/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Two cars have identical horns, e... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Two cars have identical horns, each emitting a frequency of \(f_{s}=395 Hz.\) One of the cars is moving with a speed of 12.0 m/s toward a bystander waiting at a corner, and the other car is parked. The speed of sound is 343 m/s. What is the beat frequency heard by the bystander?

Short Answer

Expert verified
The beat frequency heard by the bystander is approximately 14.4 Hz.

Step by step solution

01

Identify Given Information

We have two cars with horns emitting the same frequency \(f_s = 395\) Hz. One car is moving toward the bystander with a speed \(v_s = 12.0\) m/s, and the other car is stationary. The speed of sound is \(v = 343\) m/s.
02

Understand the Doppler Effect

The Doppler effect causes the frequency of sound to change due to the relative motion between the source and the observer. For a moving source towards a stationary observer, the perceived frequency \(f'\) is higher than the emitted frequency \(f_s\).
03

Calculate the Frequency Heard from the Moving Car

Use the formula for frequency observed when the source is moving towards the observer:\[f' = \frac{v}{v - v_s} \times f_s\]Plugging in the values:\[f' = \frac{343}{343 - 12} \times 395 = \frac{343}{331} \times 395\]Calculate \(f'\) to find the frequency heard by the bystander from the moving car.
04

Calculate the Beat Frequency

The beat frequency \(f_b\) is the difference between the frequencies of two signals. With one car parked (frequency \(f_s\)) and the other moving (frequency \(f'\)), the beat frequency is:\[f_b = |f' - f_s|\]Calculate \(f_b\) using the calculated \(f'\) from Step 3 and the known \(f_s\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Beat Frequency
When two sounds with slightly different frequencies are heard together, they produce a phenomenon known as beat frequency. Essentially, this creates a pulsing or "wobbling" effect rather than a single pure tone.
Beat frequency is calculated by finding the absolute difference between the two frequencies.
  • If you have frequencies from two sources, say one producing a frequency "A" and the other "B", the beat frequency is simply \(f_{b} = |A - B|\).
  • In our problem, the two frequencies involved are the emitted frequency from the horns of the moving car, and the stationary car. So,\[ f_{b} = |f' - f_{s}| \]
This beat frequency formula allows us to hear fluctuations in sound intensity and is used in various fields, such as tuning musical instruments, where subtle differences in pitch need to be adjusted.
Frequency Calculation
The frequency calculation for an observer changes depending on the movement of the source or the observer, as explained by the Doppler effect.
In our scenario, the frequency perceived by the bystander, who serves as a stationary observer, is altered due to the motion of the source — the moving car.To calculate the new perceived frequency \( f' \) when a source is moving towards an observer, use the formula:
  • \[ f' = \frac{v}{v - v_{s}} \times f_{s} \]
  • Here, \( v \) is the speed of sound, \( v_s \) is the speed of the moving source, and \( f_s \) is the original frequency.
Plugging the given values into this formula gives the new frequency \( f' \), which is higher than \( f_s \) due to the source moving towards the observer.
This calculation is essential to understand how motion affects perceived sound, especially in contexts such as vehicle horns or sirens.
Speed of Sound
The speed of sound is a critical component in the study of wave phenomena, specifically when analyzing how sound travels through different mediums. In this problem, we assume a constant speed of sound in air, given as 343 m/s. This speed can vary based on factors like temperature, pressure, and humidity.
  • Understanding the speed of sound helps us calculate how quickly sound waves reach us.
  • In Doppler-related problems, changes in frequency due to relative motion rely on this speed.
  • For many standard calculations, particularly in educational settings, a value near 343 m/s is used.
Knowing the speed of sound is fundamental for accurately determining observed frequencies and calibrating instruments for precision in sound perception.
Moving Source and Stationary Observer
In the context of the Doppler Effect, the roles of the moving source and stationary observer are fundamental for understanding how sound frequency appears to change. When a sound source moves towards a stationary observer, the waves compress, causing the observer to hear a higher frequency. This scenario is commonly analyzed using the given Doppler formula.
  • The source emits sound uniformly, but motion alters the path the sound waves take, increasing the frequency as it approaches.
  • The further the source continues towards the observer, the higher the frequency heard.
This principle is not only relevant for sounds like vehicle horns but also in astrophysics for understanding light from stars shifting towards the blue part of the spectrum when they move closer. By recognizing this source and observer relationship, we can understand many real-world phenomena, from the everyday to the cosmic level.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A tube with a cap on one end, but open at the other end, has a fundamental frequency of 130.8 Hz. The speed of sound is 343 m/s (a) If the cap is removed, what is the new fundamental frequency of the tube? (b) How long is the tube?

Multiple-Concept Example 3 reviews the concepts that are important in this problem. The entrance to a large lecture room consists of two side-by-side doors, one hinged on the left and the other hinged on the right. Each door is 0.700 m wide. Sound of frequency 607 Hz is coming through the entrance from within the room. The speed of sound is 343 m/s. What is the diffraction angle of the sound after it passes through the doorway when (a) one door is open and (b) both doors are open?

The approach to solving this problem is similar to that taken in Multiple- Concept Example 4. On a cello, the string with the largest linear density \(\left(1.56 \times 10^{-2} kg / m\right)\) is the C string. This string produces a fundamental frequency of 65.4 \(\mathrm{Hz}\) and has a length of 0.800 \(m\) between the two fixed ends. Find the tension in the string.

Sound enters the ear, travels through the auditory canal, and reaches the eardrum. The auditory canal is approximately a tube open at only one end. The other end is closed by the eardrum. A typical length for the auditory canal in an adult is about 2.9 cm. The speed of sound is 343 m/s. What is the fundamental frequency of the canal? (Interestingly, the fundamental frequency is in the frequency range where human hearing is most sensitive.)

A 440.0-Hz tuning fork is sounded together with an out-of-tune guitar string, and a beat frequency of 3 Hz is heard. When the string is tightened, the frequency at which it vibrates increases, and the beat frequency is heard to decrease. What was the original frequency of the guitar string?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.