise to what is known as **equivalent resistance**. In simple terms, it is the total resistance that a single resistor would have to have to replace all the resistors in the series without altering the circuit's behavior.

To find the equivalent resistance of resistors in series, we add them together. The formula is:
  • \( R_{eq} = R_1 + R_2 + R_3 + \ldots \)
For example, if we have three resistors with resistances of \(25 \Omega\), \(45 \Omega\), and \(75 \Omega\) connected in series, the equivalent resistance is:
  • \( R_{eq} = 25 + 45 + 75 = 145 \Omega \)
This means the circuit behaves as if a single resistor of \(145 \Omega\) is present, greatly simplifying calculations involving the circuit.
Ohm's Law
Ohm's Law is a foundational principle in understanding electrical circuits. It describes the relationship between voltage (V), current (I), and resistance (R) with the simple formula:
  • \( V = IR \)
This equation tells us that the potential difference across a resistor increases with higher resistance or a larger current. It's like how the water pressure in a hose increases if you tighten the nozzle (increased resistance) or if you open the faucet wider (increased current).

Ohm's Law is instrumental when dealing with complex circuits, as long as we know any two of the quantities, the third can be easily calculated. In our example with series resistors having an equivalent resistance of \(145 \Omega\) and a current of \(0.51\ A\), the potential difference across the resistors can be found using:
  • \( V = 0.51 \times 145 = 73.95\ V \)
Potential Difference
The potential difference, often referred to as voltage, is essentially the "push" that drives the current through the circuit. Imagine it as the pressure that makes water flow through pipes. In electrical terms, it is the energy difference per unit charge between two points in the circuit.

Using Ohm's Law, the potential difference across components in a circuit can be calculated easily if you know the current flowing and the total resistance, like in the case of resistors in series. For the example, with an equivalent resistance of \(145 \Omega\) and a current of \(0.51\ A\), the voltage can be derived as:
  • \( V = I \times R_{eq} = 0.51 \times 145 = 73.95\ V \)
This result tells us that a total of \(73.95\ V\) is required to drive the given current through the series circuit of resistors.
Resistors in Series
Resistors in series are like groups of people holding hands in a chain; current must pass through one to get to the next. This setup causes the total resistance in the circuit to be the sum of each resistance in the line-up. Such a configuration is extremely useful for achieving desired resistance values that are not found as single components.

To understand how this works, imagine you have three resistors: \(25 \Omega\), \(45 \Omega\), and \(75 \Omega\), lined up in series. Each adds its own resistance to the circuit. The current flowing through this assembly faces each resistor's opposition in turn, so they effectively behave as a single resistor with:
  • \( R_{eq} = 25 + 45 + 75 = 145 \Omega \)
This simplifies the circuit analysis process and allows for easy calculations using basic principles like Ohm's Law.

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Most popular questions from this chapter

The current in a series circuit is 15.0 A. When an additional \(8.00-\Omega\) resistor is inserted in series, the current drops to 12.0 \(\mathrm{A}\) . What is the resistance in the original circuit?

A coffee-maker \((14 \Omega)\) and a toaster \((19 \Omega)\) are connected in parallel to the same \(120-\mathrm{V}\) outlet in a kitchen. How much total power is supplied to the two appliances when both are turned on?

Two wires have the same cross-sectional area and are joined end to end to form a single wire. One is tungsten, which has a temperature coefficient of resistivity of \(\alpha=0.0045\left(\mathrm{C}^{\circ}\right)^{-1}\) . The other is carbon, for which \(\alpha=-0.0005\left(\mathrm{C}^{\circ}\right)^{-1} .\) The total resistance of the composite wire is the sum of the resistances of the pieces. The total resistance of the composite does not change with temperature. What is the ratio of the lengths of the tungsten and carbon sections? Ignore any changes in length due to thermal expansion.

A \(60.0-\Omega\) resistor is connected in parallel with a \(120.0-\Omega\) resistor. This parallel group is connected in series with a \(20.0-\Omega\) resistor. The total combination is connected across a \(15.0-\mathrm{V}\) battery. Find (a) the current and \(\quad(b)\) the power delivered to the \(120.0-\Omega\) resistor.

Three resistors are connected in series across a battery. The value of each resistance and its maximum power rating are as follows: 2.0\(\Omega\) and \(4.0 \mathrm{W}, 12.0 \Omega\) and \(10.0 \mathrm{W},\) and 3.0\(\Omega\) and 5.0 \(\mathrm{W}\) . (a) What is the greatest voltage that the battery can have without one of the resistors burning up? (b) How much power does the battery deliver to the circuit in ( a \()\) ?

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