/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 The components of vector \(\over... [FREE SOLUTION] | 91Ó°ÊÓ

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The components of vector \(\overrightarrow{\mathbf{A}}\) are \(A_{x}\) and \(A_{y}\) (both positive), and the angle that it makes with respect to the positive \(x\) axis is \(\theta\) . Find the angle \(\theta\) if the components of the displacement vector \(\overrightarrow{\mathbf{A}}\) are (a) \(A_{x}=12 \mathrm{m}\) and \(A_{y}=12 \mathrm{m}, \quad(\mathrm{b}) A_{x}=17 \mathrm{m}\) and \(A_{y}=12 \mathrm{m},\) and (c) \(A_{x}=12 \mathrm{m}\) and \(A_{y}=17 \mathrm{m} .\)

Short Answer

Expert verified
(a) 45°; (b) 35.26°; (c) 54.74°.

Step by step solution

01

Understand the Relationship

The angle \( \theta \) between the vector \( \overrightarrow{\mathbf{A}} \) and the positive \( x \)-axis is given by the arctangent function: \( \theta = \tan^{-1} \left( \frac{A_y}{A_x} \right) \). This formula represents the angle formed by the vector and its components along the \( x \)- and \( y \)-axes.
02

Compute Angle for Part (a)

For \( A_x = 12 \mathrm{m} \) and \( A_y = 12 \mathrm{m} \), substitute these values into the formula. So, \( \theta = \tan^{-1} \left( \frac{12}{12} \right) = \tan^{-1}(1) \). The angle for which tangent equals 1 is \( 45^{\circ} \).
03

Compute Angle for Part (b)

For \( A_x = 17 \mathrm{m} \) and \( A_y = 12 \mathrm{m} \), substitute into the formula. \( \theta = \tan^{-1} \left( \frac{12}{17} \right) \). Use a calculator to find \( \theta \). This computes to approximately \( 35.26^{\circ} \).
04

Compute Angle for Part (c)

For \( A_x = 12 \mathrm{m} \) and \( A_y = 17 \mathrm{m} \), substitute into the formula. \( \theta = \tan^{-1} \left( \frac{17}{12} \right) \). Use a calculator to find \( \theta \). This computes to approximately \( 54.74^{\circ} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometry
Trigonometry is a branch of mathematics that studies the relationships between the angles and sides of triangles. It is especially useful in vector mathematics, where we deal with angles formed by vectors and their components. Vectors are often represented in terms of their components along the x and y axes. To find the direction or angle of a vector, trigonometry offers us various functions, such as sine, cosine, and tangent. Each function relates an angle with a ratio of different sides of a right triangle. In many vector problems, the tangent function is particularly useful because it relates the angle to the opposite and adjacent sides. When calculating angles in vector problems, ensure your calculator is in the correct mode (degrees or radians) based on what the problem requires. Trigonometry helps translate real-world phenomena into mathematical language, allowing us to solve problems with precision.
Vector Components
Vector components play a critical role in understanding vector direction and magnitude. A vector is a mathematical entity possessing both magnitude and direction, much like a force or velocity. - The horizontal component (often along the x-axis) is denoted as \( A_x \).- The vertical component (along the y-axis) is denoted as \( A_y \).By breaking a vector down into its components, we simplify complex two-dimensional motion into basic one-dimensional analyses. Vector components are typically resolved using simple geometry or trigonometric functions, where the vector can be expressed as \( \overrightarrow{\mathbf{A}} = A_x \hat{\mathbf{i}} + A_y \hat{\mathbf{j}} \), where \( \hat{\mathbf{i}} \) and \( \hat{\mathbf{j}} \) are unit vectors along the x and y axes, respectively.Understanding the components helps in calculating resultant vectors when multiple vectors act in a system, providing clarity and ease when navigating through linear algebra and physics problems.
Arctangent Function
The arctangent function, often denoted as \( \tan^{-1} \) or \( \mathrm{atan} \), is an inverse trigonometric function used to calculate the angle whose tangent value is known. In the context of vector mathematics, it is essential for finding the angle a vector makes concerning the positive x-axis.The arctangent function is crucial when both components of the vector are known, and the question is to determine the angle \( \theta \). The formula \( \theta = \tan^{-1} \left( \frac{A_y}{A_x} \right) \) allows us to derive this angle:- \( A_y \) represents the vertical component.- \( A_x \) represents the horizontal component.This function returns the angle in radians. For convenience, you may need to convert it into degrees. The arctangent function helps avoid ambiguity in angle measurement by consistently providing angles between \(-90^{\circ}\) and \(90^{\circ}\), making it reliable for calculations involving vector directions.

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