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The A string on a string bass vibrates at a fundamental frequency of 55.0 Hz. If the string’s tension were increased by a factor of four, what would be the new fundamental frequency?

Short Answer

Expert verified
The new fundamental frequency is 110.0 Hz.

Step by step solution

01

Understanding the relationship

The fundamental frequency of a vibrating string is related to the tension in the string by the formula \( f = \frac{1}{2L} \sqrt{\frac{T}{\mu}} \), where \( f \) is the frequency, \( L \) is the length of the string, \( T \) is the tension, and \( \mu \) is the linear mass density. If tension doubles, frequency changes by the square root of the factor of increase.
02

Calculating the new tension effect

Since the tension is increased by a factor of four, we calculate the effect on the frequency as follows: The frequency is proportional to the square root of the tension. Thus, \( f' = f \times \sqrt{\text{factor of increase in tension}} = 55.0 \times \sqrt{4} \).
03

Solving for the new frequency

Calculate the new frequency using the equation from the previous step. Plug the values into the equation: \[ f' = 55.0 \times \sqrt{4} = 55.0 \times 2 = 110.0 \, \text{Hz} \]
04

Verification and conclusion

Verify the calculation is consistent with understanding the physical principles: A fourfold increase in tension results in a doubling of frequency, according to the square root relationship, confirming correctness. The final frequency is 110.0 Hz.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fundamental Frequency
The fundamental frequency is the lowest frequency at which a string vibrates. It's determined by the properties of the string and the tension applied. In simpler terms, imagine a guitar string: when you pluck it, the sound you hear is dominated by its fundamental frequency. This frequency depends on three main factors:

  • The length of the string (L)
  • The tension (T) applied to it
  • The linear mass density (μ), which is its mass per unit length

The fundamental frequency is calculated using the formula:\[ f = \frac{1}{2L} \sqrt{\frac{T}{μ}} \]Here, \( f \) is the fundamental frequency."Understanding how these factors influence \( f \) helps in adjusting instruments to produce desired tones and pitches."
String Vibration
String vibration refers to the oscillatory motion of a string when plucked or struck. This vibration produces sound, with the fundamental frequency being the most prominent tone we perceive. The vibration of the string is not just simple back-and-forth motion: - The string vibrates in patterns that can include overtones. - Overtones are multiples of the fundamental frequency, adding richness to the sound. For practical purposes, most instruments are tuned to highlight the fundamental frequency, as it sets the base note. Ensuring the right tension, length, and material of the string is crucial for achieving the correct tonal quality.
Tension and Frequency Relationship
The tension and frequency relationship explains how changes in string tension affect the frequency of its vibration. When the tension on a string is altered, the pitch changes as well:- An increase in tension leads to a higher frequency, resulting in a higher pitch.- Conversely, reducing tension results in a lower frequency and thus a lower pitch.The relationship between frequency and tension is expressed mathematically by the square root component in the fundamental frequency formula:\[ f \propto \sqrt{T} \]This indicates that frequency is proportional to the square root of the tension. In the example problem, increase the tension by a factor of four, meant using \( f' = f \times \sqrt{4} \), which gave a doubling of the fundamental frequency. Consistently adjusting tension is essential for tuning string instruments to the right pitch.
Square Root Relationship
The square root relationship plays a pivotal role in understanding how physical changes in a string's properties affect its vibration frequency. This relationship is evident in the interplay between frequency and tension: - When you square the factor by which tension is increased, you determine the factor by which frequency changes after taking its square root. - It's a non-linear relationship indicating that large changes in tension yield smaller changes in frequency compared to a linear expectation. To visualize, if tension increases by a factor of four, the square root is two. Hence, the frequency doubles, as derived in the exercise example. This principle demonstrates the sensitivity of string instruments to changes in tension, affecting sound resonance and pitch adjustment.

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Most popular questions from this chapter

Suppose that the strings on a violin are stretched with the same tension and each has the same length between its two fixed ends. The musical notes and corresponding fundamental frequencies of two of these strings are G (196.0 Hz) and E (659.3 Hz). The linear density of the E string is \(3.47 \times 10^{-4} kg/m\) What is the linear density of the G string?

A person hums into the top of a well and finds that standing waves are established at frequencies of 42, 70.0, and 98 Hz. The frequency of 42 Hz is not necessarily the fundamental frequency. The speed of sound is 343 m/s. How deep is the well?

Two wires, each of length 1.2 m, are stretched between two fixed supports. On wire A there is a second-harmonic standing wave whose frequency is 660 Hz. However, the same frequency of 660 Hz is the third harmonic on wire B. Find the speed at which the individual waves travel on each wire.

A tube with a cap on one end, but open at the other end, has a fundamental frequency of 130.8 Hz. The speed of sound is 343 m/s (a) If the cap is removed, what is the new fundamental frequency of the tube? (b) How long is the tube?

Two out-of-tune flutes play the same note. One produces a tone that has a frequency of 262 Hz, while the other produces 266 Hz. When a tuning fork is sounded together with the 262-Hz tone, a beat frequency of 1 Hz is produced. When the same tuning fork is sounded together with the 266-Hz tone, a beat frequency of 3 Hz is produced. What is the frequency of the tuning fork?

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