/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 A Ferris wheel rotates at an ang... [FREE SOLUTION] | 91Ó°ÊÓ

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A Ferris wheel rotates at an angular velocity of \(0.24 \mathrm{rad} / \mathrm{s}\). Starting from rest, it reaches its operating speed with an average angular acceleration of \(0.030 \mathrm{rad} / \mathrm{s}^{2}\). How long does it take the wheel to come up to operating speed?

Short Answer

Expert verified
It takes 8 seconds for the Ferris wheel to reach its operating speed.

Step by step solution

01

Identify Given Values

We are given the angular velocity \( \omega = 0.24 \, \text{rad/s} \) and the average angular acceleration \( \alpha = 0.030 \, \text{rad/s}^2 \). The Ferris wheel starts from rest, so its initial angular velocity \( \omega_0 = 0 \, \text{rad/s} \). Our task is to find the time \( t \) it takes to reach \( \omega = 0.24 \, \text{rad/s} \).
02

Use Angular Motion Equation

We can use the equation for angular motion \( \omega = \omega_0 + \alpha t \), where \( \omega \) is the final angular velocity, \( \omega_0 \) is the initial angular velocity, \( \alpha \) is the angular acceleration, and \( t \) is the time.
03

Substitute Known Values

Substitute the given values into the angular motion equation: \( 0.24 = 0 + (0.030)t \), which simplifies to \( 0.24 = 0.030t \).
04

Solve for Time \( t \)

Rearrange the equation \( 0.24 = 0.030t \) to solve for \( t \): Divide both sides by \( 0.030 \), resulting in \( t = \frac{0.24}{0.030} \).
05

Calculate the Result

Perform the division: \( t = \frac{0.24}{0.030} = 8 \). Therefore, it takes 8 seconds for the Ferris wheel to reach its operating speed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity is a fundamental concept in the study of rotational motion. It measures how quickly an object rotates or spins around a fixed point or axis. In simpler terms, it's the rate at which an object changes its angle from a central point, usually expressed in radians per second (rad/s). Just as speed measures how fast an object travels from one place to another, angular velocity measures how swiftly an angle changes in a rotational path.
In any circular motion, knowing the angular velocity is key to understanding the dynamics of the system. For instance, in a Ferris wheel scenario, the given angular velocity is the rate the wheel spins at its full speed, which is 0.24 rad/s in our exercise. It's important as it helps predict the motion pattern of the wheel as well as synchronize systems dependent on this motion, like the boarding and exodus of passengers.
To sum up, think of angular velocity as the speedometer of rotation – it's a valuable tool for quantifying how fast something is spinning at any given time.
Angular Acceleration
Angular acceleration is another essential part of understanding rotational motion. It describes how quickly the angular velocity of an object changes with time. When you think about acceleration in a linear motion, you consider the increase or decrease of speed – angular acceleration does the parallel job for spinning and turning motions.
In our exercise of a Ferris wheel, it started from rest and gradually reached its operating angular velocity with an angular acceleration given as 0.030 rad/s². This rate of change in angular speed helps us calculate how long it will take for any rotating object, like our Ferris wheel, to gain speed and reach its steady spinning rate. This concept is especially vital in engineering and physics as it aids in designing machines and systems needing precise rotational speed control.
For a real-world example, consider a bicycle tire spinning faster and faster when you pedal – this increase in spinning speed results from angular acceleration. Similar to how a car's acceleration tells us how its speed increases or decreases, angular acceleration gives insights into rotational speed changes.
Physics Problem Solving
Physics problems, like our Ferris wheel example, often require methodical problem-solving techniques to find solutions. It begins with identifying what is known and the question at hand. Here, we knew the final angular velocity and the angular acceleration, and we were tasked to find the time it takes for the wheel to reach full speed from rest.
A systematic approach often involves:
  • Listing known values and unknowns to solve for.
  • Choosing the right equations that relate these variables. For angular motion, the equation \( \omega = \omega_0 + \alpha t \) was selected.
  • Substituting the known values into the equation ensures we keep the relationships between the quantities correct.
  • Solving the equation carefully to find the unknown variable, in our case, the time \( t \).
  • Finally, performing any calculations needed, ensuring accuracy throughout the process.
Solving physics problems is much like piecing together a puzzle – with each step building upon the last, ultimately leading to the solution. It's not just about getting the answer but understanding the journey and process, which helps deepen one's grasp of physics concepts.

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Most popular questions from this chapter

A CD has a playing time of 74 minutes. When the music starts, the \(\mathrm{CD}\) is rotating at an angular speed of 480 revolutions per minute (rpm). At the end of the music, the \(\mathrm{CD}\) is rotating at \(210 \mathrm{rpm}\). Find the magnitude of the average angular acceleration of the \(\mathrm{CD}\). Express your answer in \(\mathrm{rad} / \mathrm{s}^{2}\)

A flywheel has a constant angular deceleration of \(2.0 \mathrm{rad} / \mathrm{s}^{2}\). (a) Find the angle through which the flywheel turns as it comes to rest from an angular speed of \(220 \mathrm{rad} / \mathrm{s}\). (b) Find the time required for the flywheel to come to rest.

A spinning wheel on a fireworks display is initially rotating in a counterclockwise direction. The wheel has an angular acceleration of \(-4.00 \mathrm{rad} / \mathrm{s}^{2}\). Because of this acceleration, the angular velocity of the wheel changes from its initial value to a final value of \(-25.0 \mathrm{rad} / \mathrm{s}\). While this change occurs, the angular displacement of the wheel is zero. (Note the similarity to that of a ball being thrown vertically upward, coming to a momentary halt, and then falling downward to its initial position.) Find the time required for the change in the angular velocity to occur.

The earth orbits the sun once a year \(\left(3.16 \times 10^{7} \mathrm{~s}\right)\) in a nearly circular orbit of radius \(1.50 \times 10^{11} \mathrm{~m} .\) With respect to the sun, determine (a) the angular speed of the earth, (b) the tangential speed of the earth, and (c) the magnitude and direction of the earth's centripetal acceleration.

Interactive Solution \(\underline{8.61}\) at offers one approach to solving this problem. The drawing shows the blade of a chain saw. The rotating sprocket tip at the end of the guide bar has a radius of \(4.0 \times 10^{-2} \mathrm{~m}\). The linear speed of a chain link at point \(\mathrm{A}\) is \(5.6 \mathrm{~m} / \mathrm{s}\). Find the angular speed of the sprocket tip in rev/s.

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