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Vector \(\overrightarrow{\mathbf{A}}\) has a magnitude of 6.00 units and points due east. Vector \(\overrightarrow{\mathbf{B}}\) points due north. (a) What is the magnitude of \(\overrightarrow{\mathbf{B}},\) if the vector \(\overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}}\) points \(60.0^{\circ}\) north of east? (b) Find the magnitude of \(\overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}}\) .

Short Answer

Expert verified
(a) The magnitude of \( \overrightarrow{\mathbf{B}} \) is 10.39 units. (b) The magnitude of \( \overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}} \) is 12.01 units.

Step by step solution

01

Resolve Vector Directions

Vector \( \overrightarrow{\mathbf{A}} \) is given as having a magnitude of 6.00 units and points due east. This means that it can be expressed in component form as \( (6.00, 0) \). Vector \( \overrightarrow{\mathbf{B}} \) points due north, so it only has a vertical component and can be expressed as \( (0, B) \), where \( B \) is its magnitude.
02

Determine Resultant Vector Direction

The resultant vector \( \overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}} \) points \(60.0^{\circ}\) north of east. This angle refers to the angle between the resultant vector and the east direction (x-axis). The tangent of this angle gives the ratio of the y-component to the x-component of the resultant vector. So \[ \tan(60.0^{\circ}) = \frac{B}{6.00} \].
03

Solve for Magnitude of B

Knowing \( \tan(60.0^{\circ}) = \sqrt{3} \), we substitute this into the equation: \[ \sqrt{3} = \frac{B}{6.00} \]. Solving for \( B \), we get \( B = 6.00 \times \sqrt{3} \approx 10.39 \). So, the magnitude of \( \overrightarrow{\mathbf{B}} \) is approximately 10.39 units.
04

Calculate Magnitude of Resultant Vector

The resultant vector \( \overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}} \) has components \( (6.00, 10.39) \). To find its magnitude, we use the Pythagorean theorem: \[ |\overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}}| = \sqrt{(6.00)^2 + (10.39)^2} \]. Calculating this gives \[ = \sqrt{36.00 + 108.1} = \sqrt{144.1} \approx 12.01 \]. Thus, the magnitude of \( \overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}} \) is approximately 12.01 units.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Resultant Vector
When we talk about a resultant vector, we are referring to the vector that results from adding two or more vectors together. Imagine you are walking in one direction and then in another; the resultant vector is like your final position from where you started.
In the given exercise, we have vectors \( \overrightarrow{\mathbf{A}} \) and \( \overrightarrow{\mathbf{B}} \) with defined directions.
The resultant vector \( \overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}} \) is what you'd get if you combine these two vectors. Its direction is given as \(60.0^\circ\) north of east.
To determine the resultant vector's direction, we consider both vectors' combined effect:
  • \( \overrightarrow{\mathbf{A}} \) pushes east with a magnitude of 6.00 units.
  • \( \overrightarrow{\mathbf{B}} \) pushes north, with its magnitude being solved for.
The angle \(60.0^\circ\) helps us figure out how much of the total push is going north versus east.
Magnitude Calculation
Magnitude calculation is crucial when determining the size or length of a vector. Think of it like measuring the distance from one point to another.
In the problem, you find the magnitude of \( \overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}} \) using the Pythagorean theorem because it forms a right triangle with the components of the vectors.
Here's a quick recap of the process:
  • First, resolve the vector components: \( \overrightarrow{\mathbf{A}} = (6.00, 0) \) and \( \overrightarrow{\mathbf{B}} = (0, B) \).
  • Apply the theorem: \[ |\overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}} |= \sqrt{(6.00)^2 + (10.39)^2} \],
  • Simplify to get \( |\overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}}| \approx 12.01 \) units.
This step ensures you know exactly how long the resulting path (vector) is when combining your movements east and north.
Component Form
Understanding vector component form is essential for breaking down and analyzing vectors effectively. It’s like seeing a puzzle piece as part of a bigger picture.
Vectors are often represented by their components to simplify calculations, especially in two-dimensional space. For vector \( \overrightarrow{\mathbf{A}} \), its component form is \( (6.00, 0) \) as it only moves east. Vector \( \overrightarrow{\mathbf{B}} \), which moves north, is expressed as \( (0, B) \).
The beauty of using component form is:
  • It allows you to easily add vectors together by simply adding corresponding components.
  • You can better visualize vector operations, especially when considering angle and direction.
These insights make solving vector problems straightforward by separating and combining movements on the x (east-west) and y (north-south) axes.

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Most popular questions from this chapter

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