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An electric circular saw is designed to reach its final angular speed, starting from rest, in \(1.50 \mathrm{~s}\). Its average angular acceleration is \(328 \mathrm{rad} / \mathrm{s}^{2}\). Obtain its final angular speed.

Short Answer

Expert verified
The final angular speed is 492 rad/s.

Step by step solution

01

Identify the Given Values

We are provided with two key pieces of information:1. The time it takes for the saw to reach its final speed, which is given as \( t = 1.50 \) seconds.2. The average angular acceleration of the saw, \( \alpha = 328 \mathrm{~rad/s}^2 \).
02

Recall the Formula for Angular Speed

The formula to calculate the final angular speed (\( \omega_f \)) when starting from rest is:\[ \omega_f = \omega_i + \alpha t \]Since the saw starts from rest, the initial angular speed \( \omega_i = 0 \).
03

Substitute the Known Values

Plug the known values into the formula:\[ \omega_f = 0 + (328 \, \mathrm{rad/s}^2 \, \times \, 1.50 \, \mathrm{s}) \]
04

Calculate the Final Angular Speed

Perform the multiplication:\[ \omega_f = 328 \, \mathrm{rad/s}^2 \, \times \, 1.50 \, \mathrm{s} = 492 \, \mathrm{rad/s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Acceleration
Angular acceleration is the rate of change of angular velocity over time. Imagine a circular saw ramping up its speed from a complete stop. This gradual increase is achieved through angular acceleration, represented by the symbol \( \alpha \). It is measured in radians per second squared (\( \mathrm{rad/s^2} \)).
In the context of our exercise, the electric saw's angular acceleration is given as \( 328 \, \mathrm{rad/s^2} \). This means that every second, the saw's angular velocity increases by \( 328 \, \mathrm{rad/s} \), contributing directly to the final speed it will eventually reach.
Understanding angular acceleration helps us predict how quickly an object will reach its desired speed. It's an essential concept in any scenario involving rotational motion, not just in machines but also in natural phenomenons like the rotation of planets. This principle allows engineers and scientists to design systems that require precise control of rotation.
Final Angular Speed
Final angular speed is the speed at which an object rotates after completing its acceleration. This is a crucial aspect when analyzing rotational motion, as it determines the object’s rotational velocity at any given terminal point in time. Final angular speed is denoted by \( \omega_f \) and is expressed in radians per second (\( \mathrm{rad/s} \)).
Given our exercise, we saw the electric circular saw reaching its final angular speed in \( 1.50 \, \mathrm{s} \), starting from rest. Using the formula \( \omega_f = \omega_i + \alpha t \) and substituting \( \omega_i = 0 \) (since the saw starts from rest) alongside the given values \( \alpha = 328 \, \mathrm{rad/s^2} \) and \( t = 1.50 \, \mathrm{s} \), we calculated the final angular speed as:
  • \( \omega_f = 328 \, \mathrm{rad/s^2} \times 1.50 \, \mathrm{s} = 492 \, \mathrm{rad/s} \)
Understanding how to calculate and interpret this value helps in determining the efficiency and capability of rotational systems.
Angular Motion
Angular motion refers to the rotation of an object around a central point or axis. This concept is broad, covering various elements such as angular displacement, angular velocity, and angular acceleration.
In our exercise, angular motion was observed in the form of the electric circular saw spinning up from rest. To evaluate such motion, we consider initial conditions, times, acceleration rates, and final velocities.
Angular motion can be described by several parameters:
  • **Angular Displacement:** Denotes the angle through which an object has rotated during a certain period.
  • **Angular Velocity:** Represents how quickly an object rotates, described in terms of \( \mathrm{rad/s} \).
  • **Angular Acceleration:** Specifies the rate at which the angular velocity changes, noted in \( \mathrm{rad/s^2} \).
By considering these components, angular motion enables us to describe the dynamics of rotating systems accurately. It's a core principle in mechanics that applies from simple devices like saws to complex systems such as orbital satellites.

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Most popular questions from this chapter

In general, does the average angular acceleration of a rotating object have the same direction as its initial angular velocity \(\omega_{0}\), its final angular velocity \(\omega\), or the difference \(\omega-\omega_{0}\) between its final and initial angular velocities? (b) The table that follows lists four pairs of initial and final angular velocities for a rotating fan blade. Determine the direction (positive or negative) of the average angular acceleration for each pair. Provide reasons for your answers. $$ \begin{array}{|c|c|c|} \hline & \text { Initial angular velocity } \omega_{0} & \text { Final angular velocity } \omega \\ \hline \text { (a) } & +2.0 \mathrm{rad} / \mathrm{s} & +5.0 \mathrm{rad} / \mathrm{s} \\ \hline \text { (b) } & +5.0 \mathrm{rad} / \mathrm{s} & +2.0 \mathrm{rad} / \mathrm{s} \\ \hline \text { (c) } & -7.0 \mathrm{rad} / \mathrm{s} & -3.0 \mathrm{rad} / \mathrm{s} \\ \hline \text { (d) } & +4.0 \mathrm{rad} / \mathrm{s} & -4.0 \mathrm{rad} / \mathrm{s} \\ \hline \end{array} $$ Problem The elapsed time for each of the four pairs of angular velocities is \(4.0 \mathrm{~s}\). Find the average angular acceleration (magnitude and direction) for each of the four pairs. Be sure that your directions agree with those found in the Concept Question. Concept Question In the table are listed the initial angular velocity \(\omega_{0}\) and the angular acceleration \(\alpha\) of four rotating objects at a given instant in time.

A baton twirler throws a spinning baton directly upward. As it goes up and returns to the twirler's hand, the baton turns through four revolutions. Ignoring air resistance and assuming that the average angular speed of the baton is 1.80 rev/s, determine the height to which the center of the baton travels above the point of release.

A baseball pitcher throws a baseball horizontally at a linear speed of \(42.5 \mathrm{~m} / \mathrm{s}\) (about 95 \(\mathrm{mi} / \mathrm{h}\) ). Before being caught, the baseball travels a horizontal distance of \(16.5 \mathrm{~m}\) and rotates through an angle of 49.0 rad. The baseball has a radius of \(3.67 \mathrm{~cm}\) and is rotating about an axis as it travels, much like the earth does. What is the tangential speed of a point on the "equator" of the baseball?

The earth spins on its axis once a day and orbits the sun once a year \(\left(365^{1 / 4}\right.\) days). Determine the average angular velocity (in rad/s) of the earth as it (a) spins on its axis and (b) orbits the sun. In each case, take the positive direction for the angular displacement to be the direction of the earth's motion.

Our sun rotates in a circular orbit about the center of the Milky Way galaxy. The radius of the orbit is \(2.2 \times 10^{20} \mathrm{~m},\) and the angular speed of the sun is \(1.2 \times 10^{-15} \mathrm{rad} / \mathrm{s}\). (a) What is the tangential speed of the sun? (b) How long (in years) does it take for the sun to make one revolution around the center?

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