/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 At reviews the approach that is ... [FREE SOLUTION] | 91Ó°ÊÓ

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At reviews the approach that is necessary for solving problems such as this one. A motorcyclist is traveling along a road and accelerates for \(4.50 \mathrm{~s}\) to pass another cyclist. The angular acceleration of each wheel is \(+6.70 \mathrm{rad} / \mathrm{s}^{2}\) and, just after passing, the angular velocity of each is \(+74.5 \mathrm{rad} / \mathrm{s}\), where the plus signs indicate counterclockwise directions. What is the angular displacement of each wheel during this time?

Short Answer

Expert verified
Each wheel's angular displacement is \(267.41\, \text{rad}\).

Step by step solution

01

Identify Key Information

We are given:1. The time of acceleration, \(t = 4.50\, \text{s}\).2. The angular acceleration, \(\alpha = +6.70\, \text{rad/s}^2\).3. The final angular velocity, \(\omega_f = +74.5\, \text{rad/s}\). Our goal is to determine the angular displacement, \(\theta\).
02

Use the Final Angular Velocity Formula

We can use the following kinematic equation for angular motion to find the initial angular velocity \(\omega_i\):\[\omega_f = \omega_i + \alpha \cdot t\]Substituting the known values:\[74.5 = \omega_i + 6.70 \times 4.50\]Solve for \(\omega_i\):
03

Solve for Initial Angular Velocity

Rearranging the equation:\[\omega_i = 74.5 - 6.70 \times 4.50\]Calculate \(\omega_i\):\[\omega_i = 74.5 - 30.15 = 44.35\, \text{rad/s}\]
04

Use the Angular Displacement Formula

With \(\omega_i\) known, use the formula for angular displacement:\[\theta = \omega_i \cdot t + \frac{1}{2} \cdot \alpha \cdot t^2\]Substitute the values:\[\theta = 44.35 \times 4.50 + \frac{1}{2} \times 6.70 \times (4.50)^2\]
05

Calculate Angular Displacement

Calculate each term:1. \(44.35 \times 4.50 = 199.575\)2. \(\frac{1}{2} \times 6.70 \times 20.25 = 67.8375\)Add them together:\[\theta = 199.575 + 67.8375 = 267.4125\, \text{rad}\]
06

Conclusion: Final Answer

The angular displacement of each wheel during the acceleration period is \(267.4125\, \text{rad}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Acceleration
Angular acceleration is a key concept in rotational motion. It measures how quickly the angular velocity of an object changes over time. Just as linear acceleration refers to the change in linear velocity, angular acceleration refers to the change in angular velocity. It is denoted by the symbol \( \alpha \).
  • In this problem, the angular acceleration is given as \(+6.70\,\text{rad/s}^2\).
  • This positive value indicates that the angular velocity is increasing in the counterclockwise direction.
Angular acceleration can affect how fast an object spins, making it crucial for understanding rotational dynamics. When calculating problems involving angular motion, knowing the angular acceleration is vital since it directly affects both angular velocity and angular displacement.
Kinematic Equations
Kinematic equations are used to describe the motion of objects, whether they are moving in a straight line or rotating. For rotational motion, these equations allow us to calculate angular displacement, velocity, and acceleration.The key kinematic equation used in this exercise is:\[ \theta = \omega_i \cdot t + \frac{1}{2} \cdot \alpha \cdot t^2 \]
  • \( \theta \) is the angular displacement.
  • \( \omega_i \) is the initial angular velocity.
  • \( t \) is the time of acceleration.
  • \( \alpha \) is the angular acceleration.
Each of these terms plays a role in calculating how far an object rotates over a period of time. Once all the values are known, plugging them into the equation helps us find the angular displacement, as was done in the problem.
Initial Angular Velocity
The initial angular velocity \(\omega_i\) is the starting rotational speed of an object before it experiences any acceleration. It is the counterpart in rotational motion to initial linear velocity.In this scenario, the initial angular velocity is necessary to solve the equation for angular displacement.
  • The initial angular velocity was unknown at first but calculated using the equation \( \omega_f = \omega_i + \alpha \cdot t \)
By rearranging this equation, we can determine:\[ \omega_i = \omega_f - \alpha \cdot t \]Given:
  • \( \omega_f = 74.5 \, \text{rad/s} \)
  • \( \alpha = 6.70 \, \text{rad/s}^2 \)
  • \( t = 4.50 \, \text{s} \)
Substituting in the values provides \( \omega_i = 44.35 \, \text{rad/s} \). Knowing this value is key to later finding the total angular displacement.
Final Angular Velocity
Final angular velocity \( \omega_f \) is the rotational speed of an object at the end of the acceleration period. It is calculated after the angular acceleration has occurred for a specified time.In the exercise:
  • \( \omega_f = +74.5 \, \text{rad/s} \)
This indicates the speed each wheel reached after the 4.50 seconds of acceleration.
The final angular velocity is pivotal for calculating the initial angular velocity and for determining the effect of acceleration over time. This value shows how much the wheel's rotation increased, reflecting the change brought about by the angular acceleration. These calculations illustrate how understanding both the initial and final angular velocities are essential for analyzing motions in rotational dynamics.

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Most popular questions from this chapter

The sun has a mass of \(1.99 \times 10^{30} \mathrm{~kg}\) and is moving in a circular orbit about the center of our galaxy, the Milky Way. The radius of the orbit is \(2.3 \times 10^{4}\) light-years (1 lightyear \(=9.5 \times 10^{15} \mathrm{~m}\) ), and the angular speed of the sun is \(1.1 \times 10^{-15} \mathrm{rad} / \mathrm{s}\). (a) Determine the tangential speed of the sun. (b) What is the magnitude of the net force that acts on the sun to keep it moving around the center of the Milky Way?

The earth spins on its axis once a day and orbits the sun once a year \(\left(365^{1 / 4}\right.\) days). Determine the average angular velocity (in rad/s) of the earth as it (a) spins on its axis and (b) orbits the sun. In each case, take the positive direction for the angular displacement to be the direction of the earth's motion.

An electric circular saw is designed to reach its final angular speed, starting from rest, in \(1.50 \mathrm{~s}\). Its average angular acceleration is \(328 \mathrm{rad} / \mathrm{s}^{2}\). Obtain its final angular speed.

A flywheel has a constant angular deceleration of \(2.0 \mathrm{rad} / \mathrm{s}^{2}\). (a) Find the angle through which the flywheel turns as it comes to rest from an angular speed of \(220 \mathrm{rad} / \mathrm{s}\). (b) Find the time required for the flywheel to come to rest.

The earth has a radius of \(6.38 \times 10^{6} \mathrm{~m}\) and turns on its axis once every \(23.9 \mathrm{~h}\). (a) What is the tangential speed (in \(\mathrm{m} / \mathrm{s}\) ) of a person living in Ecuador, a country that lies on the equator? (b) At what latitude (i.e., the angle \(\theta\) in the drawing) is the tangential speed onethird that of a person living in Ecuador?

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