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Two wires, each of length 1.2 m, are stretched between two fixed supports. On wire A there is a second-harmonic standing wave whose frequency is 660 Hz. However, the same frequency of 660 Hz is the third harmonic on wire B. Find the speed at which the individual waves travel on each wire.

Short Answer

Expert verified
Wire A speed: 792 m/s; Wire B speed: 528 m/s.

Step by step solution

01

Understanding Harmonics

Standing waves are formed at specific frequencies known as harmonics. The second harmonic has two loops, and the third harmonic has three loops. These harmonics are related to the wave speed, frequency, and length of the wire.
02

Identifying the Wave Formula

The general formula for the frequency of the n-th harmonic is given by \( f_n = \frac{n \cdot v}{2L} \) for wire harmonics, where \( n \) is the harmonic number, \( v \) is the wave speed, and \( L \) is the length of the wire.
03

Solving for the Wave Speed on Wire A

For wire A at the second harmonic, where \( n = 2 \), the frequency \( f = 660 \, \text{Hz} \), and length \( L = 1.2 \, \text{m} \), solve for the wave speed \( v \):\[v = \frac{2Lf}{n} = \frac{2 \times 1.2 \, \text{m} \times 660 \, \text{Hz}}{2} = 792 \, \text{m/s}.\]
04

Solving for the Wave Speed on Wire B

For wire B at the third harmonic, where \( n = 3 \), the frequency \( f = 660 \, \text{Hz} \), and length \( L = 1.2 \, \text{m} \), solve for the wave speed \( v \):\[v = \frac{2Lf}{n} = \frac{2 \times 1.2 \, \text{m} \times 660 \, \text{Hz}}{3} = 528 \, \text{m/s}.\]
05

Conclusion on Wave Speeds

From the calculations, the wave speed on wire A is 792 m/s and on wire B is 528 m/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Speed
Wave speed is an essential concept in physics, particularly when discussing waves on strings or wires. It indicates how quickly the wave travels along the medium. In the context of the problem with the two wires, knowing the wave speed helps determine how harmonics behave and relate to each other in different setups.
Given the formula for harmonic frequency, we use it to derive the wave speed. For any wire with a fixed length, if you know the harmonic frequency and number, you can easily calculate the speed using the formula:
  • \[v = \frac{2Lf}{n}\]
where:
  • \(v\) is the wave speed
  • \(L\) is the length of the wire
  • \(f\) is the frequency
  • \(n\) is the harmonic number
So, in this exercise, we calculated different wave speeds for wires A and B using the same frequency but different harmonics.
Standing Waves
Standing waves are a fascinating phenomenon involving waves traveling in opposite directions. They appear as waves that are stationary, with certain points called nodes remaining still while others, known as antinodes, vibrate with maximum amplitude.
These waves occur when two identical waves interfere with each other under specific conditions. When a wave reflects back upon reaching a fixed endpoint like a clamped wire, it can interfere with incoming waves to form standing waves.
Standing waves support certain frequencies called harmonics, and understanding these can help us predict how different systems behave based on their dimensions and tension.
Harmonics
Harmonics are the specific frequencies at which standing waves form. Each harmonic corresponds to a particular pattern of nodes and antinodes:
  • The first harmonic (or fundamental frequency) has one half-wavelength fitting within the wire's length.
  • The second harmonic doubles the number of antinodes, producing two loops within the same length.
  • The third harmonic has three loops, and so on.
In this exercise, wire A supports the second harmonic and wire B the third harmonic at the same frequency (660 Hz). Changing the harmonic number changes how energy is distributed along the wire, affecting both the wave speed and amplitude.
Frequency
Frequency is the number of oscillations or cycles a wave completes in one second, measured in Hertz (Hz). It's a critical property that relates closely to wave speed and harmonics. Every harmonic has a specific frequency it resonates at, and in many practical situations, like musical instruments, this determines the pitch we hear.
The frequency formula, as used in this exercise, is:
  • \[f_n = \frac{n \cdot v}{2L}\]
This formula shows that:
  • As the number of harmonics increases, frequency does too, assuming constant wave speed and length.
  • A higher frequency indicates a higher pitch sound if the waves are sound waves on instruments.
Wave Formula
The wave formula is a mathematical expression used to relate wave properties like speed, frequency, and wavelength. When discussing harmonics, the specific formula employed is tailored to standing waves on strings:
  • General formula for harmonic frequency: \[f_n = \frac{n \cdot v}{2L}\]
Understanding this formula is crucial because it lets us explore how changes in length \(L\), wave speed \(v\), or harmonic number \(n\) influence the frequency of the wave.
By rearranging this expression, we can solve for different unknowns, like calculating wave speed when given frequency and harmonic information. Thus, mastering this formula allows one to unravel complex wave systems simply by knowing a few variables.

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Most popular questions from this chapter

The E string on an electric bass guitar has a length of 0.628 m and, when producing the note E, vibrates at a fundamental frequency of 41.2 Hz. Players sometimes add to their instruments a device called a 鈥淒-tuner.鈥 This device allows the E string to be used to produce the note D, which has a fundamental frequency of 36.7 Hz. The D-tuner works by extending the length of the string, keeping all other factors the same. By how much does a D-tuner extend the length of the E string?

Two speakers, one directly behind the other, are each generating a 245-Hz sound wave. What is the smallest separation distance between the speakers that will produce destructive interference at a listener standing in front of them? The speed of sound is 343 m/s.

Two cars have identical horns, each emitting a frequency of \(f_{s}=395 Hz.\) One of the cars is moving with a speed of 12.0 m/s toward a bystander waiting at a corner, and the other car is parked. The speed of sound is 343 m/s. What is the beat frequency heard by the bystander?

Suppose that the strings on a violin are stretched with the same tension and each has the same length between its two fixed ends. The musical notes and corresponding fundamental frequencies of two of these strings are G (196.0 Hz) and E (659.3 Hz). The linear density of the E string is \(3.47 \times 10^{-4} kg/m\) What is the linear density of the G string?

Sound enters the ear, travels through the auditory canal, and reaches the eardrum. The auditory canal is approximately a tube open at only one end. The other end is closed by the eardrum. A typical length for the auditory canal in an adult is about 2.9 cm. The speed of sound is 343 m/s. What is the fundamental frequency of the canal? (Interestingly, the fundamental frequency is in the frequency range where human hearing is most sensitive.)

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