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Multiple-Concept Example 4 deals with the same concepts as this problem. A 41-cm length of wire has a mass of 6.0 g. It is stretched between two fixed supports and is under a tension of 160 N. What is the fundamental frequency of this wire?

Short Answer

Expert verified
The fundamental frequency of the wire is approximately 127.51 Hz.

Step by step solution

01

Identify the known values

We are given the following known values:- Length of the wire, \( L = 41 \) cm = 0.41 m,- Mass of the wire, \( m = 6.0 \) g = 0.006 kg,- Tension in the wire, \( T = 160 \) N.
02

Calculate the linear mass density (\( \mu \))

The linear mass density \( \mu \) is given by the formula \( \mu = \frac{m}{L} \). Substitute the known values:\[ \mu = \frac{0.006 \text{ kg}}{0.41 \text{ m}} = 0.01463 \text{ kg/m}. \]
03

Use the formula for the fundamental frequency

The fundamental frequency \( f_1 \) of a stretched string is given by:\[ f_1 = \frac{1}{2L} \sqrt{\frac{T}{\mu}}. \]Substitute the known values into the equation.
04

Substitute and compute the fundamental frequency

Substitute \( L = 0.41 \) m, \( T = 160 \) N, and \( \mu = 0.01463 \) kg/m into the formula:\[ f_1 = \frac{1}{2 \times 0.41} \sqrt{\frac{160}{0.01463}} \]\[ \approx \frac{1}{0.82} \times 104.66 \approx 127.51 \text{ Hz} \].Thus, the fundamental frequency is approximately 127.51 Hz.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Mass Density
Linear mass density is a crucial concept when it comes to understanding vibrating strings. It is defined as the mass per unit length of a string or wire. This property is denoted by the symbol \( \mu \) and its unit is the kilogram per meter \( \text{kg/m} \). Understanding linear mass density helps us to predict how a wire or string will behave when put under tension.

For instance, if you have a wire with a mass of 6.0 grams and a length of 41 cm, the linear mass density can be computed using the formula \( \mu = \frac{m}{L} \). By performing this calculation, the density is \( 0.01463 \text{ kg/m} \).

Keep in mind this property directly impacts the speed at which vibrations travel through the string, and thus, affects the frequency of any standing waves generated.
Tension in a String
The tension in a string is the force that is applied along the string's length. It pulls or stretches the string tight, impacting how the string vibrates and the sound it produces when it vibrates. Tension is measured in newtons (N).

When calculating the fundamental frequency of a string, tension plays a key role. In our example, the wire is under a tension of 160 N. This value is used in the fundamental frequency formula \( f_1 = \frac{1}{2L} \sqrt{\frac{T}{\mu}} \).

Increased tension typically results in a higher pitch because the vibrations travel faster along the string. Thus, understanding tension is essential for anyone working with musical instruments or mechanical systems involving strings.
Standing Waves
Standing waves are a fascinating phenomenon that occur when a wave is confined within a fixed medium, such as a string. In physics, these waves do not appear to be traveling but instead oscillate up and down in the same space.

Standing waves are highly important in understanding the behavior of vibrating strings. When a string is fixed at both ends and vibrated, certain frequencies will produce standing waves. These frequencies are known as the natural frequencies of the string.

In the context of the wire example, calculating the fundamental frequency helps us determine the lowest frequency at which a standing wave will form. This frequency is crucial for musical applications, ensuring the correct pitch is produced by an instrument.
Vibrating Strings
Vibrating strings are at the core of many musical instruments and physical systems. When a string vibrates, it produces sound waves that we can hear. Several factors influence how the string vibrates, including its length, mass density, and the tension applied to it.

When a string is plucked, struck, or bowed, it vibrates in various modes. The fundamental frequency is the lowest frequency at which the string vibrates naturally. It directly relates to the pitch of the sound produced.

Understanding vibrating strings also involves grasping how changes in tension or length affect sound production. For example:
  • Increasing the tension in the string usually increases the frequency, resulting in a higher pitch.
  • Increasing the length of the string lowers the frequency, producing a lower pitch.
  • The linear mass density also affects the vibration speed, contributing to the sound's characteristics.
Each of these elements must be considered when designing or tuning instruments to ensure they produce the desired sounds.

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Most popular questions from this chapter

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