/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 For a standard production car, t... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

For a standard production car, the highest road-tested acceleration ever reported occurred in \(1993,\) when a Ford RS200 Evolution went from zero to 26.8 \(\mathrm{m} / \mathrm{s}(60 \mathrm{mi} / \mathrm{h})\) in 3.275 s. Find the magnitude of the car's acceleration.

Short Answer

Expert verified
The car's acceleration is approximately 8.18 m/s².

Step by step solution

01

Identify the known variables

We are given the initial velocity \( u = 0 \, \text{m/s} \), final velocity \( v = 26.8 \, \text{m/s} \), and the time \( t = 3.275 \, \text{s} \). We need to find the acceleration \( a \).
02

Use the formula for acceleration

The formula for acceleration \( a \) is given by:\[a = \frac{v - u}{t}\]where \( v \) is the final velocity, \( u \) is the initial velocity, and \( t \) is the time.
03

Substitute the known values into the formula

Substituting in the given values:\[a = \frac{26.8 \, \text{m/s} - 0 \, \text{m/s}}{3.275 \, \text{s}}\]Simplifying gives:\[a = \frac{26.8}{3.275}\]
04

Calculate the acceleration

Now, calculate the division:\[a \approx 8.18 \, \text{m/s}^2\]Thus, the magnitude of the car's acceleration is approximately \( 8.18 \, \text{m/s}^2 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is a branch of physics that describes the motion of objects without considering the forces causing them. It's like focusing on what happens, rather than why. In our context, analyzing the Ford RS200 Evolution's acceleration deals with understanding its change in motion over time.

When we consider kinematics, we focus on several key aspects of motion, specifically:
  • Displacement - How far the object has moved.
  • Velocity - The speed of the object in a given direction.
  • Acceleration - The rate at which the object's velocity changes.
The exercise is primarily focused on acceleration, which is crucial in defining how quickly a vehicle can increase its speed.

Understanding kinematics allows us to predict how an object will move from one point to another, which can be useful in designing vehicles, planning trips, or even predicting how fast a car can outrun another in a drag race. "Why did the car go from zero to 26.8 m/s in just 3.275 seconds?" is a kinematic inquiry.
Velocity
Velocity is a vector quantity, meaning it has both magnitude and direction. It's different from speed, which only has magnitude. In simple terms, while speed tells you how fast something is moving, velocity tells you how fast and in which direction.

For the Ford RS200 Evolution, we are given:
  • Initial velocity ( \( u \) ): 0 m/s
  • Final velocity ( \( v \) ): 26.8 m/s
The focus is on how the car's velocity changes from the initial to the final state.

Velocity is crucial because:
  • It helps in determining the car's direction of travel.
  • Understanding changes in velocity helps calculate acceleration.
In this context, the velocity change helps to find how rapidly the car reaches a certain speed, which is essential for performance evaluation.
Time
Time is a fundamental aspect of physics that, alongside space, creates the fabric in which motion occurs. In the realm of kinematics, time helps describe how far and fast something moves.

In our exercise, the time taken by the Ford RS200 Evolution to change its velocity is given as 3.275 seconds. Time here is not just a measure of how long the event takes place but also a key factor in calculating other kinematic quantities, like acceleration.

Time is essential because:
  • It allows us to describe how quickly events occur.
  • It is a constant reference that kinematics relies on for precision. Without a proper grasp of time, concepts like velocity and acceleration lose their meaning.
Thus, understanding time in relation to motion is crucial, as it lets us explore how various objects "fit" into the sequence of events in the universe of motion.
Motion Equations
Motion equations are mathematical tools used to describe the relationship between displacement, velocity, acceleration, and time. They allow us to predict the movement of objects by knowing three things: where they started, how fast they're going, and in what timeframe.

For the Ford RS200 Evolution, we utilized the basic formula of acceleration:\[a = \frac{v - u}{t}\]This formula reveals:
  • The calculated acceleration is directly dependent on changes in velocity and the time taken for this change.
  • Knowing any three out of the four quantities (initial velocity, final velocity, time, and acceleration) allows you to solve for the unknown.
Motion equations are essential for:
  • Predicting how fast a vehicle can go given its acceleration abilities.
  • Understanding how forces applied to vehicles will change their velocity over time.
By using motion equations, engineers can design cars that meet desired speed and performance targets.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An 18 -year-old runner can complete a \(10.0-\mathrm{km}\) course with an average speed of 4.39 \(\mathrm{m} / \mathrm{s}\) . A 50 -year-old runner can cover the same distance with an average speed of 4.27 \(\mathrm{m} / \mathrm{s}\) . How much later (in seconds) should the younger runer start in order to finish the course at the same time as the older runner?

A car makes a trip due north for three-fourths of the time and due south one- fourth of the time. The average northward velocity has a magnitude of \(27 \mathrm{m} / \mathrm{s},\) and the average southward velocity has a magnitude of 17 \(\mathrm{m} / \mathrm{s}\) . What is the average velocity (magnitude and direction) for the entire trip?

A police car is traveling at a velocity of 18.0 \(\mathrm{m} / \mathrm{s}\) due north, when a car zooms by at a constant velocity of 42.0 \(\mathrm{m} / \mathrm{s}\) due north. After a reaction time of 0.800 \(\mathrm{s}\) s the policeman begins to pursue the speeder with an acceleration of 5.00 \(\mathrm{m} / \mathrm{s}^{2}\) . Including the reaction time, how long does it take for the police car to catch up with the speeder?

In a quarter-mile drag race, two cars start simultaneously from rest, and each accelerates at a constant rate until it either reaches its maximum speed or crosses the finish line. Car A has an acceleration of 11.0 \(\mathrm{m} / \mathrm{s}^{2}\) and a maximum speed of 106 \(\mathrm{m} / \mathrm{s}\) . Car \(\mathrm{B}\) has an acceleration of 11.6 \(\mathrm{m} / \mathrm{s}^{2}\) and a maximum speed of 92.4 \(\mathrm{m} / \mathrm{s}\) . Which car wins the race, and by how many seconds?

The Kentucky Derby is held at the Churchill Downs track in Louisville, Kentucky. The track is one and one-quarter miles in length. One of the most famous horses to win this event was Secretariat. In 1973 he set a Derby record that would be hard to beat. His average acceleration during the last four quarter-miles of the race was \(+0.0105 \mathrm{m} / \mathrm{s}^{2}\) . His velocity at the start of the final mile \((x=+1609 \mathrm{m})\) was about \(+16.58 \mathrm{m} / \mathrm{s}\) . The acceleration, although small, was very important to his victory. To assess its effect, determine the difference between the time he would have taken to run the final mile at a constant velocity of \(+16.58 \mathrm{m} / \mathrm{s}\) and the time he actually took. Although the track is oval in shape, assume it is straight for the purpose of this problem.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.